Problem 70
Question
Use intercepts to graph the each equation. $$3 x+5 y+15-0$$
Step-by-Step Solution
Verified Answer
The x-intercept of the equation is (-5,0), the y-intercept is (0,-3). Plotting these two points and drawing a line through them provides the graph of the equation.
1Step 1: Identify the x-intercept
To find the x-intercept, set y to 0 in the equation and solve for x. Using the equation \(3x + 5 * 0 + 15 = 0\), simplifies to \(3x + 15 = 0\). Solving for x results in \(x = -15/3 = -5\). So, the x-intercept is at (-5,0).
2Step 2: Identify the y-intercept
To find the y-intercept, set x to 0 in the equation and solve for y. Using the equation \(3 * 0 + 5y + 15 = 0\), simplifies to \(5y + 15 = 0\). Solving for y, results in \(y = -15/5 = -3\). So, the y-intercept is at (0,-3).
3Step 3: Graph the line
Plot the identified intercepts (-5,0) and (0,-3) on a graph. Draw a line passing through these two points. The line represents the graph of the equation \(3x + 5y + 15 = 0\).
Key Concepts
x-intercepty-interceptcoordinate planeplotting points
x-intercept
The x-intercept of a linear equation is the point where the graph of the equation crosses the x-axis. This means that at the x-intercept, the value of y is always 0.
To find the x-intercept, you replace y with 0 in the equation and solve for x. For example, if we have the equation \(3x + 5y + 15 = 0\), to find the x-intercept, we set \(y = 0\) which simplifies the equation to \(3x + 15 = 0\). Solving this equation leads to the calculation \(x = -\frac{15}{3} = -5\).
Thus, the x-intercept is at the point \((-5, 0)\). Knowing this point is crucial as it helps you graph the line by giving you a specific location where the line interacts with the x-axis.
To find the x-intercept, you replace y with 0 in the equation and solve for x. For example, if we have the equation \(3x + 5y + 15 = 0\), to find the x-intercept, we set \(y = 0\) which simplifies the equation to \(3x + 15 = 0\). Solving this equation leads to the calculation \(x = -\frac{15}{3} = -5\).
Thus, the x-intercept is at the point \((-5, 0)\). Knowing this point is crucial as it helps you graph the line by giving you a specific location where the line interacts with the x-axis.
- Remember: At the x-intercept, \(y = 0\)
- Solve for x by substituting \(y = 0\) into your equation
- This process locates the point \((x, 0)\) on the x-axis
y-intercept
The y-intercept is the point where the graph of a linear equation crosses the y-axis, where the value of x is always 0.
To find the y-intercept, set x to 0 and solve for y. Using the same example equation, \(3x + 5y + 15 = 0\), setting \(x = 0\) leads to the equation \(5y + 15 = 0\). Solving for y results in \(y = -\frac{15}{5} = -3\).
This gives us the y-intercept at \((0, -3)\). The y-intercept provides a clear point where the line intersects the y-axis, which is essential for graphing the equation as it gives an additional accurate point.
To find the y-intercept, set x to 0 and solve for y. Using the same example equation, \(3x + 5y + 15 = 0\), setting \(x = 0\) leads to the equation \(5y + 15 = 0\). Solving for y results in \(y = -\frac{15}{5} = -3\).
This gives us the y-intercept at \((0, -3)\). The y-intercept provides a clear point where the line intersects the y-axis, which is essential for graphing the equation as it gives an additional accurate point.
- At the y-intercept, \(x = 0\)
- Solve the equation by substituting \(x = 0\)
- Find the point \((0, y)\) on the y-axis
coordinate plane
The coordinate plane is a two-dimensional surface that allows us to locate points using pairs of numbers, known as coordinates. It consists of a horizontal axis, typically called the x-axis, and a vertical axis, known as the y-axis.
Each point on the plane is described by an ordered pair \((x, y)\), where x indicates the horizontal position and y the vertical position. Understanding the coordinate plane is fundamental for graphing any linear equation or understanding the geometrical representation of algebraic expressions.
Each point on the plane is described by an ordered pair \((x, y)\), where x indicates the horizontal position and y the vertical position. Understanding the coordinate plane is fundamental for graphing any linear equation or understanding the geometrical representation of algebraic expressions.
- The x-axis runs horizontally, left to right
- The y-axis runs vertically, top to bottom
- The point \((0, 0)\) is known as the origin
plotting points
Plotting points involves marking the location of coordinates on the coordinate plane. This is an essential initial step when graphing a line from a linear equation. By identifying key points such as the x-intercept and y-intercept, you lay down the foundation for drawing the linear graph accurately.
When plotting points, it's crucial to understand their coordinates. For instance, the points \((-5, 0)\) and \((0, -3)\) tell you exactly where to place them on the x-axis and y-axis respectively. Each coordinate pair gives a specific position on the grid where x and y meet.
When plotting points, it's crucial to understand their coordinates. For instance, the points \((-5, 0)\) and \((0, -3)\) tell you exactly where to place them on the x-axis and y-axis respectively. Each coordinate pair gives a specific position on the grid where x and y meet.
- Ensure accuracy by checking both x and y values
- Mark each point carefully on the plane
- Use several points for clear and precise graph representation
Other exercises in this chapter
Problem 70
Find a. \((f \circ g)(x) \qquad\) b. the domain of \(f \circ g\) $$f(x)=\frac{x}{x+5}, g(x)=\frac{6}{x}$$
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Begin by graphing the square root function, \(f(x)=\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$g(x)=\sqrt{x+1}$$
View solution Problem 71
Describe how to find the inverse of a one-to-one function.
View solution Problem 71
find and simplify the difference quotient $$ \frac{f(x+h)-f(x)}{h}, h \neq 0 $$ for the given function. $$ f(x)=6 $$
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