Problem 73
Question
Find the indicated value for each given rational expression, if possible. $$W(b)=\frac{4 b^{3}-1}{b^{2}-b-6}, W(-2)$$
Step-by-Step Solution
Verified Answer
The expression is undefined at \( b = -2 \).
1Step 1: Understand the Expression
The given rational expression is \( W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \). We need to find \( W(-2) \).
2Step 2: Substitute the Value
Substitute \( b = -2 \) into the expression: \[ W(-2) = \frac{4(-2)^3 - 1}{(-2)^2 - (-2) - 6} \]
3Step 3: Simplify the Numerator
Calculate the numerator:\[ 4(-2)^3 - 1 = 4(-8) - 1 = -32 - 1 = -33 \]
4Step 4: Simplify the Denominator
Calculate the denominator:\[ (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 \]
5Step 5: Check for Undefined Expression
Since the denominator is 0, the expression is undefined.This means \( W(-2) \) does not exist.
Key Concepts
Rational FunctionsUndefined ExpressionsPolynomial Simplification
Rational Functions
A rational function is expressed as the ratio of two polynomials. The general form is: \[ f(x) = \frac{P(x)}{Q(x)} \] Here, \(P(x)\) and \(Q(x)\) are polynomials and \(Q(x)\) is not zero. In our exercise, the rational function given is \( W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \). Rational functions are useful in many applications including engineering and science. They can represent real-world scenarios where one quantity is dependent on another. For example, speed or concentration analysis. The key to understanding rational functions is to manage both the numerator and the denominator effectively. Let’s unpack further to understand more about concepts like undefined expressions and polynomial simplification. By understanding these concepts well, you can master rational functions!
Undefined Expressions
An expression in mathematics becomes undefined when it leads to an impossible or undefined operation. This typically happens when the denominator of a fraction equals zero. As seen in our exercise:
\[ W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \] We substituted \( b = -2 \):
\[ W(-2) = \frac{4(-2)^3 - 1}{(-2)^2 - (-2) - 6} \] By simplifying the denominator:
\[ (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 \] Our denominator is zero, making \( W(-2) \) undefined.
An undefined expression occurs whenever dividing by zero, as division by zero has no meaning in conventional arithmetic. Thus, solutions to rational expressions must always confirm that the denominator is not zero at the evaluated point.
\[ W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \] We substituted \( b = -2 \):
\[ W(-2) = \frac{4(-2)^3 - 1}{(-2)^2 - (-2) - 6} \] By simplifying the denominator:
\[ (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 \] Our denominator is zero, making \( W(-2) \) undefined.
An undefined expression occurs whenever dividing by zero, as division by zero has no meaning in conventional arithmetic. Thus, solutions to rational expressions must always confirm that the denominator is not zero at the evaluated point.
Polynomial Simplification
Simplifying polynomials involves combining like terms and factoring where possible. This is crucial when working with rational functions to make expressions easier to evaluate. For example, in \( W(b) \):
\[ W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \] The steps for solving include:
Numerator: \[ 4(-2)^3 - 1 = 4(-8) - 1 = -32 - 1 = -33 \] Denominator: \[ (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 \] Factors and simplification are often used in polynomial simplification. Factoring can further break down polynomials to reveal roots and zeros, and aid in simplifying rational expressions.
Polynomial simplification is foundational in calculus and algebra, forming the basis for solving more complex mathematical problems.
\[ W(b) = \frac{4b^3 - 1}{b^2 - b - 6} \] The steps for solving include:
- Understanding the function
- Substituting values into the function
- Simplifying the numerator and the denominator
Numerator: \[ 4(-2)^3 - 1 = 4(-8) - 1 = -32 - 1 = -33 \] Denominator: \[ (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 \] Factors and simplification are often used in polynomial simplification. Factoring can further break down polynomials to reveal roots and zeros, and aid in simplifying rational expressions.
Polynomial simplification is foundational in calculus and algebra, forming the basis for solving more complex mathematical problems.
Other exercises in this chapter
Problem 73
Perform the indicated operations. $$\frac{\left(a^{2} b^{3} c\right)^{2}}{\left(-2 a b^{2} c\right)^{3}} \cdot \frac{\left(a^{3} b^{2} c\right)^{3}}{(a b c)^{4}
View solution Problem 73
Work with a group to simplify the complex fraction. For what values of \(x\) is the complex fraction undefined? $$\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{x}}}
View solution Problem 74
Either solve the given equation or perform the indicated operation \((s),\) whichever is appropriate. $$\frac{1}{2 x}-\frac{5}{3 x}+\frac{1}{4}$$
View solution Problem 74
Perform the indicated operations. $$\frac{\left(-w y^{2}\right)^{3}}{3 w^{2} y} \cdot \frac{(2 w y)^{2}}{4 w y^{3}}$$
View solution