Problem 86
Question
Plot \(y_{1}=e^{-x}\) and \(y_{2}=1-x+\frac{x^{2}}{2}-\frac{x^{3}}{6}+\frac{x^{4}}{24}\) in the same viewing screen. What do you notice?
Step-by-Step Solution
Verified Answer
The plot shows that \( y_2 \) approximates \( y_1 \) well near \( x=0 \), but diverges as \( x \) increases.
1Step 1: Understand the Functions
First, identify the two functions we are dealing with. The function \( y_1 = e^{-x} \) is the exponential decay function, while \( y_2 = 1 - x + \frac{x^{2}}{2} - \frac{x^{3}}{6} + \frac{x^{4}}{24} \) is the fourth-order Taylor series approximation of \( e^{-x} \) centered at \( x=0 \).
2Step 2: Plot the Functions
Using a graphing tool or graph paper, plot \( y_1 = e^{-x} \), which will look like a curve that starts at \( (0,1) \) and approaches the x-axis as \( x \) increases. Plot \( y_2 \) on the same set of axes, noticing that it should also start at \( (0,1) \) due to the Taylor series approximation.
3Step 3: Compare the Plots
Observe how the two plots correspond. \( y_2 \) closely follows \( y_1 \) near \( x=0 \), but begins to diverge as \( x \) moves further away from zero, particularly as \( x \) becomes larger.
Key Concepts
Exponential DecayFunction PlottingGraphical Analysis
Exponential Decay
Exponential decay is a fundamental mathematical concept that describes processes which reduce or deplete over time in a fashion that is proportional to the current value. It is commonly seen in various disciplines such as physics, biology, and finance. The function \( y_1 = e^{-x} \) is a classic example of exponential decay. This function represents a rapidly decreasing curve that starts at 1 when \( x = 0 \), demonstrating how initially there is a substantial drop that becomes more gradual as \( x \) increases.
This behavior can be explained by looking at how the rate of change itself decreases. As the value of the exponent \( x \) increases, the whole expression \( e^{-x} \) becomes smaller, representing less change over time given a constant rate.
If you think of this in practical terms, imagine a substance that decreases in quantity by half every measured time interval. This essence of exponential behavior is captured in the mathematics by maintaining a consistent rate of decrease.
This behavior can be explained by looking at how the rate of change itself decreases. As the value of the exponent \( x \) increases, the whole expression \( e^{-x} \) becomes smaller, representing less change over time given a constant rate.
If you think of this in practical terms, imagine a substance that decreases in quantity by half every measured time interval. This essence of exponential behavior is captured in the mathematics by maintaining a consistent rate of decrease.
Function Plotting
Function plotting is a powerful visual tool that aids in understanding the behavior of mathematical functions. By plotting a function like \( y_1 = e^{-x} \) and comparing it to another function, such as its Taylor series approximation \( y_2 \), we can visually assess how two expressions relate to each other. Such plots allow us to easily see where the functions overlap or deviate from one another.
To plot a function, you generally follow these steps:
To plot a function, you generally follow these steps:
- Choose a range of values for \( x \).
- Calculate the corresponding \( y \) values for each \( x \).
- Represent these as points on a graph and connect these points to form a curve.
Graphical Analysis
Graphical analysis helps deepen our understanding of mathematical concepts by interpreting graph behaviors and characteristics. When comparing the exponential decay function \( y_1 = e^{-x} \) with its Taylor series approximation \( y_2 = 1 - x + \frac{x^{2}}{2} - \frac{x^{3}}{6} + \frac{x^{4}}{24} \), graphical analysis allows us to comprehend not just the numbers but the visual discrepancies and congruities between these functions.
The process involves:
The process involves:
- Identifying where the plots of \( y_1 \) and \( y_2 \) coincide or diverge.
- Evaluating how close the approximation is to the actual curve near \( x=0 \), where it's designed to be the most precise.
- Noticing the deviation that increases as \( x \) moves away from zero due to diminishing accuracy of the polynomial terms.
Other exercises in this chapter
Problem 86
Explain the mistake that is made. Solve the equation: \(\log (x)+\log (3)=1\) Solution: Apply the product property ( 5 ). \(\log (3 x)=1\) Exponentiate (base 10
View solution Problem 86
Use a graphing calculator to plot \(y=\log \left(\frac{x}{2}\right)\) and \(y=\log x-\log 2 .\) Are they the same graph?
View solution Problem 87
Solve the equation: \(\log (x)+\log (x+3)=1\) for \(x\) Solution: Apply the product property (5). \(\quad \log \left(x^{2}+3 x\right)=1\) Exponentiate both side
View solution Problem 87
Use a graphing calculator to plot \(y=\ln \left(x^{2}\right)\) and \(y=2 \ln x\) Are they the same graph?
View solution