Problem 64
Question
In each case, find a polynomial function whose graph behaves in the required manner. Answers may vary. The graph has only two \(x\) -intercepts at \((5,0)\) and \((-6,0)\) It does not cross the \(x\) -axis at either \(x\) -intercept.
Step-by-Step Solution
Verified Answer
f(x) = (x - 5)^2(x + 6)^2
1Step 1 - Understand the problem
The graph of the polynomial must touch the x-axis at the points \(5, 0\) and \(-6, 0\), but not cross it. This implies that these points are double roots of the polynomial.
2Step 2 - Define the roots
Since the polynomial touches but does not cross the x-axis at \(5, 0\) and \(-6, 0\), the roots must be of even multiplicity. Let’s assume they are of multiplicity 2.
3Step 3 - Form the polynomial
Given roots \(5, 0\) and \(-6, 0\) with multiplicity 2, the polynomial can be written as: \( f(x) = a(x - 5)^2(x + 6)^2 \) where \(a\) is a non-zero constant.
4Step 4 - Choose a value for a
Typically \(a = 1 \) is chosen for simplicity unless specified otherwise. Therefore, \( f(x) = (x - 5)^2(x + 6)^2 \).
Key Concepts
Double RootsX-InterceptsMultiplicity
Double Roots
In polynomial functions, double roots are quite interesting. They occur when the graph of the polynomial touches the x-axis at a particular point but doesn't cross it.
This happens because the root is repeated, meaning the factor corresponding to that root is squared.
For example, consider the polynomial from the exercise:
\[ f(x) = (x - 5)^2(x + 6)^2 \]
Here, 5 and -6 are double roots because each one is squared in the polynomial.
When the graph hits these points, it simply touches the x-axis and bounces back instead of crossing it.
This happens because the root is repeated, meaning the factor corresponding to that root is squared.
For example, consider the polynomial from the exercise:
\[ f(x) = (x - 5)^2(x + 6)^2 \]
Here, 5 and -6 are double roots because each one is squared in the polynomial.
When the graph hits these points, it simply touches the x-axis and bounces back instead of crossing it.
X-Intercepts
The x-intercepts of a polynomial are the points where the graph intersects the x-axis.
These points can be found by setting the polynomial equal to zero and solving for x.
In our specific exercise, the x-intercepts are given as (5, 0) and (-6, 0).
This means the polynomial is zero when x is 5 or -6.
\[ f(x) = (x - 5)^2(x + 6)^2 \]
At these points, the graph touches the x-axis but doesn't cross, indicating double roots with an even multiplicity.
These points can be found by setting the polynomial equal to zero and solving for x.
In our specific exercise, the x-intercepts are given as (5, 0) and (-6, 0).
This means the polynomial is zero when x is 5 or -6.
\[ f(x) = (x - 5)^2(x + 6)^2 \]
At these points, the graph touches the x-axis but doesn't cross, indicating double roots with an even multiplicity.
Multiplicity
Multiplicity refers to the number of times a particular root is repeated in a polynomial.
A root with multiplicity 2 means that the factor is squared in the polynomial.
For example, in our exercise, both x = 5 and x = -6 have a multiplicity of 2.
\[ f(x) = (x - 5)^2(x + 6)^2 \]
Higher multiplicities also affect how the graph behaves around that root:
A root with multiplicity 2 means that the factor is squared in the polynomial.
For example, in our exercise, both x = 5 and x = -6 have a multiplicity of 2.
\[ f(x) = (x - 5)^2(x + 6)^2 \]
Higher multiplicities also affect how the graph behaves around that root:
- A root with an odd multiplicity means the graph crosses the x-axis at that point.
- A root with an even multiplicity means the graph just touches the x-axis but doesn't cross it.
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