Problem 67
Question
One of the wavelengths of light emitted by hydrogen atoms under normal laboratory conditions is \(\lambda=656.3 \mathrm{nm},\) in the red portion of the electromagnetic spectrum. In the light emitted from a distant galaxy this same spectral line is observed to be Doppler-shifted to \(\lambda=953.4 \mathrm{nm}\) , in the infrared portion of the spectrum. How fast are the emitting atoms moving relative to the earth? Are they approaching the earth or receding from it?
Step-by-Step Solution
Verified Answer
The atoms are moving away from Earth at about 1.071 × 10⁸ m/s.
1Step 1: Identify the Problem
We are given the wavelengths of light \( \lambda_0 = 656.3 \, \text{nm} \) (emitted wavelength) and \( \lambda = 953.4 \, \text{nm} \) (observed wavelength). We need to find the velocity of the source using the Doppler effect formula for light.
2Step 2: Write Doppler Effect Formula for Light
The relativistic Doppler shift formula is given by:\[ \frac{\lambda}{\lambda_0} = \sqrt{\frac{1 + v/c}{1 - v/c}} \]where \( \lambda \) is the observed wavelength, \( \lambda_0 \) is the original wavelength, \( v \) is the velocity of the source relative to the observer, and \( c \) is the speed of light \( c \approx 3 \times 10^8 \, \text{m/s} \).
3Step 3: Rearrange the Formula to Solve for Velocity
First, we express the equation:\[ \lambda = \lambda_0 \sqrt{\frac{1 + v/c}{1 - v/c}} \]Then, rearrange to solve for \( v \):\[ \left(\frac{\lambda}{\lambda_0}\right)^2 = \frac{1 + v/c}{1 - v/c} \]\[ \frac{\lambda^2}{\lambda_0^2}(1 - v/c) = 1 + v/c \]
4Step 4: Solve for \( v \)
Continuing from the rearranged equation, we multiply both sides by the denominator:\[ \frac{\lambda^2}{\lambda_0^2} - \frac{\lambda^2}{\lambda_0^2} \cdot \frac{v}{c} = 1 + \frac{v}{c} \]Rearranging gives:\[ \frac{\lambda^2}{\lambda_0^2} - 1 = \left( \frac{1 + \frac{v}{c}}{1 - \frac{v}{c}} \right) \]Let's isolate \( v/c \). Define \( x = \frac{\lambda}{\lambda_0} \), then:\[ x^2 - 1 = \frac{v}{c} \left( x^2 + 1 \right) \]Solving for \( v/c \):\[ \frac{v}{c} = \frac{x^2 - 1}{x^2 + 1} \]Substitute \( x = \frac{953.4}{656.3} \approx 1.453 \):\[ \frac{v}{c} = \frac{1.453^2 - 1}{1.453^2 + 1} \approx \frac{2.111209 - 1}{2.111209 + 1} \approx \frac{1.111209}{3.111209} \approx 0.357 \]
5Step 5: Calculate the Velocity
Now, calculate the velocity \( v = 0.357 \times 3 \times 10^8 \, \text{m/s} \approx 1.071 \times 10^8 \, \text{m/s} \). The positive sign of \( v \) indicates that the galaxy is moving away from the Earth.
6Step 6: Conclusion
The emitting atoms are moving at approximately \( 1.071 \times 10^8 \, \text{m/s} \) away from the Earth, as observed from the redshift in the spectral line.
Key Concepts
Wavelength ShiftRelativistic PhysicsSpectral LinesRedshift
Wavelength Shift
The concept of a wavelength shift is a critical component of understanding the Doppler effect, especially in astrophysics and cosmology. It refers to the change in wavelength of light or other electromagnetic waves as observed from a moving source relative to an observer.
- If the source is moving towards the observer, the wavelengths get shorter – this is known as a blueshift.
- Conversely, if the source is moving away, the wavelengths become longer, resulting in what is known as a redshift.
Relativistic Physics
Relativistic physics, particularly as described by Einstein's theory of relativity, is essential when examining bodies moving at speeds close to the speed of light. In the case of the relativistic Doppler effect, the classical Doppler effect is modified to account for the high velocity of astronomical objects.
- The formula involves the speed of light, \(c\), as a constant, and incorporates the velocity \(v\) of the moving source.
- The equation used in the solution, \( \frac{\lambda}{\lambda_0} = \sqrt{\frac{1 + v/c}{1 - v/c}} \), shows how wavelengths are altered at such high speeds.
Spectral Lines
Spectral lines are unique to different elements and occur when atoms emit or absorb specific wavelengths of light. These lines are used in astrophysics to identify elements present in stars and galaxies. Each element has a 'fingerprint' of spectral lines under specific conditions.
- For example, hydrogen emits a distinct line at \(656.3 \text{nm}\) known as the H-alpha line observed under laboratory conditions.
- When viewed through the prism of a telescope, these lines can shift due to motion, thus providing information on the velocity and direction of the source.
Redshift
Redshift is a term commonly associated with the expansion of the universe and the movement of objects within it. When a spectral line moves from a shorter wavelength to a longer wavelength, it undergoes a redshift.
- This implies the source of the light is moving away from the observer, a fundamental observation supporting the theory of an expanding universe.
- The degree of redshift can provide insights into how fast an object, like a galaxy, is receding.
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