Problem 86
Question
Find the standard form of the equation of the specified circle. Center: \((0,0) ;\) radius: 5
Step-by-Step Solution
Verified Answer
The standard form of the equation of the circle is \(x^2 + y^2 = 25\).
1Step 1: Identify the formula
The equation of a circle in standard form is given by \(x^2 + y^2 = r^2\), where \((x, y)\) represent the coordinates of any point on the circle and \(r\) is the radius.
2Step 2: Apply circle parameters
The given center of the circle is at the origin \((0,0)\), and the radius is 5. Substituting the radius value into the formula, we get: \(x^2 + y^2 = 5^2\).
3Step 3: Simplify Equation
Simplify the equation by calculating the square of the radius. This gives: \(x^2 + y^2 = 25\).
Key Concepts
Standard FormRadiusCenter of Circle
Standard Form
When talking about the circle equations, the standard form is one of the most common ways to write them. This form makes it straightforward to identify different properties of the circle.
In its standard form, the equation of a circle looks like this:
For instance, if the center is at the origin \((0, 0)\), the equation simplifies to \(x^2 + y^2 = r^2\). This particular case is often simpler to understand and easier to work with.
In its standard form, the equation of a circle looks like this:
- \((x - h)^2 + (y - k)^2 = r^2\)
- \((h, k)\) is the center of the circle.
- \(r\) is the radius of the circle.
For instance, if the center is at the origin \((0, 0)\), the equation simplifies to \(x^2 + y^2 = r^2\). This particular case is often simpler to understand and easier to work with.
Radius
The radius of a circle is defined as the distance from the center to any point on its boundary. This is an essential circle parameter and is denoted by the symbol \(r\).
In the standard form of the circle's equation \((x - h)^2 + (y - k)^2 = r^2\), the radius can be identified immediately as the square root of the right-hand side. If \(r = 5\), inserting it into the equation, you get \((x - h)^2 + (y - k)^2 = 25\).
The procedure followed is squaring the radius, such as:
In the standard form of the circle's equation \((x - h)^2 + (y - k)^2 = r^2\), the radius can be identified immediately as the square root of the right-hand side. If \(r = 5\), inserting it into the equation, you get \((x - h)^2 + (y - k)^2 = 25\).
The procedure followed is squaring the radius, such as:
- If \(r = 5\), then \(r^2 = 25\).
- This is inserted into the equation, giving \(x^2 + y^2 = 25\) for a circle centered at \((0,0)\).
Center of Circle
The center of a circle is a key feature that defines the position of the circle in a coordinate plane. It is denoted by \((h, k)\), which represents the x and y coordinates of the center.
In the standard form equation \((x - h)^2 + (y - k)^2 = r^2\), the terms \((x - h)\) and \((y - k)\) indicate that all points \((x, y)\) on the circle maintain a constant distance from this center.
For a circle centered at the origin \((0,0)\), the equation simplifies to \(x^2 + y^2 = r^2\).
In the standard form equation \((x - h)^2 + (y - k)^2 = r^2\), the terms \((x - h)\) and \((y - k)\) indicate that all points \((x, y)\) on the circle maintain a constant distance from this center.
For a circle centered at the origin \((0,0)\), the equation simplifies to \(x^2 + y^2 = r^2\).
- This means each point on the circle is exactly \(r\) units away from the center point \((0,0)\).
Other exercises in this chapter
Problem 85
Find the standard form of the equation of the specified circle. Center: \((0,0) ;\) radius: 3
View solution Problem 86
Write equations of the lines through the point (a) parallel to the given line and (b) perpendicular to the given line. Point \(\quad\) Line \((-5,4) \quad x+y=8
View solution Problem 87
Write equations of the lines through the point (a) parallel to the given line and (b) perpendicular to the given line. Point \(\quad\) Line \(\begin{array}{ll}\
View solution Problem 87
Find the standard form of the equation of the specified circle. Center: \((-4,1)\); radius: \(\sqrt{2}\)
View solution