Problem 65
Question
Two events observed in a frame of reference Shave positions and times given by \(\left(x_{1}, t_{1}\right)\) and \(\left(x_{2}, t_{2}\right),\) respectively. (a) Frame \(S^{\prime}\) moves along the \(x\) -axis just fast enough that the two events occur at the same position in \(S^{\prime} .\) Show that in \(S^{\prime},\) the time interval \(\Delta t^{\prime}\) between the two events is given by $$\Delta t^{\prime}=\sqrt{(\Delta t)^{2}-\left(\frac{\Delta x}{c}\right)^{2}}$$ where \(\Delta x=x_{2}-x_{1}\) and \(\Delta t=t_{2}-t_{1}\) . Hence show that if \(\Delta x>c \Delta t,\) there is \(n o\) frame \(S^{\prime}\) in which the two events occur at the same point. The interval \(\Delta t^{\prime}\) is sometimes called the proper time interval for the events. Is this term appropriate? (b) Show that if \(\Delta x>c \Delta t,\) there is a different frame of reference \(S\) in which the two events occur simultaneously. Find the distance between the two events in \(S^{\prime} ;\) express your answer in terms of \(\Delta x, \Delta t,\) and \(c\). This distance is sometimes called a proper length. Is this term appropriate? (c) Two events are observed in a frame of reference \(S^{\prime}\) to occur simultancously at points separated by a distance of 2.50 \(\mathrm{m}\) . In a second frame \(S\) moving relative to \(S^{\prime}\) along the line joining the two points in \(S^{\prime},\) the two events appear to be separated by 5.00 \(\mathrm{m}\) . What is the time interval between the events as measured in \(S ?[\text { Hint: Apply the result obtained in part (b).1 }\)
Step-by-Step Solution
VerifiedKey Concepts
Special Relativity
Special Relativity redefines conventional concepts of time and space.
- It introduces time dilation, where a moving clock appears to tick slower relative to a stationary observer.
- It describes length contraction, meaning an object's length appears shorter in the direction of motion when observed from a moving reference frame.
Ultimately, Special Relativity shows us that our understanding of time and space is relative to our frame of reference and relative velocity.
Proper Time
In the context of Special Relativity, Proper Time is often derivable using the formula:\[ \\Delta t' = \sqrt{(\Delta t)^2 - \left(\frac{\Delta x}{c}\right)^2} \\]where \( \Delta t \) is the time interval between two events in one frame, and \( \Delta x \) is the spatial separation between these events in the same frame.
- If \( \Delta x > c \Delta t \), the Proper Time becomes imaginary — indicating that no such frame exists where the events can occur at the same location simultaneously.
- Proper Time is used to objectively compare time intervals from different frames of reference.
Frame of Reference
In Special Relativity, understanding different Frames of Reference is crucial because:
- They define spatial positions and times differently, thereby affecting the perception of events.
- The relative velocity between frames affects time dilation and length contraction.
Switching between different Frames of Reference, especially at relativistic speeds, can demonstrate how relative motion influences our perceptions of time and space. It reminds us how our understanding of "movement" and "rest" are relative, grounded in the speed and perspective from which we observe events.
Simultaneous Events
Events that are simultaneous in one frame may not be in another due to the finite speed of light:
- The notion of simultaneity is altered because observers moving at different velocities may disagree on whether events are synchronous.
- This leads to the realization that time can be experienced differently depending on the observer’s motion relative to the events occurring.
Understanding simultaneous events challenges our classical intuitions and highlights the novelty and counterintuitive nature of Special Relativity.