Problem 82
Question
a. Graph \(h(x)=x^{2} \cos \left(1 / x^{3}\right)\) to estimate \(\lim _{x \rightarrow 0} h(x),\) zooming in on the origin as necessary. b. Confirm your estimate in part (a) with a proof.
Step-by-Step Solution
Verified Answer
\( \lim_{x \rightarrow 0} h(x) = 0 \).
1Step 1: Understand the function
We need to graph the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \). This function is defined for \( x eq 0 \) because \( \cos\left(\frac{1}{x^3}\right) \) is undefined at \( x = 0 \). The factor \( x^2 \) suggests that the function could approach zero as \( x \) approaches zero.
2Step 2: Graph the Function
By using a graphing calculator or software like Desmos, plot the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \). Zoom in on the graph around the origin (\( x = 0 \)) to observe the behavior of the function. You should see that as \( x \) approaches zero, the graph appears to approach \( h(x) = 0 \).
3Step 3: Analyze the Behavior of the Function
Consider the function \( \cos\left(\frac{1}{x^3}\right) \), which oscillates between -1 and 1. The \( x^2 \) term, however, approaches zero as \( x \to 0 \). This suggests that regardless of the oscillating cosine term, the overall function \( h(x) \) should also approach 0 since \( x^2\cdot \text{bounded term} \to 0 \).
4Step 4: Proof with Squeeze Theorem
Consider the inequality \(-x^2 \leq x^2 \cos\left(\frac{1}{x^3}\right) \leq x^2\). As \( x \rightarrow 0 \), both \(-x^2\) and \(x^2\) approach 0. By the squeeze theorem, since \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \) is bound by these expressions, \( \lim_{x \to 0} h(x) = 0 \).
Key Concepts
Squeeze TheoremFunction BehaviorGraphing Functions
Squeeze Theorem
The Squeeze Theorem is a powerful tool in calculus used to determine the limit of a function. It's especially useful when dealing with functions that fluctuate or oscillate between two boundaries. Imagine you're trying to "squeeze" the function you're examining between two simpler functions that are easier to handle.
For the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), we can use the Squeeze Theorem by establishing the inequality
The theorem then tells us that if \(-x^2\) and \(x^2\) both tend toward the same limit, then \( h(x) \) must also tend to that limit. Thus,
For the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), we can use the Squeeze Theorem by establishing the inequality
- \(-x^2 \leq x^2 \cos\left(\frac{1}{x^3}\right) \leq x^2\)
The theorem then tells us that if \(-x^2\) and \(x^2\) both tend toward the same limit, then \( h(x) \) must also tend to that limit. Thus,
- \( \lim_{x \to 0} h(x) = 0 \)
Function Behavior
Understanding the behavior of a function as it approaches a particular point is essential. This helps to intuitively grasp how the function behaves under different conditions.
For the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), consider the two components: \( x^2 \) and \( \cos\left(\frac{1}{x^3}\right) \).
By analyzing each component of the function, you gain insights into why the limit behaves the way it does, reinforcing the conclusion reached through formal methods like the Squeeze Theorem.
For the function \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), consider the two components: \( x^2 \) and \( \cos\left(\frac{1}{x^3}\right) \).
- \( x^2 \) is straightforward; it becomes smaller and closer to zero as \( x \) approaches zero, regardless of any surrounding oscillations.
- The cosine part, \( \cos\left(\frac{1}{x^3}\right) \), fluctuates between -1 and 1. This rapid oscillation doesn't allow the cosine value itself to settle easily at a particular number.
By analyzing each component of the function, you gain insights into why the limit behaves the way it does, reinforcing the conclusion reached through formal methods like the Squeeze Theorem.
Graphing Functions
Graphing is an invaluable tool for visualizing function behavior and understanding how they approach certain limits.
To examine \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), graphing the function allows us to visually confirm its behavior near \( x = 0 \). By using graphing software like Desmos, you can see how \( h(x) \) behaves by zooming into the graph close to the origin.
To examine \( h(x) = x^2 \cos\left(\frac{1}{x^3}\right) \), graphing the function allows us to visually confirm its behavior near \( x = 0 \). By using graphing software like Desmos, you can see how \( h(x) \) behaves by zooming into the graph close to the origin.
- Initially, the graph might seem chaotic due to the oscillations of \( \cos\left(\frac{1}{x^3}\right) \), but as you zoom closer, it becomes evident that the function values tend toward zero.
- The graph effectively demonstrates what you've established analytically — that despite fluctuations, \( h(x) \) maintains a trajectory narrowing towards zero.
Other exercises in this chapter
Problem 81
a. Graph \(g(x)=x \sin (1 / x)\) to estimate lim \(_{x \rightarrow 0} g(x),\) zooming in on the origin as necessary. b. Confirm your estimate in part (a) with a
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Find the limits in Exercises \(80-86\). $$\lim _{x \rightarrow-\infty}\left(\sqrt{x^{2}+3}+x\right)$$
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Use a CAS to perform the following steps: a. Plot the function near the point \(x_{0}\) being approached. b. From your plot guess the value of the limit. $$\lim
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