Problem 79
Question
Use the indicated base to logarithmically transform each exponential relationship so that a linear relationship results. Then use the indicated base to graph each relationship either in log or semilog transformed coordinates so that a straight line results. $$ y=2^{x} ; \text { base } 2 $$
Step-by-Step Solution
Verified Answer
Transforming to \( \log_2(y) = x \), the graph is linear with slope 1 on semilog axes.
1Step 1: Identify the Function and Base
The given exponential function is \( y = 2^x \), and we are asked to use base 2 for the transformation.
2Step 2: Apply Logarithm of the Specified Base
Take the logarithm base 2 of both sides of the equation \( y = 2^x \). This gives us \( \log_2(y) = x \cdot \log_2(2) \). Since \( \log_2(2) = 1 \), the equation simplifies to \( \log_2(y) = x \).
3Step 3: Resulting Linear Relationship
The transformed equation \( \log_2(y) = x \) is a linear relationship, where \( x \) is the independent variable and \( \log_2(y) \) the dependent variable. It follows the form \( y = mx + c \) with slope \( m = 1 \) and intercept \( c = 0 \).
4Step 4: Graphing the Transformed Equation
Plot \( x \) against \( \log_2(y) \) using a semilog graph, where the y-axis is logarithmically scaled. This will result in a straight line with a slope of 1, indicating a linear relationship on the logarithmically transformed coordinates.
Key Concepts
Understanding Exponential FunctionsLinear Relationship from Exponential FunctionsGraphing Logarithmically Transformed Equations
Understanding Exponential Functions
An exponential function is a type of mathematical expression where a constant base is raised to a variable exponent. In our example, the function given is \( y = 2^x \). Here, the base is \( 2 \), and \( x \) is the exponent that varies. Exponential functions are characterized by rapid growth or decay, depending on the context. This rapid change is due to the multiplication of the base by itself as \( x \) changes. Key characteristics of exponential functions:
- They have a constant base; in this example, the base is \( 2 \).
- The exponent is typically the variable, influencing the function's growth.
Linear Relationship from Exponential Functions
To find a linear relationship from an exponential function, a logarithmic transformation is used. By applying the appropriate logarithm (in this case, base 2), we convert the exponential equation \( y = 2^x \) into a linear form. The transformed equation is \( \log_2(y) = x \), which mirrors the form of a classic linear equation \( y = mx + c \). Here, the transformation works because the logarithm of the base itself, \( \log_2(2) \), equals 1. So, the transformed equation simplifies to \( x = \log_2(y) \). This equation becomes a straight line with:
- The slope \( m = 1 \)
- An intercept \( c = 0 \)
Graphing Logarithmically Transformed Equations
When graphing an equation that has undergone logarithmic transformation, such as \( \log_2(y) = x \), we typically use a semilog or logarithmic scale. This kind of graphing converts the exponential growth characteristics into a linear format, enabling simpler interpretation. Steps to graph:
- Plot \( x \) on the horizontal axis (standard scale).
- Plot \( \log_2(y) \) on the vertical axis (logarithmic scale).
Other exercises in this chapter
Problem 78
Find the inverse of \(f(x)=\left(\frac{1}{3}\right)^{x}, x \in \mathbf{R}\), together with its domain, and graph both functions in the same coordinate system.
View solution Problem 78
Which real number \(x\) satisfies (a) \(\log _{3} 81=x\) ? (b) \(\log _{5} \frac{1}{25}=x\) ? (c) \(\log _{10} 1000=x ?\)
View solution Problem 79
Simplify the following expressions: (a) \(2^{5 \log _{2} x}\) (b) \(4^{3 \log _{4} x}\) (c) \(5^{5 \log _{1 / 5} x}\) (d) \(4^{3 \log _{2} x}\) (e) \(2^{3 \log
View solution Problem 79
Simplify the following expressions: (a) \(-\ln \frac{1}{3}\) (b) \(\log _{4}\left(x^{2}-4\right)\) (c) \(\log _{2} 4^{3 x-1}\)
View solution