Problem 76
Question
$$ a_{n}= \begin{cases}\frac{1}{n} & \text { for } n \text { odd } \\ n^{2} & \text { for } n \text { cven } \\ 1,4, \frac{1}{3}, 16, \frac{1}{5}, 36\end{cases} $$
Step-by-Step Solution
Verified Answer
The sequence alternates between \( \frac{1}{n} \) for odd \( n \) and \( n^2 \) for even \( n \).
1Step 1: Identifying Odd and Even Numbers
First, identify whether each number in the sequence corresponds to an odd or even value of \( n \). The sequence given is \( 1, 4, \frac{1}{3}, 16, \frac{1}{5}, 36 \). Here, 1, \( \frac{1}{3} \), and \( \frac{1}{5} \) should align with odd positions, and 4, 16, and 36 should align with even positions.
2Step 2: Mapping Sequence to Formula
Match each element to its corresponding formula based on the position:- **\( a_1 = \frac{1}{n} \) with \( n = 1 \) (odd), thus \( a_1 = 1 \).**- **\( a_2 = n^2 \) with \( n = 2 \) (even), thus \( a_2 = 4 \).**- **\( a_3 = \frac{1}{n} \) with \( n = 3 \) (odd), thus \( a_3 = \frac{1}{3} \).**- **\( a_4 = n^2 \) with \( n = 4 \) (even), thus \( a_4 = 16 \).**- **\( a_5 = \frac{1}{n} \) with \( n = 5 \) (odd), thus \( a_5 = \frac{1}{5} \).**- **\( a_6 = n^2 \) with \( n = 6 \) (even), thus \( a_6 = 36 \).**
Key Concepts
Odd and Even NumbersRecursive FormulasMathematical Sequences
Odd and Even Numbers
Odd and even numbers are an essential concept in algebra and mathematics as a whole. They are used to classify numbers based on their divisibility by 2.
- An even number is a number that is divisible by 2 without leaving a remainder. Examples of even numbers include 2, 4, 6, etc.
- An odd number, on the other hand, is a number that leaves a remainder of 1 when divided by 2. Examples of odd numbers include 1, 3, 5, etc.
Recursive Formulas
A recursive formula establishes how each term in a sequence is related to the previous terms. This connection allows us to find any term of the sequence if we know the preceding ones, or sometimes just the initial conditions. Recursive formulas are often used in sequences where relationships between terms are clearly defined. For instance, in our example problem, different expressions are used when the index \( n \) is either odd or even. This classification leads to two distinct types of formulas:
- For odd \( n \): The formula is given by \( a_n = \frac{1}{n} \).
- For even \( n \): The formula becomes \( a_n = n^2 \).
Mathematical Sequences
Mathematical sequences are ordered lists of numbers defined by a specific pattern or rule. They are fundamental in mathematics and are used to model a wide array of phenomena in different fields.In sequences, each number in the list is called a term. The position of the term in the sequence is referred to as its index, usually denoted as \( n \). When dealing with sequences, one of the primary tasks is to determine the nth term, based on some described formula or rule, just like the example problem. The example shows a mixed sequence that uses one rule for odd-indexed terms and another for even-indexed terms:
- For odd indices (1, 3, 5,...): Terms are calculated using the formula \( a_n = \frac{1}{n} \).
- For even indices (2, 4, 6,...): The formula \( a_n = n^2 \) is used.
Other exercises in this chapter
Problem 74
Explain how one can tell that a particular sequence is an arithmetic sequence.
View solution Problem 75
1–8, Express the given inequality in interval notation and sketch a graph of the interval. x>1
View solution Problem 77
x \geq-1
View solution Problem 78
$$ I_{n}= \begin{cases}5 n-1 & \text { for } n \text { a multiple of } 3 \\ 2 n & \text { otherwise }\end{cases} $$
View solution