Problem 63
Question
Simplify each fraction. You will need to use factoring by grouping. $$\frac{x y-3 x+2 y-6}{x y+5 x+2 y+10}$$
Step-by-Step Solution
Verified Answer
The simplified fraction is \(\frac{y-3}{y+5}\).
1Step 1: Identify Groups in Numerator
Look at the numerator, which is \(xy - 3x + 2y - 6\). Group the terms to make two groups: \((xy - 3x)\) and \((2y - 6)\).
2Step 2: Factor Each Group in Numerator
Factor out the common factor in each group found in Step 1. For \(xy - 3x\), the common factor is \(x\), so it becomes \(x(y - 3)\). For \(2y - 6\), the common factor is \(2\), so it becomes \(2(y - 3)\).
3Step 3: Factor by Grouping in Numerator
You now have \(x(y - 3) + 2(y - 3)\). Notice \(y - 3\) is common, so factor it out: \((y - 3)(x + 2)\).
4Step 4: Identify Groups in Denominator
Look at the denominator, which is \(xy + 5x + 2y + 10\). Group the terms to make two groups: \((xy + 5x)\) and \((2y + 10)\).
5Step 5: Factor Each Group in Denominator
Factor out the common factor in each group found in Step 4. For \(xy + 5x\), the common factor is \(x\), so it becomes \(x(y + 5)\). For \(2y + 10\), the common factor is \(2\), so it becomes \(2(y + 5)\).
6Step 6: Factor by Grouping in Denominator
You now have \(x(y + 5) + 2(y + 5)\). Notice \(y + 5\) is common, so factor it out: \((y + 5)(x + 2)\).
7Step 7: Simplify the Fraction
The expression is now \(\frac{(y-3)(x+2)}{(y+5)(x+2)}\). You can cancel the common factor \((x+2)\) from both numerator and denominator. The simplified fraction is \(\frac{y-3}{y+5}\).
Key Concepts
Simplifying FractionsPolynomial FactoringAlgebraic Expressions
Simplifying Fractions
Simplifying fractions involves reducing them to their simplest form. When simplifying, our goal is to ensure the numerator and the denominator have no common factors other than 1.
To simplify fractions, you can often factor both the numerator and the denominator and eliminate the common factors. This means finding terms that appear in both parts and canceling them out.
For example, if you have a fraction like \(\frac{(y-3)(x+2)}{(y+5)(x+2)}\), you can cancel out the \((x+2)\) term since it appears in both the numerator and the denominator. This makes the fraction simpler, resulting in \(\frac{y-3}{y+5}\).
By doing this, you make calculations simpler and often more insightful. Learning to simplify fractions is a valuable skill for solving algebraic equations more easily.
To simplify fractions, you can often factor both the numerator and the denominator and eliminate the common factors. This means finding terms that appear in both parts and canceling them out.
For example, if you have a fraction like \(\frac{(y-3)(x+2)}{(y+5)(x+2)}\), you can cancel out the \((x+2)\) term since it appears in both the numerator and the denominator. This makes the fraction simpler, resulting in \(\frac{y-3}{y+5}\).
By doing this, you make calculations simpler and often more insightful. Learning to simplify fractions is a valuable skill for solving algebraic equations more easily.
Polynomial Factoring
Factoring polynomials can seem tricky at first, but it becomes easier with practice. This process involves breaking down a polynomial into a product of simpler polynomials.
Polynomials can often be factored by recognizing patterns or grouping terms. In the exercise, factoring by grouping was used. This means:
Factoring is an essential skill in algebra as it simplifies expressions, making them easier to manage and solve.
Polynomials can often be factored by recognizing patterns or grouping terms. In the exercise, factoring by grouping was used. This means:
- Identify terms that can be grouped.
- Factor out the greatest common factor from each group.
- Recognize and pull out common terms.
Factoring is an essential skill in algebra as it simplifies expressions, making them easier to manage and solve.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations such as addition and subtraction. Understanding how to manipulate these expressions is key to mastering various algebraic techniques.
When dealing with algebraic expressions, one often needs to perform operations like factoring, expanding, or simplifying to make calculations easier.
For example, in our exercise, expressions like \(xy - 3x + 2y - 6\) were manipulated to find a simpler form. This involved identifying parts of the expression that could be grouped and factored, demonstrating how versatile and flexible algebraic expressions can be.
Algebraic expressions form the building blocks of more complex algebra problems, and mastering them helps you in various fields such as physics, engineering, and computer science, where they're frequently used to solve real-world problems.
When dealing with algebraic expressions, one often needs to perform operations like factoring, expanding, or simplifying to make calculations easier.
For example, in our exercise, expressions like \(xy - 3x + 2y - 6\) were manipulated to find a simpler form. This involved identifying parts of the expression that could be grouped and factored, demonstrating how versatile and flexible algebraic expressions can be.
Algebraic expressions form the building blocks of more complex algebra problems, and mastering them helps you in various fields such as physics, engineering, and computer science, where they're frequently used to solve real-world problems.
Other exercises in this chapter
Problem 62
If Kent can mow the entire lawn in \(m\) minutes, what fractional part of the lawn has he mowed at the end of 20 minutes?
View solution Problem 63
Add or subtract as indicated and express your answers in simplest form. (Objective 3) $$\frac{5}{12 x}-\frac{11}{16 x^{2}}$$
View solution Problem 63
If Sandy drove \(k\) kilometers at a rate of \(r\) kilometers per hour, how long did it take her to make the trip?
View solution Problem 64
Add or subtract as indicated and express your answers in simplest form. (Objective 3) $$\frac{4}{9 x}-\frac{7}{6 x^{2}}$$
View solution