Problem 68
Question
In Exercises 65-68, find an equation of the tangent line to the parabola at the given point, and find the \(x\)-intercept of the line. \(y=-2x^2, (2, -8)\)
Step-by-Step Solution
Verified Answer
The equation of the tangent line to the parabola at the point (2, -8) is \(y = -8x + 8\) and the \(x\)-intercept of the line is 1.
1Step 1: Find the derivative of the function
The derivative of the given function \(y = -2x^2\) is \(-4x\) using power rule.
2Step 2: Find the slope of the tangent line
The slope of the tangent line on the function \(y = -2x^2\) at the point (2, -8) is calculated by substituting the \(x\) value of the point into the derivative, such that the slope, \(m = -4(2) = -8\).
3Step 3: Find the equation of the tangent line
The formula for a linear equation is \(y = mx + c\). Here, \(m = -8\) (from Step 2) and the point (2, -8) can be substituted in to solve for the intercept \(c\). From this, \(c = -8 - (-8*2) = 8\), thus the equation of the tangent line is \(y = -8x + 8\).
4Step 4: Find the x-intercept of the line
The \(x\)-intercept of the line is found by setting \(y = 0\) in the equation of the line, thus \(0 = -8x + 8 \Rightarrow x = 1\).
Key Concepts
Understanding DerivativesSlopes of Tangent LinesGraphs of ParabolasFinding the X-Intercept
Understanding Derivatives
When dealing with problems involving tangent lines to curves, the term "derivative" becomes crucial. The derivative of a function is a fundamental concept in calculus that represents the rate of change of the function's value with respect to its input. In simpler terms, the derivative tells you how a function is changing at any given point.
For example, if you have a function like \( y = -2x^2 \), the derivative using the power rule is calculated by multiplying the exponent by the coefficient in front of \( x \), and then subtracting one from the exponent. This results in the derivative \( -4x \).
For example, if you have a function like \( y = -2x^2 \), the derivative using the power rule is calculated by multiplying the exponent by the coefficient in front of \( x \), and then subtracting one from the exponent. This results in the derivative \( -4x \).
- The derivative shows how the function \( y = -2x^2 \) is changing as \( x \) changes.
- It helps in finding the slope of the tangent line at any given point on the curve.
Slopes of Tangent Lines
The slope of a tangent line at a specific point on a curve provides important information about how steep the line is and in which direction it goes.
To find the slope of the tangent line at a specific point, we evaluate the derivative at that point.
To find the slope of the tangent line at a specific point, we evaluate the derivative at that point.
- In our problem, the tangent line needs to be found at the point \((2, -8)\).
- The given derivative of the function \( y = -2x^2 \) is \(-4x\).
- Substituting \( x = 2 \) into \(-4x\) gives us the slope \( -8 \).
Graphs of Parabolas
Understanding the shape of a parabola helps in visualizing how tangent lines coincide with parabolas. A parabola is a U-shaped curve that can open upward or downward.
Tangent lines intersect the curve at exactly one point, the point of tangency, and understanding this helps in visualizing how the slope and the derivative come into play.
- The parabola described by \( y = -2x^2 \) opens downward because of the negative coefficient of \( x^2 \).
- The point \((2, -8)\) lies on the curve, and our task was to find the tangent at this point.
Tangent lines intersect the curve at exactly one point, the point of tangency, and understanding this helps in visualizing how the slope and the derivative come into play.
Finding the X-Intercept
Once the equation of a tangent line is found, we can determine its x-intercept. The x-intercept is where the line crosses the x-axis.
Identifying x-intercepts is useful for understanding where a function or its tangent intersects the axis and typically involves solving simple algebraic equations.
- For a line described by \( y = -8x + 8 \), the x-intercept is found by setting \( y = 0 \).
- Solving \( 0 = -8x + 8 \) yields \( x = 1 \).
Identifying x-intercepts is useful for understanding where a function or its tangent intersects the axis and typically involves solving simple algebraic equations.
Other exercises in this chapter
Problem 68
In Exercises 57-70, find any points of intersection of the graphs algebraically and then verify using a graphing utility. \(x^2+2y^2-4x+6y-5=0\) \(x^2-4x-y+4=0\
View solution Problem 68
In Exercises 57-72, classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. \(4y^2+4x^2-24x+35=0\)
View solution Problem 68
CONVEYOR DESIGN A moving conveyor is built so that it rises 1 meter for each 3 meters of horizontal travel. (a) Draw a diagram that gives a visual representatio
View solution Problem 69
TRUE OR FALSE? In Exercises 67-70, determine whether the statement is true or false. Justify your answer. The conic represented by the following equation is an
View solution