Problem 82
Question
Find the limits in Exercises \(80-86\). $$\lim _{x \rightarrow-\infty}\left(\sqrt{x^{2}+3}+x\right)$$
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Understand the Expression
The expression we are dealing with is \( \lim_{x \rightarrow -\infty} \left( \sqrt{x^2 + 3} + x \right) \). As \( x \rightarrow -\infty \), both terms inside the parenthesis approach infinity, but at different rates. We need to find a way to simplify these terms to determine the limit.
2Step 2: Simplify the Expression
Rewrite the expression inside the limit: \( \sqrt{x^2 + 3} = \sqrt{x^2(1 + \frac{3}{x^2})} = |x|\sqrt{1 + \frac{3}{x^2}} \). Since \( x \rightarrow -\infty \), \( |x| = -x \). Thus, \( \sqrt{x^2 + 3} = -x\sqrt{1 + \frac{3}{x^2}} \).
3Step 3: Substitute Back into Limit
Substitute the simplified expression back into the limit: \( \lim_{x \rightarrow -\infty} \left(-x\sqrt{1 + \frac{3}{x^2}} + x\right) \). Simplify further: \( \lim_{x \rightarrow -\infty} x(-\sqrt{1 + \frac{3}{x^2}} + 1) \).
4Step 4: Simplify Further and Evaluate
Notice the expression \(-\sqrt{1 + \frac{3}{x^2}} + 1\). Evaluating the limit of the expression \( \sqrt{1+\frac{3}{x^2}} \rightarrow 1 \) as \( x \rightarrow -\infty \), thus \( -\sqrt{1 + \frac{3}{x^2}} + 1 \rightarrow 0. \) Therefore, \( \lim_{x \rightarrow -\infty} x(0) = 0 \).
5Step 5: Conclusion of Evaluation
Finally, the limit of the expression \( \lim_{x \rightarrow -\infty} \left( \sqrt{x^2+3} + x \right) \) evaluates to 0.
Key Concepts
Asymptotic BehaviorInfinity LimitsSquare Root Simplification
Asymptotic Behavior
Asymptotic behavior refers to how a function behaves as its input approaches a certain value or infinity. In this exercise, we are concerned with the behavior of the function as \( x \) approaches \(-\infty\). Understanding asymptotic behavior allows us to predict the trend of a graph, especially for large values of \( x \).When analyzing the function \( \sqrt{x^2 + 3} + x \), we note that each term contributes differently to the function's behavior at negative infinity. For very large negative values of \( x \), the term \( x \) is crucial, as it tends to dominate due to its linear nature when compared to terms inside a square root, highlighting the importance of examining growth rates in asymptotic analysis.Overall, asymptotic behavior helps us see beyond immediate values to the important trends and tendencies of a function as \( x \) stretches out towards \(-\infty\), providing insight into its limit.
Infinity Limits
Infinity limits deal with the behavior of functions as the variable approaches positive or negative infinity. In this scenario, the challenge is to find the limit of the expression \( \lim_{x \rightarrow -\infty} ( \sqrt{x^2 + 3} + x) \).Here's the thought process:
- As \( x \to -\infty \), both \( \sqrt{x^2 + 3} \) and \( x \) individually approach infinity, but at different rates.
- To tackle this, we simplify the square root using algebraic manipulation, turning it into \(-x\sqrt{1 + \frac{3}{x^2}}\).
Square Root Simplification
Square root simplification is a crucial technique in solving limits, particularly those involving expressions like \( \sqrt{x^2 + 3} \). The process involves reshaping the expression to evaluate extreme behavior more easily.
- We rewrote \( \sqrt{x^2 + 3} \) as \( \sqrt{x^2(1 + \frac{3}{x^2})} \).
- This allowed us to express it as \(-x\sqrt{1 + \frac{3}{x^2}}\) when \( x \) heads to \(-\infty\), given \(|x| = -x \) at such values.
Other exercises in this chapter
Problem 81
Find the limits in Exercises \(80-86\). $$\lim _{x \rightarrow \infty}\left(\sqrt{x^{2}+25}-\sqrt{x^{2}-1}\right)$$
View solution Problem 82
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Use a CAS to perform the following steps: a. Plot the function near the point \(x_{0}\) being approached. b. From your plot guess the value of the limit. $$\lim
View solution Problem 83
Find the limits in Exercises \(80-86\). $$\lim _{x \rightarrow+\infty}\left(2 x+\sqrt{4 x^{2}+3 x-2}\right)$$
View solution