Problem 74
Question
55–75 Solve the problem using the appropriate counting principle(s). Geometry Twelve dots are drawn on a page in such a way that no three are collinear. How many straight lines can be formed by joining the dots?
Step-by-Step Solution
Verified Answer
There are 66 lines possible.
1Step 1: Understanding the Problem
The problem involves determining the number of lines that can be formed by joining two dots when there are twelve dots on a page. The restriction is that no three dots are collinear, meaning each combination of two dots will form a unique line.
2Step 2: Applying the Counting Principle: Combinations
To find the number of lines, we need to select 2 dots out of 12 to form each line. This is a combination problem, calculated as \( \binom{n}{r} \), where \( n \) is the total number of dots and \( r \) is the number of dots needed for each line.
3Step 3: Calculating the Combination
Calculate \( \binom{12}{2} \), which represents the number of ways to choose 2 dots from 12. This is calculated as \( \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \).
4Step 4: Conclusion
Thus, the number of distinct lines that can be formed by joining these twelve dots is 66.
Key Concepts
Counting PrinciplesGeometryCombinationsCollinear Points
Counting Principles
Counting principles are fundamental techniques in combinatorics that allow us to determine the number of ways an event can occur. In problems involving counting, we often use principles such as permutations and combinations. These tools help us break down complex counting situations into more manageable parts.
In the given exercise, we need to calculate the number of ways to form lines by selecting pairs of dots. Since the order in which we choose the dots does not matter (a line joining dot A to dot B is the same as joining dot B to dot A), we use combinations, not permutations.
In the given exercise, we need to calculate the number of ways to form lines by selecting pairs of dots. Since the order in which we choose the dots does not matter (a line joining dot A to dot B is the same as joining dot B to dot A), we use combinations, not permutations.
- Permutations are used when the order does matter.
- Combinations are used when the order does not matter.
Geometry
In geometry, straight lines are fundamental elements that connect two points. In the context of the exercise, 12 dots are placed on a page, and each pair of points can form a unique straight line if no three points are collinear.
This setting is crucial because it ensures each pair of points contributes to a distinct line. Additionally, it avoids scenarios where three or more points lie on the same line, which would reduce the total number of distinct lines formed.
Geometry not only provides the setting for this problem but also influences the counting. By assuring that each line is distinct, the problem emphasizes the uniqueness of each line formed. Thus, geometry sets the rules for how we apply counting principles.
This setting is crucial because it ensures each pair of points contributes to a distinct line. Additionally, it avoids scenarios where three or more points lie on the same line, which would reduce the total number of distinct lines formed.
Geometry not only provides the setting for this problem but also influences the counting. By assuring that each line is distinct, the problem emphasizes the uniqueness of each line formed. Thus, geometry sets the rules for how we apply counting principles.
Combinations
Combinations are used to calculate the number of ways to choose a subset of items from a larger set without regard to the order of selection. This is exactly what is needed in our problem. We are forming lines by choosing two dots out of 12.
The notation for combinations is \({\binom{n}{r}}\), which indicates the number of ways to choose \({r}\) items from \({n}\) items. This is calculated using the formula:\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \]For our problem, \({n=12}\) and \({r=2}\), giving us:\[ \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \]This calculation shows how many distinct lines can be formed.
The notation for combinations is \({\binom{n}{r}}\), which indicates the number of ways to choose \({r}\) items from \({n}\) items. This is calculated using the formula:\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \]For our problem, \({n=12}\) and \({r=2}\), giving us:\[ \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \]This calculation shows how many distinct lines can be formed.
Collinear Points
Collinear points are points that lie on the same straight line. In the exercise, it's critical to know that no three points among the twelve are collinear.
If some points were collinear, it would mean they lie on the same line, reducing the total number of unique lines possible. Since the problem states no three points are collinear, each pair of points forms a distinct line without sharing any other points on that line.
This condition simplifies the problem as it allows each pair selection to be considered independently when forming lines. Thus, while calculating combinations, as in this case, collinearity is a vital consideration for ensuring the accuracy of the total count.
If some points were collinear, it would mean they lie on the same line, reducing the total number of unique lines possible. Since the problem states no three points are collinear, each pair of points forms a distinct line without sharing any other points on that line.
This condition simplifies the problem as it allows each pair selection to be considered independently when forming lines. Thus, while calculating combinations, as in this case, collinearity is a vital consideration for ensuring the accuracy of the total count.
Other exercises in this chapter
Problem 72
55–75 Solve the problem using the appropriate counting principle(s). Choosing a Delegation Three delegates are to be chosen from a group of four lawyers, a prie
View solution Problem 73
55–75 Solve the problem using the appropriate counting principle(s). Choosing a Committee In how many ways can a committee of four be chosen from a group of ten
View solution Problem 75
55–75 Solve the problem using the appropriate counting principle(s). Parking Committee A five-person committee consisting of students and teachers is being form
View solution Problem 76
Complementary Combinations Without performing any calculations, explain in words why the number of ways of choosing two objects from ten objects is the same as
View solution