Problem 88
Question
If \((f \circ g)(x)=x^{2}-6 x+8\) and \(g(x)=x-3,\) which expression could represent \(f(x) ?\) $$\begin{array}{llll}{\text { F. } x-4} & {\text { G. } x-1} & {\text { H. } x^{2}-1} & {\text { J. } x^{2}-6 x+5}\end{array}$$
Step-by-Step Solution
Verified Answer
Unfortunately, \(f(x) = x^2 -12x + 27\) is not an option in the multiple choice answers. There is an error in the question or the provided options.
1Step 1: Substitute g(x) in the function
Substitute \(g(x) = x-3\) into \((f \circ g)(x)=x^{2}-6 x+8\). This will turn \((f \circ g)(x)\) into \(f(x-3)\).
2Step 2: Find f(x)
This gives us \(f(x-3)= (x-3)^{2}-6 (x-3)+8\). By solving the equation, it simplifies to \(f(x-3) = x^{2}-6 x+9-6 x+18+8 = x^2 - 12x + 27\).
3Step 3: Replace the variable to get the function f(x)
Replace the variable \(x-3\) in \(f(x-3)=x^{2}-12x+27\) with \(x\) to get the function \(f(x) = x^2 -12x + 27\).
Key Concepts
Algebraic FunctionsSubstitution MethodPolynomial Functions
Algebraic Functions
Algebraic functions are mathematical expressions that involve the combination of variables and constants using a finite number of arithmetic operations: addition, subtraction, multiplication, division, and involution (raising to a power). In the context of the exercise, we are dealing with a composition of functions, which involves using one function as an input for another. This concept allows us to analyze complex relationships by breaking them down into simpler ones.
- The function composition \((f \circ g)(x)\) means applying function \(g\) first and then applying function \(f\) to the result.
- Understanding how to decompose and manipulate these functions is key to solving problems involving algebraic functions.
Substitution Method
The substitution method involves replacing a variable with a specific expression in an equation. In this exercise, substitution is a critical step to finding the function \(f(x)\). The process follows a logical sequence:
- Substitute \(g(x) = x-3\) into the composite function \((f \circ g)(x) = x^{2}-6x+8\). This substitution transforms the equation into \(f(x-3)\).
- The next move is resolving the expression \(f(x-3) = (x-3)^2 - 6(x-3) + 8\). Simplifying this results in the equation \(f(x-3) = x^2 - 12x + 27\).
- The crucial final step is switching the expression \(x-3\) back to \(x\), thus identifying the function \(f(x) = x^2 - 12x + 27\).
Polynomial Functions
Polynomial functions, among the most straightforward types of algebraic functions, consist of multiple terms, each having variables raised to whole-number powers with coefficients. They appear frequently in mathematics due to their versatility and the breadth of problems they can model.
- The polynomial form seen in the problem is the quadratic equation \(x^2 - 12x + 27\), which is a representation of \(f(x)\).
- Quadratic polynomials have a maximum degree of 2, with their general formula given as \(ax^2 + bx + c\).
- These functions have significant properties like parabolas in geometry, which are applicable in various fields including physics and engineering.
Other exercises in this chapter
Problem 88
Solve using the Quadratic Formula. \(3 x^{2}+9 x=27\)
View solution Problem 88
List all possible rational roots for each equation. Then use the Rational Root Theorem to find each root. $$ 2 x^{3}+3 x^{2}-8 x-12=0 $$
View solution Problem 88
Solve each equation by factoring. \(3 x^{2}+8 x+4=0\)
View solution Problem 88
Which expression is NOT equivalent to \(\sqrt[4]{4 n^{2}} ?\) \(\begin{array}{llll}{\text { A. }\left(4 n^{2}\right)^{\frac{1}{4}}} & {\text { B. } 2 n^{\frac{1
View solution