Problem 76
Question
perform the indicated operations. Simplify the result, if possible. $$ \left(4-\frac{3}{x+2}\right)\left(1+\frac{5}{x-1}\right) $$
Step-by-Step Solution
Verified Answer
The result is \(\frac{4x^2+25x+28}{x^2+x-2}\)
1Step 1: Distribute the Terms
Multiply each term from the first parenthesis by each term from the second parenthesis like follows: \[ 4 * 1 + 4 * \frac{5}{{x-1}} - \frac{3}{{x+2}} * 1 - \frac{3}{{x+2}} * \frac{5}{{x-1}} \]
2Step 2: Simplify the expression
Write down the multiplication results: \[ 4 + \frac{20}{{x-1}} - \frac{3}{{x+2}} - \frac{15}{{(x+2)*(x-1)}} \] Now we need to find a common denominator for these terms to simplify the expression. A good choice is \((x-1)(x+2)\) which is the least common multiple of the denominators.
3Step 3: Simplify further
Rewrite the expression with common denominator: \[ \frac{4(x-1)(x+2) + 20(x+2) - 3(x-1) - 15}{(x-1)(x+2)} \]. After performing all the operations, we get: \[ = \frac{4x^2+8x + 20x + 40 - 3x + 3 - 15}{x^2+x-2} \]. Further simplifying brings to: \[ = \frac{4x^2+25x+28}{x^2+x-2} \]
Key Concepts
Distributive PropertyRational ExpressionsSimplifying Expressions
Distributive Property
The Distributive Property is a fundamental principle in algebra that helps simplify complex problems. It allows you to break down problems involving multiplication over addition or subtraction. Simply put, it lets you distribute a single term across the terms inside a parenthesis.
For the given problem, we apply the distributive property to multiply each term in one set of parentheses by each term in the other set. This is done as follows:
For the given problem, we apply the distributive property to multiply each term in one set of parentheses by each term in the other set. This is done as follows:
- Multiply 4 by 1 resulting in 4.
- Multiply 4 by \( \frac{5}{x-1} \) resulting in \( \frac{20}{x-1} \).
- Multiply \( -\frac{3}{x+2} \) by 1 resulting in \( -\frac{3}{x+2} \).
- Multiply \( -\frac{3}{x+2} \) by \( \frac{5}{x-1} \) resulting in \( -\frac{15}{(x+2)(x-1)} \).
Rational Expressions
Rational expressions are fractions that involve polynomials in the numerator, the denominator, or both. Dealing with rational expressions requires careful attention to the factors in both the numerator and the denominator.
In this exercise, after applying the distributive property, we are left with the expression:
In this exercise, after applying the distributive property, we are left with the expression:
- \( 4 + \frac{20}{x-1} - \frac{3}{x+2} - \frac{15}{(x+2)(x-1)} \)
Simplifying Expressions
Simplifying expressions is the process of reducing them to a more manageable form. After finding a common denominator for the rational expressions, we can then combine and simplify the equation.
The steps include:
The steps include:
- Multiply each term by the common denominator \((x-1)(x+2)\) to eliminate fraction parts.
- Combine like terms. This involves combining all similar terms from the expanded form.
- Expanded numerator: \[ 4(x-1)(x+2) + 20(x+2) - 3(x-1) - 15 \]
- \( \frac{4x^2 + 25x + 28}{x^2 + x - 2} \)
Other exercises in this chapter
Problem 75
State the name of the property illustrated. $$6+(-4)=(-4)+6$$
View solution Problem 76
Factor completely, or state that the polynomial is prime. $$9 x^{3}-9 x$$
View solution Problem 76
In Exercises 67–82, find each product. $$ \left(x^{2} y^{2}-5\right)^{2} $$
View solution Problem 76
Add or subtract terms whenever possible. $$ 6 \sqrt[5]{3}+2 \sqrt[5]{3} $$
View solution