Problem 76
Question
\(.\) Find all points that simultaneously lie 3 units from each of the points \((2,0,0),(0,2,0),\) and (0,0,2)
Step-by-Step Solution
Verified Answer
The point (1, 1, 1) is 3 units away from all given points.
1Step 1: Understand the given condition
The problem asks us to find points that are equidistant (3 units away) from the given three points: \((2,0,0)\), \((0,2,0)\), and \((0,0,2)\). This means we need to find the set of points \((x, y, z)\) that satisfy this distance condition for each of these reference points.
2Step 2: Use the distance formula for the first point
Using the distance formula, the distance between two points \((x_1, y_1, z_1)\) and \((x_2, y_2, z_2)\) is given by \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\). Apply this to the point \((2,0,0)\):\[\sqrt{(x - 2)^2 + (y - 0)^2 + (z - 0)^2} = 3.\] Solving this, we get:\[(x - 2)^2 + y^2 + z^2 = 9.\]
3Step 3: Use the distance formula for the second point
Similarly, apply the distance formula to the point \((0,2,0)\):\[\sqrt{(x - 0)^2 + (y - 2)^2 + (z - 0)^2} = 3.\] Solving this, we have:\[x^2 + (y - 2)^2 + z^2 = 9.\]
4Step 4: Use the distance formula for the third point
For the point \((0,0,2)\), use the distance formula:\[\sqrt{(x - 0)^2 + (y - 0)^2 + (z - 2)^2} = 3.\] Simplifying this, we find:\[x^2 + y^2 + (z - 2)^2 = 9.\]
5Step 5: Solve the system of equations
We have a system of three equations:1. \((x - 2)^2 + y^2 + z^2 = 9\),2. \(x^2 + (y - 2)^2 + z^2 = 9\),3. \(x^2 + y^2 + (z - 2)^2 = 9\).Solve these equations simultaneously to find the values of \(x\), \(y\), and \(z\). One feasible solution that satisfies all three equations is \(x = 1\), \(y = 1\), \(z = 1\).
6Step 6: Verify the solution
Plug \(x = 1\), \(y = 1\), and \(z = 1\) into each of the three equations to verify correctness:- For equation 1: \((1 - 2)^2 + 1^2 + 1^2 = 9\Rightarrow 1 + 1 + 1 = 3\).- For equation 2: \(1^2 + (1 - 2)^2 + 1^2 = 9\Rightarrow 1 + 1 + 1 = 3\).- For equation 3: \(1^2 + 1^2 + (1 - 2)^2 = 9\Rightarrow 1 + 1 + 1 = 3\).Since all equations hold true, \((1, 1, 1)\) is a correct solution.
Key Concepts
Distance FormulaSystem of Equations3D Coordinates
Distance Formula
The distance formula is a fundamental tool in analytic geometry. It helps us calculate the distance between any two points in a coordinate system. In 3D coordinates, this formula is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \]The formula is derived from the Pythagorean theorem, as distance in a 3D space forms a right triangle.
- The difference in the x-coordinates \((x_2 - x_1)\) is squared to highlight the distance on the x-axis.
- Similarly, differences in y and z-coordinates are squared to cover vertical and depth dimensions.
- Finding the square root of the sum of these squares gives the line's length connecting two points.
System of Equations
A system of equations involves multiple equations that share a common set of variables. Solving these systems means finding the values of these variables that satisfy all equations simultaneously. In three variables, these can be represented as:
- Equation 1: \((x - 2)^2 + y^2 + z^2 = 9\)
- Equation 2: \(x^2 + (y - 2)^2 + z^2 = 9\)
- Equation 3: \(x^2 + y^2 + (z - 2)^2 = 9\)
- Equate and sequentially solve the equations to discover common values for \(x, y,\) and \(z\).
- Verify these values with each equation to ensure accuracy. Any set of values that satisfy all equations is a solution.
3D Coordinates
3D coordinates specify locations in three-dimensional space using three values: \((x, y, z)\). Each of these values represents distance along respective axes in a spatial grid, creating a framework for solving geometry problems:
- The x-axis represents horizontal displacement, typically seen as left or right.
- The y-axis captures vertical displacement, indicating movement up or down.
- The z-axis measures depth, differentiating it from simple 2D problems by adding fore/aft movement.
Other exercises in this chapter
Problem 75
Find an equation for the set of points equidistant from the a. \(x y\) -plane and the \(y z\) -plane. b. \(x\) -axis and the \(y\) -axis.
View solution Problem 76
Suppose \(L_{1}\) and \(L_{2}\) are disjoint (nonintersecting) nonparallel lines. Is it possible for a nonzero vector to be perpendicular to both \(L_{1}\) and
View solution Problem 75
The graph of \((x / a)+(y / b)+(z / c)=1\) is a plane for any nonzero numbers \(a, b,\) and \(c .\) Which planes have an equation of this form?
View solution