Problem 83

Question

Write the Lewis structures of \(\mathrm{H}_{2} \mathrm{CNH}\) and \(\mathrm{H}_{3} \mathrm{CNH}_{2}\). Predict which molecule has the greater \(\mathrm{C}-\mathrm{N}\) bond energy.

Step-by-Step Solution

Verified
Answer
\( \mathrm{H}_2 \mathrm{CNH} \) has the greater \( \mathrm{C}-\mathrm{N} \) bond energy due to its triple bond.
1Step 1: Determine Valence Electrons
To write the Lewis structures, we first need to calculate the total number of valence electrons in each molecule. For \( \mathrm{H}_2 \mathrm{CNH} \): 2 hydrogen atoms each with 1 electron, 1 carbon with 4, 1 nitrogen with 5, and a total of 2 electrons for hydrogen (\(2 \times 1 + 4 + 5 + 1 = 12\)). For \( \mathrm{H}_3 \mathrm{CNH}_2 \): 5 hydrogen atoms (\(5 \times 1 = 5\)), 1 carbon with 4, 1 nitrogen with 5, totaling 14 electrons (\(5 + 4 + 5 = 14\)).
2Step 2: Assign Connectivity
Establish the connectivity of atoms. \( \mathrm{H}_2 \mathrm{CNH} \) has a linear arrangement such that \( H - C \equiv N - H \). \( \mathrm{H}_3 \mathrm{CNH}_2 \) typically has \( H \) around \( C \), forming \( H_3C - NH_2 \), a standard arrangement in amines.
3Step 3: Draw Initial Structures
For \( \mathrm{H}_2 \mathrm{CNH} \): Start with single bonds \( H - C - N - H \) and add multiple bonds to satisfy valence electrons.For \( \mathrm{H}_3 \mathrm{CNH}_2 \): Begin with \( H_3C - NH_2 \) showing single bonds.
4Step 4: Complete Octets
Ensure each atom satisfies its octet (or duet for H):- \( \mathrm{H}_2 \mathrm{CNH} \): Carbon and nitrogen complete their octets by forming a triple bond, \( H - C \equiv N - H \). Each hydrogen forms a stable single bond. Count electrons to confirm total is 12.- \( \mathrm{H}_3 \mathrm{CNH}_2 \): The octets for \( \mathrm{C} \) and \( \mathrm{N} \) are completed by single bonds, affirm total number is 14 electrons.
5Step 5: Compare Bond Energies
In molecules, triple bonds (\( \mathrm{C} \equiv \mathrm{N} \)) have higher bond energies compared to single bonds (\( \mathrm{C}-\mathrm{N} \)). Hence, \( \mathrm{H}_2 \mathrm{CNH} \) with a triple bond should have a greater \( \mathrm{C}-\mathrm{N} \) bond energy compared to the single bond in \( \mathrm{H}_3 \mathrm{CNH}_2 \).

Key Concepts

Valence ElectronsC-N Bond EnergyOctet Rule
Valence Electrons
Valence electrons are the outermost electrons of an atom and they play a crucial role in chemical bonding. In the context of Lewis structures for molecules like \( \text{H}_2 \text{CNH} \) and \( \text{H}_3 \text{CNH}_2 \), we aim to account for the total number of valence electrons present in each molecule.

Understanding the count of valence electrons helps determine how atoms bond and organize themselves within a molecule, affecting its structure and properties.

Let's break down the counting process:
  • Hydrogen (H) has 1 valence electron.
  • Carbon (C) has 4 valence electrons.
  • Nitrogen (N) has 5 valence electrons.
For \( \text{H}_2 \text{CNH} \), there are 2 hydrogens contributing 2 electrons, 1 carbon contributing 4, and 1 nitrogen providing 5 electrons, plus an additional electron from hydrogen's single bond, making the total 12 valence electrons.

For \( \text{H}_3 \text{CNH}_2 \), the 5 hydrogens contribute 5 electrons, carbon contributes 4, and nitrogen adds 5 more, leading to a total of 14 valence electrons

By accounting for these valence electrons, we can accurately create the Lewis structure that visually represents the bonding and lone electron pairs.
C-N Bond Energy
Bond energy refers to the energy required to break a bond between two atoms. A high C-N bond energy suggests a stronger and more stable bond.

In the Lewis structures for \( \text{H}_2 \text{CNH} \), there is a triple bond between carbon and nitrogen, whereas in \( \text{H}_3 \text{CNH}_2 \), there is a single bond.

Triple bonds, like \( \text{C} \equiv \text{N} \), involve more electron sharing than single bonds and are thus stronger, possessing higher bond energies. This means breaking a triple bond requires more energy compared to a single bond.

This concept explains why \( \text{H}_2 \text{CNH} \) has a greater \( \text{C}-\text{N} \) bond energy than \( \text{H}_3 \text{CNH}_2 \).
Bonds are crucial in determining the chemical stability and reactivity of a compound, with triple bonds rendering \( \text{H}_2 \text{CNH} \) more stable in this aspect compared to its counterpart with a single bond.
Octet Rule
The octet rule is a chemistry principle that states that atoms tend to bond in such a way that each atom has eight electrons in its valence shell, resembling the electron configuration of a noble gas.

In the practice of constructing Lewis structures, it is important to apply this rule to ensure stability of the molecule.

For \( \text{H}_2 \text{CNH} \), carbon and nitrogen achieve their octets through a series of bonds, specifically the triple bond between them, while hydrogen achieves the 'duet' rule due to its capacity to hold only 2 electrons.

Meanwhile, in \( \text{H}_3 \text{CNH}_2 \), carbon and nitrogen complete their octets through single bonds, and the multiple hydrogen atoms each satisfy their duet rule.

This focus on fulfilling the octet or duet rule is a fundamental step when drafting Lewis structures. It not only solidifies the electron distribution but also enhances our understanding of molecular behavior and reactivity.