Problem 77
Question
An Identity Involving Combinations Kevin has ten different marbles, and he wants to give three of them to Luke and two to Mark. How many ways can he choose to do this? There are two ways of analyzing this problem: He could first pick three for Luke and then two for Mark, or he could first pick two for Mark and then three for Luke. Explain how these two viewpoints show that $$C(10,3) \cdot C(7,2)=C(10,2) \cdot C(8,3)$$ In general, explain why $$C(n, r) \cdot C(n-r, k)=C(n, k) \cdot C(n-k, r)$$
Step-by-Step Solution
Verified Answer
Both methods count ways to distribute marbles, leading to the identity \( C(10,3)\cdot C(7,2)=C(10,2)\cdot C(8,3) \).
1Step 1: Understanding Combinations
Combinations refer to selecting items from a group, where the order does not matter. The notation \( C(n, r) \) represents the number of ways to choose \( r \) items from a total of \( n \) items.
2Step 2: Breaking Down the Problem
Kevin wants to give 3 marbles to Luke and 2 to Mark. We can choose 3 marbles from 10 for Luke, and then 2 marbles from the remaining 7 for Mark. This is represented by the expression \( C(10,3) \times C(7,2) \).
3Step 3: Reversing the Selection Process
Alternatively, Kevin could choose 2 marbles from 10 for Mark first, and then choose 3 marbles from the remaining 8 for Luke. This is expressed as \( C(10,2) \times C(8,3) \).
4Step 4: Equivalence of Counting Methods
These two expressions show different ways to distribute the marbles, but they must yield the same total number of ways, emphasizing that \( C(10,3) \times C(7,2) = C(10,2) \times C(8,3) \). Each expression calculates a sequence of independent choices to achieve the same outcome.
5Step 5: Generalizing the Identity
Generally, \( C(n, r) \times C(n-r, k) \) is the number of ways to pick \( r \) items and then \( k \) from the remainder, and \( C(n, k) \times C(n-k, r) \) is for choosing \( k \) items first and then \( r \) from what's left. Both structures count the same distinct outcome over the total \( n \) items, confirming the identity.
Key Concepts
CombinationsBinomial CoefficientsCounting Principles
Combinations
Combinations are a way to count the selection of items, where the arrangement or order of the items does not matter. This concept is vital in many areas of mathematics and real-world scenarios. If you think about choosing marbles from a bag, whether red, blue, or green, the focus is on which marbles are chosen, not the sequence. The mathematical notation for combinations is represented as \( C(n, r) \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items selected.
- \( C(n, r) \) is also referred to as "n choose r."
- For instance, \( C(10, 3) \) means how many ways can you choose 3 items out of 10.
Binomial Coefficients
In the realm of combinatorics, binomial coefficients appear prominently in the expansion of binomials, that is expressions like \((a + b)^n\). These coefficients are essentially the same as combinations.A binomial coefficient is expressed as \( C(n, r) \) or \( \binom{n}{r} \), and it tells you how many different ways you can pick \( r \) elements from a set of \( n \) elements. It forms a crucial part of the binomial theorem: \[(a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r\]
- It helps calculate terms in polynomial expansions.
- \( \binom{n}{r} \) is determined by the same formula for combinations.
Counting Principles
Counting principles are foundational ideas used to count how many different ways an event can occur. These principles often involve combinations, permutations, and factorials. When Kevin decides to divide marbles between friends, he applies these principles by choosing marbles in steps:
- Firstly, by choosing how many marbles Luke receives, calculated using combinations.
- Secondly, selecting from the remaining marbles for Mark.
Other exercises in this chapter
Problem 75
55–75 Solve the problem using the appropriate counting principle(s). Parking Committee A five-person committee consisting of students and teachers is being form
View solution Problem 76
Complementary Combinations Without performing any calculations, explain in words why the number of ways of choosing two objects from ten objects is the same as
View solution Problem 78
Why is \(\left(\begin{array}{c}{n} \\ {r}\end{array}\right)\) the Same as \(C(n, r) ?\) This exercise explains why the binomial coefficients \(\left(\begin{arra
View solution Problem 74
55–75 Solve the problem using the appropriate counting principle(s). Geometry Twelve dots are drawn on a page in such a way that no three are collinear. How man
View solution