Problem 69
Question
Let \(V(x, y, z)=V_{1} i+V_{2} j+V_{3} k\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the curl or roation of \(\vec{V}\), written \(\nabla \times \vec{V}\), curl \(\vec{V}\) or rot \(\vec{V}\), is defined by \(\begin{aligned} \nabla \times V &=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \times\left(V_{1} i+V_{2} j+V_{3} k\right) \\ &=\left|\begin{array}{lll}i & j & k \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ V_{1} & V_{2} & V_{3}\end{array}\right| \\\ &=\left(\frac{\partial V_{3}}{\partial y}-\frac{\partial V_{2}}{\partial z_{2}}\right) i+\left(\frac{\partial V_{2}}{\partial z}-\frac{\partial V_{3}}{\partial x}\right) j+\left(\frac{\partial V_{2}}{\partial x}-\frac{\partial V_{1}}{\partial y}\right) k \end{aligned}\) Note that in the expansion of the determinant the operators \(\frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z}\) must precede \(V_{1}, V_{2}, V_{3}\). For a vector function \(A\) possessing continuous second order partial derivatives, \(\nabla \cdot(\nabla \times A)=\) (A) \(A\) (B) \(\nabla \times A\) (C) 0 (D) none of these
Step-by-Step Solution
VerifiedKey Concepts
Curl of a Vector Field
Following the determinant, you'll find the resulting expression which involves the partial derivatives of \(V_1, V_2,\) and \(V_3\). The formula derived: \[\left(\frac{\partial V_3}{\partial y} - \frac{\partial V_2}{\partial z}\right) \mathbf{i} + \left(\frac{\partial V_1}{\partial z} - \frac{\partial V_3}{\partial x}\right) \mathbf{j} + \left(\frac{\partial V_2}{\partial x} - \frac{\partial V_1}{\partial y}\right) \mathbf{k}\] offers rich insight into how the components of the field are changing in relation to each other. In essence, the curl provides details about the vector field's rotational behavior.
Divergence
To find the divergence of the curl of a vector field \(abla \cdot (abla \times \vec{A})\), the identity in vector calculus states that it is zero. This underscores a significant property: a field's curl inherently has no divergence. This fact can greatly simplify analyses in fluid dynamics and electromagnetic theory where such concepts are frequently applied.
Mathematical Expression
Expressions in mathematics break down complex operations into manageable steps. For vector calculus, they allow the visualization of the vector field's structure, showing forms of motion and intensity over space. By using partial derivatives assembled into a determinant, the complex interaction of multi-dimensional systems become more approachable. These expressions are essential for anyone working in fields requiring spatial analysis, like physics or engineering, making it possible to predict and understand natural phenomena.
Partial Derivatives
Consider a vector field \( \vec{V}(x, y, z) = V_1 \mathbf{i} + V_2 \mathbf{j} + V_3 \mathbf{k} \). Calculating the curl requires computing partial derivatives like \(\frac{\partial V_3}{\partial y}\) or \(\frac{\partial V_2}{\partial z}\). This detailed breakdown offers insights into how the vector field's component functions change individually when x, y, or z are modified. By isolating the effects of single variables in a multivariable context, partial derivatives are key to unlocking the dynamics of complex systems, allowing solutions from climate models to fluid flow in engineering.