Problem 67
Question
Let \(f\) be a differentiable function satisfying \(f(x+y)\) \(f(x)+f(y)+x y .\) If \(\lim _{h \rightarrow 0} \frac{1}{h} f(h)=3\), then (A) \(f(x)=3 x\) (B) \(f(x)=3 x+x^{2}\) (C) \(f(x)=3 x+\frac{x^{2}}{2}\) (D) None of these
Step-by-Step Solution
Verified Answer
(C) \(f(x) = 3x + \frac{x^2}{2}\).
1Step 1: Substitute Known Expression in Functional Equation
Given the functional equation \( f(x+y) = f(x) + f(y) + xy \). Substitute \( y = 0 \):\[ f(x+0) = f(x) + f(0) + x \cdot 0 \Rightarrow f(x) = f(x) + f(0) \].Thus, \( f(0) = 0 \).
2Step 2: Evaluate Derivative Using Limit
The condition \( \lim_{h \to 0} \frac{1}{h} f(h) = 3 \) suggests we find \( f'(0) \). We use the derivative definition:\[ f'(0) = \lim_{h \to 0} \frac{f(h) - f(0)}{h} = \lim_{h \to 0} \frac{f(h)}{h} = 3 \].
3Step 3: Differentiate the Functional Equation
Differentiate the given functional equation with respect to \( y \):\[ \frac{d}{dy} (f(x+y)) = \frac{d}{dy} (f(x) + f(y) + xy) \]This gives \( f'(x+y) = f'(y) + x \).
4Step 4: Simplify Using Known Values
Setting \( y = 0 \), we get \( f'(x+0) = f'(0) + x \). Therefore,\[ f'(x) = 3 + x \].
5Step 5: Integrate to Find Original Function
Integrate \( f'(x) = 3 + x \) with respect to \( x \):\[ f(x) = \int (3 + x) \, dx = 3x + \frac{x^2}{2} + C \].
6Step 6: Determine Constant Using Initial Condition
Since \( f(0) = 0 \), substitute into \( f(x) = 3x + \frac{x^2}{2} + C \):\[ f(0) = 3 \cdot 0 + \frac{0^2}{2} + C = 0 \Rightarrow C = 0 \].
7Step 7: Conclusion and Answer
The function \( f(x) = 3x + \frac{x^2}{2} \) satisfies all conditions. Comparing with the options given, the correct answer is option (C).
Key Concepts
Functional EquationLimit of a FunctionDerivativeIntegration
Functional Equation
A functional equation is very much like an algebraic equation, but instead of involving numbers, it involves functions. It describes the relation between functions or between the values of the functions for given values of variables. A clever use of functional equations can reveal properties of unknown functions.
In this exercise, we're given a functional equation: \[f(x+y) = f(x) + f(y) + xy\]This tells us how the function behaves when two arguments are added. To explore this, substitute simple values, such as setting one of the variables to zero. By substituting \(y = 0\), we found that \(f(0) = 0\). This is a typical approach for getting insights into the function's behavior.
In this exercise, we're given a functional equation: \[f(x+y) = f(x) + f(y) + xy\]This tells us how the function behaves when two arguments are added. To explore this, substitute simple values, such as setting one of the variables to zero. By substituting \(y = 0\), we found that \(f(0) = 0\). This is a typical approach for getting insights into the function's behavior.
Limit of a Function
Limits are a fundamental concept in calculus and analysis, describing the behavior of functions as they approach a certain point. The limit \[\lim_{h \rightarrow 0} \frac{1}{h} f(h) = 3\]gives important information about the function's derivative at zero.Understanding limits helps in establishing continuity and differentiability of functions. Here, the limit implies that as \(h\) approaches zero, the ratio approaches 3, which indicates the slope of the tangent line at zero or the value of the derivative at that point.
Derivative
The derivative of a function measures how the function's output changes as its input changes. In calculus, it's the mathematical representation of the rate of change or slope of the function.From our functional equation, differentiating with respect to \(y\), and utilizing the limit, we deduced\[f'(0) = 3\]and then more generally,\[f'(x) = 3 + x\]This tells us about the rate of change for the function across its entire domain. Derivatives are essential for understanding the turning points and concave structure of graphs.
Integration
Integration is often seen as the reverse process of differentiation. While derivatives give us information about the rate of change, integration helps us to find the original function given its derivative.In this problem, to find the function \(f(x)\), we integrated its derivative:\[\int (3 + x) \, dx = 3x + \frac{x^2}{2} + C\]Through integration, we reconstructed the original formula of the function by determining the constant \(C\) using initial conditions. This process encapsulates the power of integration, capturing the cumulative effect of a variable's change over an interval.
Other exercises in this chapter
Problem 65
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