Problem 72
Question
\(71-74\). Find all solutions of the equation that lie in the interval \([0, \pi]\) . State each answer correct to two decimal places. $$ \tan x=2 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = 1.11 \).
1Step 1: Solve the Basic Trigonometric Equation
We begin by solving the equation \( \tan x = 2 \). To find \( x \), we take the arctangent of both sides: \( x = \tan^{-1}(2) \). Using a calculator, \( x \approx 1.1071 \) radians.
2Step 2: Determine the General Solution for Tangent
The general solution for the tangent function is given by \( x = \tan^{-1}(2) + n\pi \), where \( n \) is any integer. This accounts for the periodic nature of the tangent function, which has a period of \( \pi \).
3Step 3: Find Solutions within the Given Interval
We need solutions in the interval \([0, \pi]\). Substituting \( n = 0 \), we get \( x \approx 1.1071 \). Substituting \( n = 1 \), we get \( x \approx 1.1071 + \pi \approx 4.2487 \), which is beyond the interval. Thus, only \( x \approx 1.1071 \) is within \([0, \pi]\).
4Step 4: Round the Solution to Two Decimal Places
Rounding the value found in the previous step to two decimal places, we find the solution \( x \approx 1.11 \).
Key Concepts
Tangent FunctionInverse Trigonometric FunctionsGeneral Solution for Tangent
Tangent Function
The tangent function is a fundamental trigonometric function that relates a right triangle's opposite side to its adjacent side in a given angle. Mathematically, it is expressed as \( \tan(x) = \frac{\text{opposite}}{\text{adjacent}} \), where \( x \) is an angle in radians or degrees.
The tangent function has some unique properties:
The tangent function has some unique properties:
- It is periodic, repeating every \( \pi \) radians (or 180 degrees).
- Unlike sine and cosine, tangent does not have a maximum or minimum limit; it ranges from \(-\infty\) to \(+\infty\).
- The function has vertical asymptotes at every odd multiple of \( \frac{\pi}{2} \), where it is undefined.
Inverse Trigonometric Functions
Inverse trigonometric functions allow us to find the angle when the trigonometric value is known. For tangent, this inverse is denoted as \( \tan^{-1}(x) \) or \( \arctan(x) \).
If you know the value of \( \tan(x) \) and want to find \( x \), you use the inverse tangent function. It's like the reverse operation of tangent. For example, if \( \tan(x) = 2 \), then \( x = \tan^{-1}(2) \).
Inverse trigonometric functions have their domains and ranges:
If you know the value of \( \tan(x) \) and want to find \( x \), you use the inverse tangent function. It's like the reverse operation of tangent. For example, if \( \tan(x) = 2 \), then \( x = \tan^{-1}(2) \).
Inverse trigonometric functions have their domains and ranges:
- The domain of \( \tan^{-1}(x) \) is all real numbers \(( -\infty, \infty )\).
- The range for \( \tan^{-1}(x) \) is \(( -\frac{\pi}{2}, \frac{\pi}{2} )\). This means you will get an angle in this specific interval.
General Solution for Tangent
The general solution of a trigonometric equation accounts for the periodic nature of trigonometric functions. For the tangent function, this is necessary due to its periodicity.
When we solve \( \tan(x) = k \) and find \( x = \tan^{-1}(k) \), the general solution incorporates the periodicity of \( \pi \). It is expressed as \( x = \tan^{-1}(k) + n\pi \), where \( n \) is any integer.
This general form illustrates why multiple solutions exist, each differing by a full cycle of \( \pi \).
The concept of the general solution:
When we solve \( \tan(x) = k \) and find \( x = \tan^{-1}(k) \), the general solution incorporates the periodicity of \( \pi \). It is expressed as \( x = \tan^{-1}(k) + n\pi \), where \( n \) is any integer.
This general form illustrates why multiple solutions exist, each differing by a full cycle of \( \pi \).
The concept of the general solution:
- Accounts for all possible angles \( x \) for which the equation holds true.
- Defines a complete set of solutions by utilizing tangent's periodicity.
- Is critical in scenarios where solutions must be within specified intervals.
Other exercises in this chapter
Problem 71
\(71-74\). Find all solutions of the equation that lie in the interval \([0, \pi]\) . State each answer correct to two decimal places. $$ \cos x=0.4 $$
View solution Problem 72
Find the values of the trigonometric functions of \(t\) from the given information. \(\tan t=-4, \quad \csc t>0\)
View solution Problem 73
Determine whether the function is even, odd, or neither. \(f(x)=x^{2} \sin x\)
View solution Problem 73
\(71-74\). Find all solutions of the equation that lie in the interval \([0, \pi]\) . State each answer correct to two decimal places. $$ \csc x=3 $$
View solution