Problem 75
Question
Solve by writing a sum of signed numbers and adding. The temperature at 8: 00 A.M. was \(-7^{\circ} \mathrm{F}\). By noon it had risen \(15^{\circ} \mathrm{F},\) but by \(4: 00 \mathrm{P} .\). \(\mathrm{M} .\) it had fallen \(5^{\circ} \mathrm{F}\). What was the temperature at 4: 00 P.M.?
Step-by-Step Solution
Verified Answer
The temperature at 4:00 P.M. was \(3^{\circ} \mathrm{F}\).
1Step 1: Identify Initial Temperature
The initial temperature given is \(-7^{\circ} \mathrm{F}\). This is the temperature at 8:00 A.M.
2Step 2: Identify Temperature change by noon
The temperature increased by \(15^{\circ} \mathrm{F}\) by noon. When temperature rises, we add this change to the initial temperature. This gives us the temperature at noon.
3Step 3: Calculate Temperature at noon
To calculate the temperature at noon, we add the initial temperature to the increase in temperature. This should be \(-7^{\circ} \mathrm{F}\) (initial temperature) + \(15^{\circ} \mathrm{F}\) (increase in temperature) = \(8^{\circ} \mathrm{F}\).
4Step 4: Identify Temperature change by 4:00 P.M.
By 4:00 P.M., the temperature fell by \(5^{\circ} \mathrm{F}\). When temperature falls, we subtract this change from the current temperature.
5Step 5: Calculate Temperature at 4:00 P.M.
To calculate the temperature at 4:00 P.M., we subtract the decrease in temperature from the temperature at noon. This should be \(8^{\circ} \mathrm{F}\) (temperature at noon) - \(5^{\circ} \mathrm{F}\) (decrease in temperature) = \(3^{\circ} \mathrm{F}\). This is the temperature at 4:00 P.M.
Key Concepts
Addition of Signed NumbersTemperature ChangeAlgebraic Reasoning
Addition of Signed Numbers
Adding signed numbers is a fundamental skill in algebra. It involves understanding how to manage both positive and negative numbers. When you add numbers with different signs, you subtract the smaller number from the larger number and keep the sign of the larger. For instance, if you start with \(-7\, \text{°F}\) and add \(15\, \text{°F}\), you find the difference, which is \(8\, \text{°F}\), and keep the positive sign because 15 is greater than 7.
Conversely, when both numbers are negative or positive, you simply add their absolute values and keep the common sign. Understanding this concept is crucial when solving real-world problems that involve changes, such as temperature fluctuations or financial calculations.
Let's look at an example to solidify this:
Conversely, when both numbers are negative or positive, you simply add their absolute values and keep the common sign. Understanding this concept is crucial when solving real-world problems that involve changes, such as temperature fluctuations or financial calculations.
Let's look at an example to solidify this:
- Start with \(-7\, \text{°F}\)
- Add \(15\, \text{°F}\) (increase)
- Result: \(8\, \text{°F}\)
Temperature Change
Temperature changes are a prevalent example of how signed numbers operate in real life. Such changes often involve increases (positive change) and decreases (negative change).
Consider a day that starts at \(-7\, \text{°F}\):
Consider a day that starts at \(-7\, \text{°F}\):
- The temperature rises by \(15\, \text{°F}\), leading us to add this value, resulting in \(8\, \text{°F}\) by noon.
- Later, it drops by \(5\, \text{°F}\). This drop means subtracting, resulting in \(3\, \text{°F}\) by 4:00 P.M.
Algebraic Reasoning
Algebraic reasoning involves using algebraic concepts to solve problems. In the context of temperature change, it's important to identify the starting point, track each change, and apply operations accordingly. This requires problem-solving skills and critical thinking.
Consider this step-by-step approach:
Consider this step-by-step approach:
- Identify the initial temperature (starting point).
- Note every temperature change in sequence.
- Use addition or subtraction to calculate new temperatures.
Other exercises in this chapter
Problem 74
Write each sentence as an equation. Let the variable \(x\) represent the number. Four times a number is equal to 25 decreased by the number.
View solution Problem 74
Perform the indicated operation. Where possible, reduce the answer to its lowest terms. $$\frac{13}{18}-\frac{5}{18}$$
View solution Problem 75
In Exercises 47-76, perform the indicated division or state that the expression is undefined. $$ 6 \div\left(-\frac{2}{5}\right) $$
View solution Problem 75
Evaluate each algebraic expression for the given value of the variable. $$3 x^{2}-8 x ; x=-2$$
View solution