Problem 77
Question
$$ 5 z-5+10 z+2 z+16 $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(17z + 11\).
1Step 1: Identify Like Terms
Start by identifying the like terms in the expression. In this case, the like terms are \(5z\), \(10z\), and \(2z\). Likewise, \(-5\) and \(16\) are like terms as they are constants.
2Step 2: Combine Like Terms
Sum the coefficients of the variables 'z' which are 5, 10, and 2. And also, sum the constants -5 and 16.
3Step 3: Write Down The Final Simplified Expression
Once we have the sums from step 2, write these down to form the final simplified expression.
Key Concepts
Algebraic ExpressionConstantsCoefficients
Algebraic Expression
An algebraic expression is a mathematical phrase that includes numbers, variables, and operation symbols. It does not have an equality sign like an equation, so it doesn't make a statement of equality. Instead, it is a combination of several components connected through operations such as addition, subtraction, multiplication, and division.
In the original exercise, the expression given was:
\( 5z - 5 + 10z + 2z + 16 \).
This is a typical algebraic expression that consists of terms. Terms are the building blocks of an expression and are separated by plus or minus signs.
In the original exercise, the expression given was:
\( 5z - 5 + 10z + 2z + 16 \).
This is a typical algebraic expression that consists of terms. Terms are the building blocks of an expression and are separated by plus or minus signs.
- The terms connected to variables here are \(5z\), \(10z\), and \(2z\).
- While constant terms like \(-5\) and \(16\) are standalone numbers without variables.
Constants
Constants are specific numbers within an algebraic expression that do not contain any variables. They represent fixed values and remain unchanged regardless of the value assigned to any variables in the expression. Understanding constants is important, especially when simplifying expressions.
In our exercise, the constants are-5 and 16. Even though they don't link to a variable, they still play a role in the expression's value.
\(-5 + 16 = 11\).
This understanding helps in creating the final simplified form of an algebraic expression.
In our exercise, the constants are-5 and 16. Even though they don't link to a variable, they still play a role in the expression's value.
- The constant \(-5\) is subtracted from the expression.
- On the other hand, the constant \(16\) is added.
\(-5 + 16 = 11\).
This understanding helps in creating the final simplified form of an algebraic expression.
Coefficients
Coefficients are the numerical part of terms that include variables. They multiply the variable, giving scale to its contribution within an algebraic expression. For example, in the term \(5z\), the coefficient is 5, which implies the value of the variable \(z\) is multiplied by 5.
In the expression provided by the exercise, identifying and summing coefficients is a fundamental step in combining like terms.
\(5 + 10 + 2 = 17\),
giving us a single term \(17z\).
This process helps simplify the expression, making it easier to evaluate or work with further in problem-solving. Knowing how to identify and combine coefficients streamlines the solving of algebraic expressions.
In the expression provided by the exercise, identifying and summing coefficients is a fundamental step in combining like terms.
- For \(5z\), the coefficient is 5.
- For \(10z\), the coefficient is 10.
- For \(2z\), the coefficient is 2.
\(5 + 10 + 2 = 17\),
giving us a single term \(17z\).
This process helps simplify the expression, making it easier to evaluate or work with further in problem-solving. Knowing how to identify and combine coefficients streamlines the solving of algebraic expressions.
Other exercises in this chapter
Problem 76
$$ \text { In Exercises 73-76, rewrite the product in exponential form. } $$ $$ (u-v) \cdot(u-v) \cdot 8 \cdot 8 \cdot 8 \cdot(u-v) $$
View solution Problem 77
Give two interpretations of "the quotient of 5 and a number times 3 ." Explain why \(\frac{3 n}{5}\) is not a possible interpretation.
View solution Problem 77
In Exercises 77-80, evaluate the algebraic expression for the given values of the variable(s). Area of a Triangle \(\frac{1}{2} b h\) (a) \(b=3, h=5\) (b) \(b=2
View solution Problem 78
Give two interpretations of "the difference of 6 and a number divided by \(3 . "\) Explain why \(\frac{n-6}{3}\) is not a possible interpretation.
View solution