Problem 63
Question
A line \(\mathrm{AB}\) in 3 -dimensional space makes angles \(45^{\circ}\) and \(120^{\circ}\) with the positive \(x\)-axis and the positive \(y\)-axis respectively. If \(A B\) makes an acute angle \(\theta\) with the positive \(z\)-axis, then \(\theta\) equals \([\mathbf{2 0 1 0}]\) (A) \(45^{\circ}\) (B) \(60^{\circ}\) (C) \(75^{\circ}\) (D) \(30^{\circ}\)
Step-by-Step Solution
Verified Answer
\(\theta = 60^{\circ}\)
1Step 1: Understand Angles with Axes
Given angles with x and y-axes are 45° and 120° respectively. We need to find the acute angle \( \theta \) with the z-axis.
2Step 2: Use Direction Cosines Formula
The direction cosines are represented as \( l, m, n \) with \( \cos(\alpha), \cos(\beta) \) and \( \cos(\theta) \) being the respective cosines of the angles with x, y, and z-axes. Respectively \( \alpha = 45^{\circ} \) and \( \beta = 120^{\circ} \) so we have: \[ l = \cos(45^{\circ}) = \frac{1}{\sqrt{2}}, \ m = \cos(120^{\circ}) = -\frac{1}{2}. \]
3Step 3: Apply the Direction Cosines Identity
Use the identity for direction cosines: \( l^2 + m^2 + n^2 = 1 \). Plug in the known values: \[ \left(\frac{1}{\sqrt{2}}\right)^2 + \left(-\frac{1}{2}\right)^2 + n^2 = 1. \]
4Step 4: Solve for \(n^2\)
Calculate and solve for \(n^2\): \[ \frac{1}{2} + \frac{1}{4} + n^2 = 1. \] Simplify: \[ \frac{3}{4} + n^2 = 1 \Rightarrow n^2 = \frac{1}{4}. \]
5Step 5: Determine \(n\) and \(\theta\)
Since angle \( \theta \) is acute, \( n = \cos(\theta) = \frac{1}{2} \). The angle corresponding to \( \cos(\theta) = \frac{1}{2} \) is \( \theta = 60^{\circ} \).
Key Concepts
3-dimensional spaceangles with axesmathematical problem-solving
3-dimensional space
Three-dimensional space is an area where everything we see in the world around us takes place. Unlike the flat, two-dimensional surfaces, 3D space involves volume because it includes the height, width, and depth of objects.
In our problem, the line \(\overline{AB}\) exists in 3-dimensional space, making angles with the coordinate axes. Each point in this space can be located by a set of numbers \(x, y, z\), representing its position along these three axes.
Using 3-dimensional space principles enables calculations such as finding angles that lines make with these axes, as illustrated in the task where we determine the angle a line makes with the z-axis.
In our problem, the line \(\overline{AB}\) exists in 3-dimensional space, making angles with the coordinate axes. Each point in this space can be located by a set of numbers \(x, y, z\), representing its position along these three axes.
- The x-axis runs horizontally.
- The y-axis runs vertically.
- The z-axis represents depth, which is what gives space its three-dimensionality.
Using 3-dimensional space principles enables calculations such as finding angles that lines make with these axes, as illustrated in the task where we determine the angle a line makes with the z-axis.
angles with axes
Angles with axes are angles that a line or vector forms with the coordinate axes in a 3-dimensional space.
These angles are important in understanding the direction of lines and vectors within this space. In our example, the line \(\overline{AB}\) makes specific angles with the x-axis and y-axis:
These angles are important in understanding the direction of lines and vectors within this space. In our example, the line \(\overline{AB}\) makes specific angles with the x-axis and y-axis:
- It makes a \(45\degree\) angle with the x-axis.
- It makes a \(120\degree\) angle with the y-axis.
- The direction cosine with the x-axis is \(l = \cos(45\degree) = \frac{1}{\sqrt{2}}\).
- With the y-axis, it is \(m = \cos(120\degree) = -\frac{1}{2}\).
mathematical problem-solving
Mathematical problem-solving is a systematic approach used to tackle complex questions, especially when dealing with topics like vectors and angles in 3D space.
One effective method is breaking down the problem into smaller, more manageable steps, as illustrated in this exercise. Here, the problem involves finding an unknown angle \(\theta\):
By approaching problems logically and methodically, the complexity reduces, making it far easier to reach the correct solution.
One effective method is breaking down the problem into smaller, more manageable steps, as illustrated in this exercise. Here, the problem involves finding an unknown angle \(\theta\):
- Initially, we identify the given angles with the x and y-axes.
- Next, we calculate the direction cosines for these known angles.
- We then apply the direction cosines identity: \(l^2 + m^2 + n^2 = 1\).
- By substituting our known values, \(n^2\) is isolated and solved.
- Finally, we determine \(n\) and find \(\theta\) using the inverse cosine function.
By approaching problems logically and methodically, the complexity reduces, making it far easier to reach the correct solution.
Other exercises in this chapter
Problem 61
If the straight lines \(\frac{x-1}{k}=\frac{y-2}{2}=\frac{z-3}{3}\) and \(\frac{x-2}{3}=\frac{y-3}{k}=\frac{z-1}{2}\) intersect at a point, then the integer \(k
View solution Problem 62
Let the line \(\frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2}\) lies in the plane \(x+\) \(3 y-\alpha z+\beta=0 .\) Then \((\alpha, \beta)\) equals [2009] (A) \((6,
View solution Problem 64
If the angle between the line \(x=\frac{y-1}{2}=\frac{z-3}{\lambda}\) and the plane \(x+2 y+3 z=\) is \(\cos ^{-1}\left(\sqrt{\frac{5}{14}}\right)\), then \(\la
View solution Problem 66
An equation of a plane parallel to the plane \(x-2 y+2 z\) \(=5\) and at a unit distance from the origin is \([\mathbf{2 0 1 2}]\) (A) \(x-2 y+2 z-3=0\) (B) \(x
View solution