Problem 66
Question
Simplify each numerical expression. $$-\frac{2}{3}\left(\frac{1}{4}\right)+\left(-\frac{1}{3}\right)\left(\frac{5}{4}\right)$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(-\frac{7}{12}\).
1Step 1: Multiply the First Pair of Fractions
Start by simplifying the expression \(-\frac{2}{3} \times \frac{1}{4}\). Multiply the numerators and the denominators: Numerator: \(-2 \times 1 = -2\)Denominator: \(3 \times 4 = 12\). Thus, the result is \(-\frac{2}{12}\), which simplifies to \(-\frac{1}{6}\) by dividing the numerator and the denominator by 2.
2Step 2: Multiply the Second Pair of Fractions
Next, simplify the expression \(-\frac{1}{3} \times \frac{5}{4}\).Multiply the numerators and the denominators: Numerator: \(-1 \times 5 = -5\)Denominator: \(3 \times 4 = 12\). Thus, the result is \(-\frac{5}{12}\).
3Step 3: Add the Results of the Products
Combine the results from Steps 1 and 2 by adding them together:\(-\frac{1}{6} + -\frac{5}{12}\).To add these fractions, find a common denominator. The least common denominator of 6 and 12 is 12.Convert \(-\frac{1}{6}\) to \(-\frac{2}{12}\), so:\(-\frac{2}{12} + -\frac{5}{12} = -\frac{7}{12}\).
4Step 4: Simplify the Final Result
The expression \(-\frac{7}{12}\) is already in its simplest form since 7 is a prime number and cannot divide 12 without a remainder.
Key Concepts
Numerical ExpressionsLeast Common DenominatorMultiplying FractionsAdding Fractions
Numerical Expressions
Numerical expressions use numbers and operations to represent a specific quantity or value. In our exercise, the given expression is \(-\frac{2}{3}\left(\frac{1}{4}\right)+\left(-\frac{1}{3}\right)\left(\frac{5}{4}\right)\). This expression involves fractions and multiple operations like multiplication and addition. To simplify numerical expressions, the order of operations must be followed. This order is usually represented by PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)). For our problem, we start with simplifying the fractions through multiplication before moving to addition. Understanding numerical expressions is key as they are foundational for algebra and many other areas of mathematics.
Least Common Denominator
When adding or subtracting fractions, it is essential to have a common denominator for the fractions involved. The Least Common Denominator (LCD) is the smallest number that can be a common denominator for a given set of fractions. Finding the LCD allows us to add or subtract fractions more easily.For example, in the expression \(-\frac{1}{6} + -\frac{5}{12}\), we first identify that the denominators are 6 and 12.
- The multiples of 6 are 6, 12, 18, etc.
- The multiples of 12 are 12, 24, 36, etc.
Multiplying Fractions
Multiplying fractions involves multiplying the numerators together for the new numerator and the denominators together for the new denominator. It is straightforward compared to other fraction operations.In our problem, we first address \(-\frac{2}{3} \times \frac{1}{4}\):
- Multiply the numerators: \(-2 \times 1 = -2\)
- Multiply the denominators: \(3 \times 4 = 12\)
- This results in \(-\frac{2}{12}\)
Adding Fractions
Adding fractions requires a common denominator. Once all fractions are expressed with this common denominator, the numerators can simply be added together. For the expression \(-\frac{1}{6} + -\frac{5}{12}\), we previously found the LCD, which is 12. Convert \(-\frac{1}{6}\) into \(-\frac{2}{12}\) so both fractions have the denominator of 12. Now add the numerators:
- \(-2 + -5 = -7\)
- The result is \(-\frac{7}{12}\)
Other exercises in this chapter
Problem 66
Translate each English phrase into an algebraic expression and use \(n\) to represent the unknown number. A number decreased by 7
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Explain how the associative and commutative properties can help simplify \([(25)(97)](-4)\).
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Simplify each of the numerical expressions. $$12+5[3(7-4)]$$
View solution Problem 67
Translate each English phrase into an algebraic expression and use \(n\) to represent the unknown number. Five less than a number
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