Problem 77
Question
In place of each question mark in Exercises \(75-92,\) put an expression that will make the rational expressions equivalent. $$5=\frac{10}{?}$$
Step-by-Step Solution
Verified Answer
The expression that makes the rational expressions equivalent is 2.
1Step 1: Understand the Equality
The given equation is: \[ 5 = \frac{10}{?} \]The goal is to find an expression that makes this equality hold true. Essentially, we need to determine the value of the denominator that makes the fraction on the right side equal to 5.
2Step 2: Isolate the Unknown
To isolate the question mark (denoted as \( x \)), rewrite the equation to solve for \( ? \): \[ 5 = \frac{10}{x} \]This implies that finding \( x \) involves basic algebraic manipulation.
3Step 3: Solve for the Unknown
To find \( x \), multiply both sides of the equation by \( x \) to get rid of the denominator:\[ 5x = 10 \]Next, solve for \( x \) by dividing both sides of the equation by 5:\[ x = \frac{10}{5} \]
4Step 4: Simplify the Expression
Simplify the expression to find the value of \( x \): \[ x = 2 \]So, the expression that should replace the question mark is \( 2 \).
Key Concepts
equivalent expressionsbasic algebraic manipulationsolving for an unknown
equivalent expressions
In algebra, we often come across rational expressions and need to determine if they are equivalent. In the given exercise, the goal is to find a value for the question mark that makes the two sides of the equation equal. This involves understanding that both sides of the equation should represent the same value.
For example, if we start with the equation \[ 5 = \frac{10}{?} \], we need to find what the denominator should be to make this true. By figuring this out, we make both expressions equivalent because they would produce the same value when evaluated.
For example, if we start with the equation \[ 5 = \frac{10}{?} \], we need to find what the denominator should be to make this true. By figuring this out, we make both expressions equivalent because they would produce the same value when evaluated.
basic algebraic manipulation
Basic algebraic manipulation involves using mathematical operations to simplify or solve equations. In this exercise, we need to isolate the unknown variable (question mark) to find its value. This is done through a series of steps:
- Isolate the unknown: Rewrite the equation to focus on the unknown. For example, \[ 5 = \frac{10}{x} \].
- Eliminate the fraction: Multiply both sides by the denominator to remove the fraction. This gives us \[ 5x = 10 \].
- Solve for the unknown: Divide both sides by 5, resulting in \[ x = 2 \].
solving for an unknown
Solving for an unknown involves finding the value that satisfies the equation. In simple linear equations like the given example, we perform operations that leave the variable by itself on one side of the equation.
Let's review the steps:
Let's review the steps:
- Start with the equation: \[ 5 = \frac{10}{x} \].
- Multiply both sides by \( x \) to get rid of the denominator: \[ 5x = 10 \].
- Divide both sides by 5 to isolate \( x \): \[ x = 2 \].
Other exercises in this chapter
Problem 77
Solve each equation. Identify each equation as a conditional equation, an inconsistent equation, or an identity. State the solution sets to the identities using
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Perform the indicated operations. $$\frac{2 x^{2}+7 x-15}{4 x^{2}-100} \cdot \frac{2 x^{2}-9 x-5}{4 x^{2}-1}$$
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Solve each equation. Identify each equation as a conditional equation, an inconsistent equation, or an identity. State the solution sets to the identities using
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Perform the indicated operations. $$\frac{x^{3}+1}{x^{2}-1} \cdot \frac{3 x-3}{x^{3}-x^{2}+x}$$
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