Problem 74
Question
Exer. 73-76: Make the trigonometric substitution $$ x=a \sec \theta \text { for } 0<\theta<\pi / 2 \text { and } a>0 \text {. } $$ Simplify the resulting expression. $$ \frac{1}{x^{2} \sqrt{x^{2}-a^{2}}} $$
Step-by-Step Solution
Verified Answer
\(\frac{\cos^3 \theta}{a^3 \sin \theta}\)
1Step 1: Substitute for x
Given the substitution \( x = a \sec\theta \), replace \( x \) in the expression with \( a \sec\theta \). The new expression becomes:\[ \frac{1}{(a \sec \theta)^2 \sqrt{(a \sec \theta)^2 - a^2}} \]
2Step 2: Simplify the Expression
First, simplify \( (a \sec \theta)^2 \):\[ (a \sec \theta)^2 = a^2 \sec^2 \theta \]Substitute back into the expression:\[ \frac{1}{a^2 \sec^2 \theta \sqrt{a^2 \sec^2 \theta - a^2}} \]
3Step 3: Factor and Simplify the Square Root
Factor out \( a^2 \) from the square root:\[ \sqrt{a^2 (\sec^2 \theta - 1)} = a \sqrt{\sec^2 \theta - 1} \]Recognize that \( \sec^2 \theta - 1 = \tan^2 \theta \), so:\[ a \sqrt{\sec^2 \theta - 1} = a \tan \theta \]Now, substitute back into the expression:\[ \frac{1}{a^2 \sec^2 \theta \cdot a \tan \theta} \]
4Step 4: Final Simplification
The expression further simplifies by canceling terms:\[ \frac{1}{a^3 \sec^2 \theta \tan \theta} \]Express \( \sec \theta \) and \( \tan \theta \) in terms of sine and cosine to further simplify:\[ \sec \theta = \frac{1}{\cos \theta}, \quad \tan \theta = \frac{\sin \theta}{\cos \theta} \]Thus:\[ \frac{1}{a^3 \left( \frac{1}{\cos^2 \theta} \right) \left( \frac{\sin \theta}{\cos \theta} \right)} = \frac{\cos^3 \theta}{a^3 \sin \theta} \]
5Step 5: Simplified Result
The expression has been simplified to:\[ \frac{\cos^3 \theta}{a^3 \sin \theta} \]
Key Concepts
Trigonometric IdentitiesSimplification TechniquesCalculus Integration Methods
Trigonometric Identities
Trigonometric identities are mathematical tools that relate the angles and sides of triangles. They are especially useful when simplifying expressions or solving equations involving trigonometric functions. In our exercise, the identity for the secant function is key. It is given by:
- \[ \sec \theta = \frac{1}{\cos \theta} \]
- The identity relating secant and tangent is:\[ \sec^2 \theta - 1 = \tan^2 \theta \]
Simplification Techniques
Simplifying expressions is an essential skill in mathematics, especially in calculus, where expressions can become complex. The primary goal is to reduce an expression to its most basic form. Let's go through the simplifications in our exercise.Initially, after substituting \(x = a \sec \theta\), the expression became more complex. However, seeing \(a^2(\sec^2 \theta - 1)\) inside the square root allows us to recognize a chance to simplify. By factoring out \(a^2\), and using the trigonometric identity \(\sec^2 \theta - 1 = \tan^2 \theta\), we transform the expression to involve \(\tan \theta\), a simpler function.The fraction further simplifies by substituting trigonometric functions with their definitions in terms of sine and cosine:
- \(\sec \theta = \frac{1}{\cos \theta}\)
- \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)
Calculus Integration Methods
Integrating functions, especially those involving square roots and trigonometric expressions, can be challenging. One effective approach is using trigonometric substitution, which simplifies the integral by transforming variables. In this exercise, we used the substitution \(x = a \sec \theta\) to handle a term with \(\sqrt{x^2-a^2}\).Trigonometric substitution is particularly useful when:
- You encounter expressions of the form \(\sqrt{x^2 - a^2}\).
- Substituting with a trigonometric function can lead to simpler integrals that are easier to integrate.
Other exercises in this chapter
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Exer. 73-76: Make the trigonometric substitution $$ x=a \sec \theta \text { for } 00 \text {. } $$ Simplify the resulting expression. $$ x^{3} \sqrt{x^{2}-a^{2}
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