Problem 66
Question
Exer. 63-68: Approximate, to the nearest 10', the solutions of the equation in the interval \(\left[0^{\circ}, 360^{\circ}\right)\). $$ 2 \tan ^{2} x-3 \tan x-1=0 $$
Step-by-Step Solution
Verified Answer
The solutions, approximated to the nearest 10 degrees, are: \(60^{\circ}, 240^{\circ}, 170^{\circ}, 350^{\circ}\).
1Step 1: Identify the Type of Equation
The given equation is a quadratic equation in terms of \( \tan x \). It is of the form \( ax^2 + bx + c = 0 \), where \( a = 2 \), \( b = -3 \), and \( c = -1 \).
2Step 2: Determine the Roots Using the Quadratic Formula
Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) to solve for \( \tan x \). Substituting the values, we get the roots:\[t \tan x = \frac{3 \pm \sqrt{(-3)^2 - 4 \cdot 2 \cdot (-1)}}{2 \cdot 2}\]Simplifying inside the square root:\[\tan x = \frac{3 \pm \sqrt{9 + 8}}{4} = \frac{3 \pm \sqrt{17}}{4}\]So the quadratic formula gives us two potential expressions for \( \tan x \):\[ \tan x = \frac{3 + \sqrt{17}}{4} \] and \[ \tan x = \frac{3 - \sqrt{17}}{4} \].
3Step 3: Calculate Numeric Values for Roots
Calculate the decimal values for \( \tan x \):First root: \( \tan x_1 = \frac{3 + \sqrt{17}}{4} \approx 1.78 \).Second root: \( \tan x_2 = \frac{3 - \sqrt{17}}{4} \approx -0.28 \).
4Step 4: Find All Possible Angles for Each Root
Convert the decimal \( \tan x \) values to angle measures in degrees:For \( \tan x_1 \approx 1.78 \): Angles \( x \approx 60^{\circ} \) (first quadrant) and \( x \approx 240^{\circ} \) (third quadrant), considering the periodicity of tangent (\(180^{\circ}\)).For \( \tan x_2 \approx -0.28 \): Angles \( x \approx 350^{\circ} \) (fourth quadrant) and \( x \approx 170^{\circ} \) (second quadrant).
5Step 5: Approximate Solutions to Nearest 10 Degrees
Round each angle to the nearest 10 degrees. For \( \tan x_1 \), the angles \(60^{\circ}\) and \(240^{\circ}\).For \( \tan x_2 \), the angles \(350^{\circ}\) and \(170^{\circ}\).This gives the solutions: \(60^{\circ}, 240^{\circ}, 170^{\circ}, 350^{\circ}\).
Key Concepts
Quadratic FormulaPeriodic FunctionsTangent FunctionAngle Approximation
Quadratic Formula
Understanding the quadratic formula is crucial for solving equations of the form \( ax^2 + bx + c = 0 \). In our given equation, \( 2 \tan^2 x - 3 \tan x - 1 = 0 \), we identify \( a = 2 \), \( b = -3 \), and \( c = -1 \). The quadratic formula itself is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
To apply this formula, you substitute the coefficients \( a \), \( b \), and \( c \) into it. This gives two potential solutions for \( x \), as there's a "plus-minus" in the formula.
To apply this formula, you substitute the coefficients \( a \), \( b \), and \( c \) into it. This gives two potential solutions for \( x \), as there's a "plus-minus" in the formula.
- The expression under the square root, \( b^2 - 4ac \), is called the discriminant. It tells us about the nature of the roots.
- If the discriminant is positive, like in our problem where it was \( \sqrt{17} \), there will be two distinct real roots.
Periodic Functions
Trigonometric functions, like the tangent function, are known as periodic functions. This means they repeat their values in regular intervals. The tangent function, \( \tan(x) \), specifically, has a period of \( 180^\circ \) or \( \pi \) radians.
This periodic nature is key when solving equations as it helps in identifying all possible angles that satisfy the equation within a given interval. For the interval \([0^\circ, 360^\circ)\), the solutions you find will repeat every \( 180^\circ \).
This periodic nature is key when solving equations as it helps in identifying all possible angles that satisfy the equation within a given interval. For the interval \([0^\circ, 360^\circ)\), the solutions you find will repeat every \( 180^\circ \).
- For a root with \( \tan(x) = 1.78 \), if one solution is \( 60^\circ \), another valid solution is \( 60^\circ + 180^\circ = 240^\circ \).
- Similar logic applies to other roots and solutions, such as \( -0.28 \), yielding \( 350^\circ \) and \( 170^\circ \).
Tangent Function
The tangent function, \( \tan(x) \), is one of the basic trigonometric functions. It's defined as the ratio of the sine of an angle to the cosine of the same angle: \( \tan(x) = \frac{\sin(x)}{\cos(x)} \).
It's particularly useful in this exercise because we have a quadratic in terms of \( \tan(x) \). Due to its periodicity and symmetry:
It's particularly useful in this exercise because we have a quadratic in terms of \( \tan(x) \). Due to its periodicity and symmetry:
- The tangent function has an infinite range but is undefined where \( \cos(x) = 0 \).
- This occurs at \( x = 90^\circ + 180^\circ n \), where \( n \) is an integer.
Angle Approximation
Approximating angles is essential when our results are not whole numbers. In our equation, we derived values \( \tan x \approx 1.78 \) and \( \tan x \approx -0.28 \). To find the angles, we utilize inverse tangent functions: \( \arctan \), which gives us specific angles in degrees.
- For a \( \tan(x) \) value of \( 1.78 \), \( \arctan(1.78) \approx 60.41^\circ \).
- For \( -0.28 \), \( \arctan(-0.28) \approx -15.64^\circ \), adjusted to the appropriate quadrant as \( 350^\circ \).
Other exercises in this chapter
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