Problem 7
Question
Decompose the functions by finding functions \(f(x)\) and \(g(x)\), \(f(x) \neq x\) and \(g(x) \neq x\), such that \(h(x)=f(g(x))\). $$ h(x)=\frac{1}{x^{2}+4} $$
Step-by-Step Solution
Verified Answer
The function \(h(x) = \frac{1}{x^{2}+4}\) can be decomposed into two functions, where \(f(x) = \frac{1}{x}\) and \(g(x) = x^{2}+4\).
1Step 1: Understanding Function Composition
Function composition is a method of combining existing functions to create new functions. In the problem, it outlines the composition as \(h(x) = f(g(x))\), where \(f(x)\) and \(g(x)\) are the constituent functions of \(h(x)\).
2Step 2: Identify the functions
identify the inner function \(g(x)\) and the outer function \(f(x)\) in the given function \(h(x)\). By looking at \(h(x) = \frac{1}{x^{2}+4}\), it's seen that \(x^{2}+4\) is inside the fraction that has composition of functions. Hence, select \(g(x) = x^{2}+4\). Now to determine \(f(x)\), take \(g(x)\) and substitute into \(h(x)\) to get \(f(g(x))\). So, \(f(x) = \frac{1}{x}\).
3Step 3: Verify the function decomposition
To make sure the decomposition is correct, substitute \(g(x)\) into \(f(x)\) and the result should be the original function \(h(x)\). Thus, \(f(g(x)) = \frac{1}{x^{2}+4}\), and this matches the given function \(h(x)\).
Key Concepts
Function DecompositionInner FunctionOuter FunctionComposite Function
Function Decomposition
Function decomposition involves breaking down a complicated function into simpler constituent functions. This is a fantastic way to simplify the process of understanding and manipulating functions. In the given problem, we have the function \[ h(x) = \frac{1}{x^{2}+4} \]which we need to decompose into two functions: \(f(x)\) and \(g(x)\). These functions are combined through composition to form \(h(x)\).
Decomposing functions can be thought of like peeling an onion. Each layer you peel back helps you to understand the bigger picture. The goal is to identify two functions where \(h(x) = f(g(x))\), ensuring that neither function is just \(x\) itself, otherwise decomposition wouldn't be meaningful. By breaking \(h(x)\) down into the simpler functions \(f\) and \(g\), it helps us to understand how the function is operating and might make solving further problems with it easier.
Decomposing functions can be thought of like peeling an onion. Each layer you peel back helps you to understand the bigger picture. The goal is to identify two functions where \(h(x) = f(g(x))\), ensuring that neither function is just \(x\) itself, otherwise decomposition wouldn't be meaningful. By breaking \(h(x)\) down into the simpler functions \(f\) and \(g\), it helps us to understand how the function is operating and might make solving further problems with it easier.
Inner Function
In the context of function decomposition, the inner function is the part of the composite function that serves as the input to another function. For our example, let's examine \[h(x) = \frac{1}{x^{2}+4} \].
What happens inside the main operation? That would be the expression \(x^{2} + 4\). This expression is encapsulated within the larger structure of the function, making it our inner function, denoted as \(g(x)\).
Choose
What happens inside the main operation? That would be the expression \(x^{2} + 4\). This expression is encapsulated within the larger structure of the function, making it our inner function, denoted as \(g(x)\).
Choose
- \(g(x) = x^{2} + 4\)
Outer Function
The outer function encapsulates or encloses the inner function in a composition. It determines how the inner function's result will be used and processed. In simpler terms, it acts as an overarching structure that governs the whole process.
For the function \[ h(x) = \frac{1}{x^{2}+4} \], the result of \(g(x) = x^{2}+4\) becomes the argument for \(f(x)\). In our decomposition, the goal is to find \(f(x)\). Since \(g(x)\) will be replaced into \(f\),
For the function \[ h(x) = \frac{1}{x^{2}+4} \], the result of \(g(x) = x^{2}+4\) becomes the argument for \(f(x)\). In our decomposition, the goal is to find \(f(x)\). Since \(g(x)\) will be replaced into \(f\),
- \(f(x) = \frac{1}{x}\)
Composite Function
A composite function emerges when you apply one function to the result of another function. It blends the actions of two functions into one streamlined operation, simplifying complex problems into manageable steps. This is conveyed through the notation \((f \circ g)(x)\) or \(f(g(x))\).
In our specific case, \[ h(x) = f(g(x)) = \frac{1}{x^{2}+4} \],we see that the composite function is actually created by using \(g(x) = x^{2}+4\) within \(f(x) = \frac{1}{x}\).
In our specific case, \[ h(x) = f(g(x)) = \frac{1}{x^{2}+4} \],we see that the composite function is actually created by using \(g(x) = x^{2}+4\) within \(f(x) = \frac{1}{x}\).
- The beauty of composite functions lies in breaking down a complex task into simpler parts.
- Each function is responsible for its own piece of the puzzle, maintaining clarity.
Other exercises in this chapter
Problem 4
Let \(j(x)=10\left(x^{-2}+2 x^{2}\right)^{3}\). Give two possible decompositions of \(j(x)\) such that \(j(x)=f(g(h(x)))\). None of the functions \(f, g\), and
View solution Problem 7
Applying what you learned in the last section of this chapter to the pocketful of functions you ve been introduced to (the identity, squaring, reciprocal, and a
View solution Problem 8
Let \(f(x)=x(x+1), g(x)=x^{3}+2 x^{2}+x\). (a) Simplify the following. i. \(f(x)+g(x)\) ii. \(\frac{f(x)}{g(x)}\) iii. \(\frac{g(x)}{f(x)}\) iv. \(\frac{[f(x)]^
View solution Problem 8
Decompose the functions by finding functions \(f(x)\) and \(g(x)\), \(f(x) \neq x\) and \(g(x) \neq x\), such that \(h(x)=f(g(x))\). $$ h(x)=\sqrt{x^{2}+1} $$
View solution