Problem 73
Question
Determine whether the function is even, odd, or neither. \(f(x)=x^{2} \sin x\)
Step-by-Step Solution
Verified Answer
The function is odd.
1Step 1: Understand the Definitions
A function is **even** if \(f(-x) = f(x)\) for all \(x\). It is **odd** if \(f(-x) = -f(x)\) for all \(x\). If neither of these conditions holds, the function is neither even nor odd.
2Step 2: Calculate f(-x)
Given \(f(x) = x^2 \sin x\), let's find \(f(-x)\):\[ f(-x) = (-x)^2 \sin(-x) = x^2 (-\sin x) = -x^2 \sin x \]
3Step 3: Compare f(x) and f(-x)
We have \(f(x) = x^2 \sin x\) and \(f(-x) = -x^2 \sin x\). Comparing these, we check:- \(f(-x) = f(x)\) does not hold since \(-x^2 \sin x eq x^2 \sin x\).- \(f(-x) = -f(x)\) does hold since \(-x^2 \sin x = -(x^2 \sin x)\).
4Step 4: Conclusion
Since \(f(-x) = -f(x)\) holds for all \(x\), the function \(f(x) = x^2 \sin x\) is an **odd** function.
Key Concepts
Trigonometric FunctionsFunction SymmetryAlgebraic Functions
Trigonometric Functions
Trigonometric functions are a fundamental part of mathematics, especially in the realm of calculus and geometry. These functions include sine, cosine, and tangent, along with their reciprocals, cosecant, secant, and cotangent. In the given exercise, the function includes the sine function, denoted as \( \sin x \).
- The sine function \( \sin x \) is periodic with a period of \( 2\pi \), meaning it repeats its values every \( 2\pi \) units.
- It is an odd function, which means that \( \sin(-x) = -\sin x \).
- This property of oddness is crucial in exercises where we determine the symmetry of composite functions that include \( \sin x \).
Function Symmetry
Function symmetry helps us determine whether a function is even, odd, or neither. This understanding can simplify calculations and graphing.
Understanding function symmetry not only aids in diagnosing function types but also supports graphing techniques and integration practices, as certain symmetrical properties can simplify processes.
- An even function has reflective symmetry about the y-axis, and it satisfies the condition that \( f(-x) = f(x) \).
- An odd function has rotational symmetry around the origin. For odd functions, \( f(-x) = -f(x) \) must hold.
Understanding function symmetry not only aids in diagnosing function types but also supports graphing techniques and integration practices, as certain symmetrical properties can simplify processes.
Algebraic Functions
Algebraic functions are constructed using polynomials, roots, and ratios of these expressions. These functions frequently appear in algebra and calculus.
- In our exercise, \( x^2 \) represents a simple polynomial, which is an algebraic function. It's utilized in combination with a trigonometric function.
- Algebraic functions like \( x^2 \) have straightforward even properties, evident in \( f(x) \) because \( x^2 \) does not change when \( x \) is replaced with \(-x\).
- The interaction between algebraic and trigonometric functions can adjust or completely change the symmetry property of the function.
Other exercises in this chapter
Problem 72
Find the values of the trigonometric functions of \(t\) from the given information. \(\tan t=-4, \quad \csc t>0\)
View solution Problem 72
\(71-74\). Find all solutions of the equation that lie in the interval \([0, \pi]\) . State each answer correct to two decimal places. $$ \tan x=2 $$
View solution Problem 73
\(71-74\). Find all solutions of the equation that lie in the interval \([0, \pi]\) . State each answer correct to two decimal places. $$ \csc x=3 $$
View solution Problem 74
Determine whether the function is even, odd, or neither. \(f(x)=x^{2} \cos 2 x\)
View solution