Problem 66
Question
Simplify the expression \(\left(\frac{2}{9}\right)^{-3}\) F. \(-\frac{6}{27}\) G. \(\frac{27}{6}\) H. \(-\frac{8}{729}\) J. \(\frac{729}{8}\)
Step-by-Step Solution
Verified Answer
J. \(\frac{729}{8}\)
1Step 1: Understand the negative exponent property
Recall the negative exponent rule: \(a^{-n} = \frac{1}{a^{n}}\). Using the rule, turn the negative exponent into a positive exponent by finding the reciprocal of the base.
2Step 2: Apply negative exponent property
Applying the negative exponent rule to \(\left(\frac{2}{9}\right)^{-3}\) gives \(\left(\frac{9}{2}\right)^{3}\)
3Step 3: Simplification.
Compute \(\left(\frac{9}{2}\right)^{3}\) which simplifies to cube of 9 (729) divided by cube of 2 (8). Hence, the simplified expression is \(\frac{729}{8}\)
Key Concepts
ReciprocalExponentiationSimplification
Reciprocal
In mathematics, understanding the concept of a reciprocal is essential, especially when working with exponents. A reciprocal is simply the inverse of a number or fraction. For any non-zero number or fraction \(a\), its reciprocal is \(\frac{1}{a}\). This is the same for fractions, where you flip the numerator and the denominator to find its reciprocal.
The process of finding the reciprocal is especially useful when dealing with negative exponents. When you encounter a negative exponent, the first step is to take the reciprocal of the base of the expression. For example, in the expression \(\left(\frac{2}{9}\right)^{-3}\), the reciprocal of \(\frac{2}{9}\) is \(\frac{9}{2}\). By flipping the fraction, you change the sign of the exponent to positive, preparing the expression for further operations.
The process of finding the reciprocal is especially useful when dealing with negative exponents. When you encounter a negative exponent, the first step is to take the reciprocal of the base of the expression. For example, in the expression \(\left(\frac{2}{9}\right)^{-3}\), the reciprocal of \(\frac{2}{9}\) is \(\frac{9}{2}\). By flipping the fraction, you change the sign of the exponent to positive, preparing the expression for further operations.
Exponentiation
Exponentiation is a fundamental mathematical operation involving a base and an exponent. When a base is raised to an exponent, it is multiplied by itself a number of times equal to the exponent. For example, when calculating \(\left(\frac{9}{2}\right)^3\), we multiply \(\frac{9}{2}\) by itself three times: \(\left(\frac{9}{2}\right) \times \left(\frac{9}{2}\right) \times \left(\frac{9}{2}\right)\).
This operation is often used for handling expressions with exponents, both positive and negative. After converting a negative exponent to a positive one using the reciprocal, you can compute the new expression using standard exponentiation rules.
This operation is often used for handling expressions with exponents, both positive and negative. After converting a negative exponent to a positive one using the reciprocal, you can compute the new expression using standard exponentiation rules.
- Positive exponents indicate repeated multiplication.
- Negative exponents indicate the need for reciprocation.
Simplification
Simplification is the process of reducing expressions to their simplest form. In this exercise, after converting the negative exponent into a positive one, the next step is to simplify \(\left(\frac{9}{2}\right)^3\). This means computing both the numerator and the denominator separately.
To simplify:
To simplify:
- Cube the numerator: \(9^3 = 729\).
- Cube the denominator: \(2^3 = 8\).
Other exercises in this chapter
Problem 65
Write the equation in standard form with integer coefficients. $$y=-\frac{3}{16} x+\frac{9}{16}$$
View solution Problem 65
Someone offers to double the amount of money you have every day for 1 month (30 days). You have 1 penny. At the end of the first day, you will have \(2 \cdot 1=
View solution Problem 66
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (0,-3), m=5 $$
View solution Problem 66
Write the number in scientific notation. Science Link , Light travels at a spced of about \(3 \times 10^{5}\) kilometers per esecond. It takes about \(1.5 \time
View solution