Problem 76
Question
Add or subtract terms whenever possible. $$ 6 \sqrt[5]{3}+2 \sqrt[5]{3} $$
Step-by-Step Solution
Verified Answer
The simplified form of \( 6 \sqrt[5]{3} + 2 \sqrt[5]{3} \) is \( 8 \sqrt[5]{3} \).
1Step 1: Identify the Like Terms
First, identify the like terms in the expression. In this case, \( 6 \sqrt[5]{3} \) and \( 2 \sqrt[5]{3} \) are like terms because they have the same variable part which is \( \sqrt[5]{3} \).
2Step 2: Add/Subtract the Like Terms
Then add these like terms. When adding like terms, add just the coefficients. The coefficient of \( \sqrt[5]{3} \) in \( 6 \sqrt[5]{3} \) is 6 and in \( 2 \sqrt[5]{3} \) is 2. Adding 6 and 2 gives 8.
3Step 3: Write the Result
Finally, write down the result by attaching the common variable part to the result of the addition. So, \( 6 \sqrt[5]{3} + 2 \sqrt[5]{3} = 8 \sqrt[5]{3} \).
Key Concepts
CoefficientLike TermsAddition of Radicals
Coefficient
The concept of coefficients in mathematics may initially seem daunting, but it's actually quite straightforward. A coefficient is essentially the numeric part of any term, especially when working with expressions involving variables or radicals. For example, in the radical expression \( 6 \sqrt[5]{3} \), the coefficient is the number 6. It tells us how many "units" of the radical \( \sqrt[5]{3} \) we have.
In contexts involving radicals, the coefficient plays a crucial role in addition and subtraction. Suppose you wish to simplify an expression involving
Understanding coefficients is essential in simplifying radical expressions, as it allows you to combine terms efficiently without dealing with the complexity of the radicals themselves.
In contexts involving radicals, the coefficient plays a crucial role in addition and subtraction. Suppose you wish to simplify an expression involving
- \( 6 \sqrt[5]{3} \)
- \( 2 \sqrt[5]{3} \)
Understanding coefficients is essential in simplifying radical expressions, as it allows you to combine terms efficiently without dealing with the complexity of the radicals themselves.
Like Terms
"Like terms" is a fundamental concept in algebra that helps in simplifying expressions. In simpler terms, like terms are terms that have the same variables raised to the same power. For radicals, like terms must have the same radical part.
Taking the example from our original problem, consider:
Recognizing like terms is an essential skill for simplifying radicals. Only like terms can be added or subtracted directly. Once identified, you simply perform arithmetic on the coefficients while keeping the radical part unchanged.
Taking the example from our original problem, consider:
- \( 6 \sqrt[5]{3} \)
- \( 2 \sqrt[5]{3} \)
Recognizing like terms is an essential skill for simplifying radicals. Only like terms can be added or subtracted directly. Once identified, you simply perform arithmetic on the coefficients while keeping the radical part unchanged.
Addition of Radicals
Adding radicals follows rules similar to those for adding variables or numerical terms, but it also has unique considerations. For the addition to occur, radicals must be like terms, meaning their radicands (the numbers inside the radical) and their indices (the root power) must be identical.
Consider the expression:
\[ 6 \sqrt[5]{3} + 2 \sqrt[5]{3} = 8 \sqrt[5]{3} \]
However, if the radicals differ, such as \( \sqrt[3]{3} \) and \( \sqrt[5]{3} \), they cannot be added together directly. They are not like terms due to differing indices or radicands, and thus must remain separate in any simplified expression.
This rule ensures that the simple process of combining coefficients is not disrupted by differing radical parts.
Consider the expression:
- \( 6 \sqrt[5]{3} + 2 \sqrt[5]{3} \)
\[ 6 \sqrt[5]{3} + 2 \sqrt[5]{3} = 8 \sqrt[5]{3} \]
However, if the radicals differ, such as \( \sqrt[3]{3} \) and \( \sqrt[5]{3} \), they cannot be added together directly. They are not like terms due to differing indices or radicands, and thus must remain separate in any simplified expression.
This rule ensures that the simple process of combining coefficients is not disrupted by differing radical parts.
Other exercises in this chapter
Problem 76
perform the indicated operations. Simplify the result, if possible. $$ \left(4-\frac{3}{x+2}\right)\left(1+\frac{5}{x-1}\right) $$
View solution Problem 76
In Exercises 67–82, find each product. $$ \left(x^{2} y^{2}-5\right)^{2} $$
View solution Problem 76
Write each number in decimal notation without the use of exponents. $$ -7.00001 \times 10^{10} $$
View solution Problem 76
State the name of the property illustrated. $$11 \cdot(7+4)=11 \cdot 7+11 \cdot 4$$
View solution