Problem 70
Question
Begin by graphing the square root function, \(f(x)=\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$g(x)=\sqrt{x+1}$$
Step-by-Step Solution
Verified Answer
The graph of \(g(x)=\sqrt{x+1}\) is the graph of the basic square root function \(f(x)=\sqrt{x}\) shifted to the left by 1 unit.
1Step 1: Graph the basic square root function
Start by graphing the basic square root function, \(f(x)=\sqrt{x}\). This function starts from the origin (0,0) and then extends towards the positive x direction.
2Step 2: Understand the transformation
The transformation applied here to graph \(g(x)\) from \(f(x)\) is \(x \to x+1\), which symbolize a horizontal shift. A positive value in the transformation \(x \to x+1\) represents a shift to the left.
3Step 3: Apply the transformation and graph the given function
Now, apply the horizontal shift to the graph of \(f(x)\). This means shifting each point of \(f(x)\) to the left by 1 unit. Doing this will give you the graph of the given function \(g(x)=\sqrt{x+1}\).
Other exercises in this chapter
Problem 70
find and simplify the difference quotient $$ \frac{f(x+h)-f(x)}{h}, h \neq 0 $$ for the given function. $$ f(x)=-3 x^{2}+x-1 $$
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Find a. \((f \circ g)(x) \qquad\) b. the domain of \(f \circ g\) $$f(x)=\frac{x}{x+5}, g(x)=\frac{6}{x}$$
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Use intercepts to graph the each equation. $$3 x+5 y+15-0$$
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Describe how to find the inverse of a one-to-one function.
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