Problem 87
Question
A drafter is making enlargements of a rectangular drawing that preserve the relative width and length of the drawing. The length of the drawing is five- fourths of the width. a. If \(W=\) width, write a polynomial expression in \(W\) that represents the length, and draw a diagram of the rectangle. Do not include the units. b. Write a polynomial expression in \(W\) that represents the perimeter. c. Write a polynomial expression in \(W\) that represents the area.
Step-by-Step Solution
Verified Answer
Length: \(\frac{5}{4}W\), Perimeter: \(\frac{9}{2}W\), Area: \(\frac{5}{4}W^2\).
1Step 1: Express the Length in terms of Width
Given that the length is five-fourths of the width, the polynomial expression for the length in terms of the width, denoted as W, is \[L = \frac{5}{4}W\].
2Step 2: Draw a Diagram
Draw a rectangle and label the width as W and the length as \(\frac{5}{4}W\). This will help visualize the problem.
3Step 3: Find the Perimeter
The perimeter of a rectangle is given by the formula \[P = 2L + 2W\]. Substituting the expression for length, we get \[P = 2 \left(\frac{5}{4}W\right) + 2W = \frac{10}{4}W + 2W = \frac{10}{4}W + \frac{8}{4}W = \frac{18}{4}W = \frac{9}{2}W\].
4Step 4: Find the Area
The area of a rectangle is given by the formula \(A = L \times W\). Substituting the expression for length, we get \[A = \left( \frac{5}{4}W \right) \times W = \frac{5}{4}W^2\].
Key Concepts
Polynomial ExpressionsRectangle GeometryRectangular Perimeter and Area Calculations
Polynomial Expressions
Polynomial expressions are algebraic expressions that consist of variables and coefficients. They involve operations like addition, subtraction, multiplication, and non-negative integer exponents of variables.
In this problem, we use polynomial expressions to represent the length, perimeter, and area of a rectangle. Such expressions help us perform geometric calculations algebraically.
For example, we express the length of the rectangle as \(L = \frac{5}{4}W\), where \(W\) is the width. These expressions allow us to further calculate important properties like perimeter and area using algebraic methods.
In this problem, we use polynomial expressions to represent the length, perimeter, and area of a rectangle. Such expressions help us perform geometric calculations algebraically.
For example, we express the length of the rectangle as \(L = \frac{5}{4}W\), where \(W\) is the width. These expressions allow us to further calculate important properties like perimeter and area using algebraic methods.
Rectangle Geometry
A rectangle is a four-sided polygon with opposite sides equal in length and every angle a right angle (90 degrees). The basic properties of a rectangle include:
In this exercise, the length of the drawing is five-fourths of the width which can be visually represented in a diagram. Just sketch a rectangle, label one side as \(W\) and the opposite longer side as \( \frac{5}{4}W\).
- Two pairs of opposite, equal, and parallel sides.
- Four right angles.
- Diagonals that bisect each other.
In this exercise, the length of the drawing is five-fourths of the width which can be visually represented in a diagram. Just sketch a rectangle, label one side as \(W\) and the opposite longer side as \( \frac{5}{4}W\).
Rectangular Perimeter and Area Calculations
The perimeter of a rectangle is the total distance around the outside, calculated by adding the lengths of all four sides together. The formula is:
\[ P = 2L + 2W \]
Substituting \(L = \frac{5}{4}W\), the perimeter becomes:
\[ P = 2 \times \frac{5}{4}W + 2W = \frac{10}{4}W + \frac{8}{4}W = \frac{18}{4}W = \frac{9}{2}W \]
The area represents the amount of space inside the rectangle, calculated by multiplying the length and the width. The formula is:
\[ A = L \times W \]
With \(L = \frac{5}{4}W\), the area translates to:
\[ A = \frac{5}{4}W \times W = \frac{5}{4}W^2 \]
Understanding these formulas and how to use polynomial expressions in them ensures accurate rectangular perimeter and area calculations, making it easier to solve geometry problems efficiently.
\[ P = 2L + 2W \]
Substituting \(L = \frac{5}{4}W\), the perimeter becomes:
\[ P = 2 \times \frac{5}{4}W + 2W = \frac{10}{4}W + \frac{8}{4}W = \frac{18}{4}W = \frac{9}{2}W \]
The area represents the amount of space inside the rectangle, calculated by multiplying the length and the width. The formula is:
\[ A = L \times W \]
With \(L = \frac{5}{4}W\), the area translates to:
\[ A = \frac{5}{4}W \times W = \frac{5}{4}W^2 \]
Understanding these formulas and how to use polynomial expressions in them ensures accurate rectangular perimeter and area calculations, making it easier to solve geometry problems efficiently.
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