Problem 76
Question
Suppose \(L_{1}\) and \(L_{2}\) are disjoint (nonintersecting) nonparallel lines. Is it possible for a nonzero vector to be perpendicular to both \(L_{1}\) and \(L_{2} ?\) Give reasons for your answer.
Step-by-Step Solution
Verified Answer
No, a nonzero vector cannot be perpendicular to both nonparallel lines.
1Step 1: Understanding the Problem
We have two nonparallel, disjoint lines (they neither intersect nor overlap in direction), and we need to check if a nonzero vector can be perpendicular to both lines. A vector is perpendicular to a line if it forms a 90-degree angle with it.
2Step 2: Defining a Vector Perpendicular to a Line
To have a vector perpendicular to a line, it must be orthogonal to the directional vector of that line. Let's denote the directional vector of \( L_1 \) as \( \mathbf{a} \) and for \( L_2 \) as \( \mathbf{b} \). A vector \( \mathbf{v} \) is perpendicular to \( L_1 \) if \( \mathbf{v} \cdot \mathbf{a} = 0 \) and to \( L_2 \) if \( \mathbf{v} \cdot \mathbf{b} = 0 \).
3Step 3: Exploring the Perpendicular Condition
The conditions \( \mathbf{v} \cdot \mathbf{a} = 0 \) and \( \mathbf{v} \cdot \mathbf{b} = 0 \) imply that \( \mathbf{v} \) should be orthogonal to both \( \mathbf{a} \) and \( \mathbf{b} \). However, \( \mathbf{a} \) and \( \mathbf{b} \) are directions for nonparallel lines, indicating that they are linearly independent.
4Step 4: Solution by Linear Independence
Because \( \mathbf{a} \) and \( \mathbf{b} \) are linearly independent, the only vector \( \mathbf{v} \) that satisfies both perpendicular conditions \( \mathbf{v} \cdot \mathbf{a} = 0 \) and \( \mathbf{v} \cdot \mathbf{b} = 0 \) is the zero vector. But since zero is not a nonzero vector, it is not possible for a nonzero vector to be perpendicular to both \( L_1 \) and \( L_2 \).
Key Concepts
Linear IndependenceOrthogonalityDirectional Vectors
Linear Independence
In mathematics, two vectors are considered linearly independent if no linear combination of these vectors equals zero unless all coefficients are zero.
Simply put, you cannot express one vector as a multiple of the other.
Because of their independence, finding another vector that is simultaneously perpendicular to both is impossible, except for the zero vector.
Simply put, you cannot express one vector as a multiple of the other.
- If two vectors are nonparallel, like our lines' directional vectors \( \mathbf{a} \) and \( \mathbf{b} \), they are linearly independent.
- Therefore, they span a plane in space.
- This plane is where every linear combination of \( \mathbf{a} \) and \( \mathbf{b} \) lives.
Because of their independence, finding another vector that is simultaneously perpendicular to both is impossible, except for the zero vector.
Orthogonality
Orthogonality refers to vectors being at right angles to each other.
In mathematical terms, two vectors \( \mathbf{u} \) and \( \mathbf{v} \) are orthogonal if their dot product equals zero: \( \mathbf{u} \cdot \mathbf{v} = 0 \).
While these conditions restrict \( \mathbf{v} \) to lie in a plane orthogonal to each directional vector independently, the linear independence of \( \mathbf{a} \) and \( \mathbf{b} \) means their only shared orthogonal vector is the zero vector. This makes it impossible to have a nonzero vector that fulfills both conditions.
In mathematical terms, two vectors \( \mathbf{u} \) and \( \mathbf{v} \) are orthogonal if their dot product equals zero: \( \mathbf{u} \cdot \mathbf{v} = 0 \).
- For a vector to be perpendicular to a line, it must be orthogonal to the line's directional vector.
- In our exercise, a vector \( \mathbf{v} \) is required to be orthogonal to both \( \mathbf{a} \) and \( \mathbf{b} \).
While these conditions restrict \( \mathbf{v} \) to lie in a plane orthogonal to each directional vector independently, the linear independence of \( \mathbf{a} \) and \( \mathbf{b} \) means their only shared orthogonal vector is the zero vector. This makes it impossible to have a nonzero vector that fulfills both conditions.
Directional Vectors
Directional vectors define the direction of lines or planes in space.
In a three-dimensional space, a directional vector is like an arrow pointing out where a line goes.
They help us determine relationships like perpendicularity, crucial in proving the limitations set by linear independence and orthogonality.
In a three-dimensional space, a directional vector is like an arrow pointing out where a line goes.
- The directional vector of a line is used to calculate perpendicular vectors, those that meet the line at a right angle.
- In our scenario, \( \mathbf{a} \) and \( \mathbf{b} \) are directional vectors of nonparallel lines \( L_1 \) and \( L_2 \).
- Since the lines are nonparallel, their directions do not overlap.
They help us determine relationships like perpendicularity, crucial in proving the limitations set by linear independence and orthogonality.
Other exercises in this chapter
Problem 75
The graph of \((x / a)+(y / b)+(z / c)=1\) is a plane for any nonzero numbers \(a, b,\) and \(c .\) Which planes have an equation of this form?
View solution Problem 75
Find an equation for the set of points equidistant from the a. \(x y\) -plane and the \(y z\) -plane. b. \(x\) -axis and the \(y\) -axis.
View solution Problem 76
\(.\) Find all points that simultaneously lie 3 units from each of the points \((2,0,0),(0,2,0),\) and (0,0,2)
View solution Problem 74
Find an equation for the set of points equidistant from the \(y\) -axis and the plane \(z=6\)
View solution