Problem 88
Question
Use a graphing device to find all real solutions of the equation, correct to two decimal places. $$ 2 x^{3}-8 x^{2}+9 x-9=0 $$
Step-by-Step Solution
Verified Answer
The real solutions to the equation are approximately 0.82 and 3.68.
1Step 1: Understand the Problem
We are asked to find all real solutions to the cubic equation \(2x^3 - 8x^2 + 9x - 9 = 0\) using a graphing device, and to express each solution correct to two decimal places.
2Step 2: Graph the Function
Input the function \(f(x) = 2x^3 - 8x^2 + 9x - 9\) into a graphing device or software. Visualize the function's graph to locate the points where it intersects the x-axis, because these points are the real solutions to the equation.
3Step 3: Identify the X-Intercepts
From the graph, observe the x-values where the curve crosses the x-axis. These are the real solutions of the equation. Ensure that the intersection points are clear.
4Step 4: Determine Solutions to Two Decimal Places
Use the zoom or trace feature in the graphing device to pinpoint the exact x-values of the intersection points. Record these values and round them to two decimal places for precision.
Key Concepts
Graphing Devices and Their Use in Solving EquationsUnderstanding Real Solutions in the Context of Cubic EquationsPrecision with Decimal Approximation
Graphing Devices and Their Use in Solving Equations
Graphing devices are incredibly helpful tools for visualizing equations and understanding their behavior on a graph. These devices can be specialized calculators or computer software programs that allow for detailed graph rendering. When working on solving equations, particularly cubic equations like \( 2x^3 - 8x^2 + 9x - 9 = 0 \), these devices speed up the process by providing visual insights.
Here's how they work:
Here's how they work:
- Input the equation into the device to generate its graph.
- The graph represents the equation visually, showing the curve of the function along the axes.
- Look for the points where the graph crosses the x-axis; these are the solutions to the equation.
Understanding Real Solutions in the Context of Cubic Equations
Real solutions of an equation are those that can be expressed as actual numbers on the number line. For cubic equations, this involves finding the x-values where the curve touches or crosses the x-axis. These intersections indicate the real roots of the equation, solutions where the function equals zero. In our example cubic equation, \( 2x^3 - 8x^2 + 9x - 9 = 0 \), real solutions are the specific points on the x-axis that satisfy the equation.
Here's why real solutions are important:
Here's why real solutions are important:
- They give concrete answers to problems involving physical quantities.
- Real solutions indicate equilibrium points or specific conditions in applied problems.
Precision with Decimal Approximation
When dealing with cubic equations and their real roots, it's often necessary to express solutions with a certain degree of precision. This is where decimal approximation comes in, which ensures that calculations are not only correct but also precise to a useful degree for further computations.
The process involves:
The process involves:
- Using graphing devices to locate x-axis interception points with precision tools like zoom or trace.
- Recording these x-values with a decimal precision, often to two decimal places, to ensure accuracy.
- Rounding the exact values to maintain consistency in results and comparisons.
Other exercises in this chapter
Problem 86
The real solutions of the given equation are rational. List all possible rational roots using the Rational Zeros Theorem, and then graph the polynomial in the g
View solution Problem 87
Use a graphing device to find all real solutions of the equation, correct to two decimal places. $$ x^{4}-x-4=0 $$
View solution Problem 89
Use a graphing device to find all real solutions of the equation, correct to two decimal places. $$ 4.00 x^{4}+4.00 x^{3}-10.96 x^{2}-5.88 x+9.09=0 $$
View solution Problem 90
Use a graphing device to find all real solutions of the equation, correct to two decimal places. $$ x^{5}+2.00 x^{4}+0.96 x^{3}+5.00 x^{2}+10.00 x+4.80=0 $$
View solution