Problem 87
Question
In place of each question mark in Exercises \(75-92,\) put an expression that will make the rational expressions equivalent. $$\frac{2 x+4}{6}=\frac{?}{3}$$
Step-by-Step Solution
Verified Answer
The missing expression is \( x + 2 \).
1Step 1 - Simplify the Left-Hand Side Expression
First, simplify the expression on the left-hand side. The given expression is \( \frac{2x + 4}{6} \). Factor out 2 from the numerator: \( \frac{2(x + 2)}{6} \).
2Step 2 - Simplify the Fraction
Next, simplify the fraction \( \frac{2(x + 2)}{6} \). Notice that \(6 \) can also be written as \( 3 \cdot 2 \). Therefore, \( \frac{2(x + 2)}{6} = \frac{2(x + 2)}{2 \cdot 3} \). We can cancel the common factor of 2 in the numerator and the denominator: \( \frac{x + 2}{3} \).
3Step 3 - Set the Equivalent Expressions
Because \( \frac{2(x + 2)}{6} \) simplifies to \( \frac{x + 2}{3} \), we can see that the two expressions are equivalent: \( \frac{2x + 4}{6} = \frac{x + 2}{3} \). Therefore, the missing expression on the right-hand side is \( x + 2 \).
Key Concepts
factoringcommon factorsequivalent expressions
factoring
Factoring is a useful algebraic technique that simplifies complex expressions. It involves breaking down a polynomial into simpler terms, called factors, that when multiplied together give the original polynomial.
For instance, consider the expression \(2x + 4\). By factoring out the common factor (which is 2 in this case), we rewrite it as \(2(x + 2)\).
This step is essential in simplifying rational expressions or solving equations, as it makes further operations more manageable.
Factoring serves as a foundational tool in algebra and is often the first step in transforming an expression or equation into a simpler form.
For instance, consider the expression \(2x + 4\). By factoring out the common factor (which is 2 in this case), we rewrite it as \(2(x + 2)\).
This step is essential in simplifying rational expressions or solving equations, as it makes further operations more manageable.
Factoring serves as a foundational tool in algebra and is often the first step in transforming an expression or equation into a simpler form.
common factors
Identifying common factors between the numerator and the denominator helps in simplifying rational expressions.
For the example \(\frac{2(x + 2)}{6}\), we notice that '2' is a common factor in both the numerator and the denominator (since 6 can be written as \(2 \cdot 3\)).
Once we cancel out the common factor of '2', we get the simplified form \(\frac{x + 2}{3}\).
Recognizing and canceling common factors not only simplifies calculations but also aids in understanding the relationship between different parts of an expression.
For the example \(\frac{2(x + 2)}{6}\), we notice that '2' is a common factor in both the numerator and the denominator (since 6 can be written as \(2 \cdot 3\)).
Once we cancel out the common factor of '2', we get the simplified form \(\frac{x + 2}{3}\).
Recognizing and canceling common factors not only simplifies calculations but also aids in understanding the relationship between different parts of an expression.
equivalent expressions
Two expressions are considered equivalent if they yield the same value for any substitution of variables. In mathematical terms, these expressions simplify to the same form.
From our exercise, starting with \(\frac{2x + 4}{6}\) and simplifying it to \(\frac{x + 2}{3}\), we confirm that these two are indeed equivalent. Despite appearing different initially, the process of simplification reveals their equality.
Understanding equivalent expressions is crucial for solving algebraic equations, verifying solutions, and transforming expressions into more convenient forms for problem-solving.
From our exercise, starting with \(\frac{2x + 4}{6}\) and simplifying it to \(\frac{x + 2}{3}\), we confirm that these two are indeed equivalent. Despite appearing different initially, the process of simplification reveals their equality.
Understanding equivalent expressions is crucial for solving algebraic equations, verifying solutions, and transforming expressions into more convenient forms for problem-solving.
Other exercises in this chapter
Problem 87
Perform the indicated operations. Variables in exponents represent integers. $$\frac{x^{2 a}+x^{a}-6}{x^{2 a}+6 x^{a}+9} \div \frac{x^{2 a}-4}{x^{2 a}+2 x^{a}-3
View solution Problem 87
Perform the indicated operations. $$ \frac{2 z^{2}-3 z+6}{z^{2}-1}-\frac{z^{2}-5 z+9}{z^{2}-1} $$
View solution Problem 88
Perform the indicated operations. Variables in exponents represent integers. $$\frac{w^{2 b}+2 w^{b}-8}{w^{2 b}+3 w^{b}-4} \div \frac{w^{2 b}-w^{b}-2}{w^{2 b}-1
View solution Problem 88
Perform the indicated operations. $$ \frac{3}{6 x^{2}-4 x}-\frac{x-2}{9 x-6} $$
View solution