Problem 64
Question
For the following problems, solve each literal equation for the designated letter. \(P=2(1+w)\) for \(w\).
Step-by-Step Solution
Verified Answer
Question: Solve the equation \(P = 2(1 + w)\) for the variable \(w\).
Answer: \(w = \frac{P - 2}{2}\)
1Step 1: Expand the equation
First, we will expand the equation by multiplying the outer term with the terms inside the parentheses: \((2*1)+(2*w)\).
2Step 2: Simplify the equation
Now that the equation has been expanded, we simplify it by adding the numbers and keeping the term with \(w\):
\(P=2+2w\)
3Step 3: Isolate the variable \(w\)
In order to isolate the variable \(w\), we need to move the constant term on the other side of the equation. Subtract \(2\) from both sides:
\(P-2 = 2w\)
4Step 4: Solve for \(w\)
Finally, to find the value of \(w\), we need to get rid of the coefficient in front of the variable \(w\). Divide both sides of the equation by \(2\):
\(w=\frac{P-2}{2}\)
So, the literal equation solved for the designated letter, \(w\), is:
\(w=\frac{P-2}{2}\).
Key Concepts
Solving EquationsAlgebraic ManipulationVariable Isolation
Solving Equations
Solving equations is all about finding the value of an unknown variable that makes the equation true. In literal equations, unlike numerical ones, we deal with multiple variables. This can initially feel a bit tricky. However, the process isn't all that different from solving more straightforward numerical equations.
The key steps involve following a logical sequence of operations:
The key steps involve following a logical sequence of operations:
- Identify: Determine which variable to solve for, based on the given problem.
- Transform: Apply operations such as addition, subtraction, multiplication, and division to simplify the equation.
- Solve: Continue manipulating the equation until the target variable is isolated on one side, with its solution clear on the other.
Algebraic Manipulation
Algebraic manipulation is the backbone of solving equations. It involves rearranging and simplifying expressions to reveal unknown values. Involves the use of basic mathematical operations in a strategic manner.
- Distributive Property: In our example, we started by expanding \(P = 2(1 + w)\). Using the distributive property, we multiplied \(2\) by both \(1\) and \(w\) to simplify the equation to \(P = 2 + 2w\).
- Simplification: This step included combining like terms, simplifying any arithmetic, and making the equation easier to work with.
- Reverse Operations: These operations are crucial to manipulate the equation in the reverse direction of its current operation to isolate the variable.
Variable Isolation
Variable isolation is the process of arranging an equation so that the desired variable stands alone on one side of the equation. In the exercise provided, the ultimate goal was to express \(w\) in terms of other variables and constants.
- Subtracting: We moved the terms not involving the target variable to the opposite side. Specifically, \(2\) was subtracted from \(P\), which adjusted our equation to \(P - 2 = 2w\).
- Dividing: The final step involved dividing both sides by \(2\) to solve for \(w\). This operation canceled out the coefficient of \(w\), leaving it isolated as \(w = \frac{P - 2}{2}\).
Other exercises in this chapter
Problem 64
For the following problems, perform the indicated operations. $$ \frac{y^{2}-1}{y^{2}+9 y+20} \div \frac{y^{2}+5 y-6}{y^{2}-16} $$
View solution Problem 64
For the following problems, perform the divisions. $$ \frac{4 x^{3}+4 x^{2}-3 x-2}{2 x-1} $$
View solution Problem 64
For the following problems, replace \(N\) with the proper quantity. $$ \frac{-8 a}{a+3}=\frac{-8 a^{2}-40 a}{N} $$
View solution Problem 64
For the following problems, perform the multiplications and divisions. $$ \frac{4 a^{3} b-4 a^{2} b^{2}}{15 a-10} \cdot \frac{3 a-2}{4 a b-2 b^{2}} $$
View solution