Problem 62
Question
For exercises 61-64, the completed problem has one mistake. (a) Describe the mistake in words or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: The relationship of the number of weeks a box of garbage bags is used, \(x\), and the number of bags left in the box, \(y\), is an inverse variation. When \(x\) is 8 weeks, \(y\) is 168 bags. Find the constant of proportionality, \(k\). Incorrect Answer: \(k=\frac{y}{x}\) $$ k=\frac{168 \text { bags }}{8 \text { weeks }} $$
Step-by-Step Solution
Verified Answer
The mistake is using the direct variation formula. Correct answer: $$k = 1344$$
1Step 1 - Identify the Mistake
In an inverse variation, the relationship between two variables is given by the equation $$ xy = k $$ where $$ k $$ is the constant of proportionality. The mistake in the solution is the use of the formula $$ k = \frac{y}{x} $$ which applies to direct variation, not inverse variation.
2Step 2 - Use the Correct Formula
For inverse variation, we use the formula $$ xy = k $$ which means that the product of the variables $$ x $$ and $$ y $$ is equal to the constant $$ k $$.
3Step 3 - Substitute the Given Values
The problem states that $$ x = 8 \text { weeks } $$ and $$ y = 168 \text { bags } $$. Substitute these values into the formula to find $$ k $$: $$ k = xy = 8 \text { weeks } \times 168 \text { bags } $$
4Step 4 - Calculate the Constant of Proportionality
Perform the multiplication to find $$ k $$: $$ k = 8 \times 168 = 1344 \text { (weeks * bags) } $$
Key Concepts
inverse variationconstant of proportionalityalgebraic equationserror identification
inverse variation
Inverse variation describes a relationship between two variables where their product is constant. This means as one variable increases, the other decreases proportionally. The mathematical formula is given by:
where $$ xy = k $$ Here, k is the constant of proportionality. When working with inverse variation, remember:
where $$ xy = k $$ Here, k is the constant of proportionality. When working with inverse variation, remember:
- The product of the variables stays constant.
- As one variable increases, the other decreases.
- The formula differs from direct variation.
Direct variation uses the formula < right> $$ y = kx $$
constant of proportionality
The constant of proportionality, denoted as $$ k $$, is a crucial value in both direct and inverse proportional relationships. In the context of inverse variation, it signifies that the product of the variables does not change. For instance, if you have an inverse variation problem and you know the values of the two variables, you can find $$ k $$ by multiplying these values together.
Here’s how we cracked this in our problem:
Understanding $$ k $$ helps you to quickly find relationships between variables and solve inverse variation problems with confidence.
Here’s how we cracked this in our problem:
- The given values were $$ x = 8 \text { weeks } $$ and $$ y = 168 \text { bags } $$.
- We used the correct formula for inverse variation: $$ xy = k $$
- Substituted the values: $$ k = 8 \times 168 $$
- Calculated to find $$ k = 1344 \text { (weeks * bags) } $$
Understanding $$ k $$ helps you to quickly find relationships between variables and solve inverse variation problems with confidence.
algebraic equations
Algebraic equations are mathematical statements that use numbers and variables. They set two expressions equal to each other. Inversely varying relationships involve algebraic equations like $$ xy = k $$. Here’s a recap of key points:
Example from our problem:
To find the constant of proportionality, we knew that:
- Identify the type of relation (inverse or direct).
- For inverse variation, multiply the variables to equal the constant.
- Isolate the unknown variable if needed to solve for it.
Example from our problem:
To find the constant of proportionality, we knew that:
- $$ k = xy $$
- The given values were $$ x = 8 $$ and $$ y = 168 $$.
- By plugging in these values, we found $$ k = 1344 $$ through straightforward multiplication.
error identification
Identifying errors in mathematical solutions is crucial to mastering algebra. Inverse variation problems often involve a specific common mistake: confusing inverse and direct variation formulas. In our given problem, the error was using
$$ \frac{y}{x} $$ instead of the inverse variation formula $$ xy = k $$.
To avoid this, follow these tips:
Consistently practice error identification to enhance your problem-solving skills!
$$ \frac{y}{x} $$ instead of the inverse variation formula $$ xy = k $$.
To avoid this, follow these tips:
- Clearly understand the type of variation described (inverse or direct).
- Use the correct formula from the start. For inverse: $$ xy = k $$.For direct: $$ y = kx $$
- Double-check your formula before computing.
- Review the problem context if your result seems off.
- We recognized the given formula $$ k = \frac{y}{x} $$ was wrong for inverse variation.
- Used the correct formula: $$ xy = k $$
- Calculated accurately to find $$ k = 8 \times 168 = 1344 $$
Consistently practice error identification to enhance your problem-solving skills!
Other exercises in this chapter
Problem 61
For exercises 59-66, use the five steps. Assume that the rate of work does not change if done individually or together. The water from a garden hose turned on a
View solution Problem 61
For exercises 1-66, simplify. $$ \frac{2 a^{3}-4 a^{2}-6 a}{4 a^{3}-16 a^{2}-20 a} $$
View solution Problem 62
For exercises \(25-68\), evaluate or simplify. $$ \frac{\frac{c}{3}+\frac{d}{2}}{\frac{c}{2}+\frac{d}{7}} $$
View solution Problem 62
For exercises 1-66, simplify. $$ \frac{2 c^{3}-2 c^{2}-4 c}{4 c^{3}-8 c^{2}-12 c} $$
View solution