Problem 62
Question
For exercises \(25-68\), evaluate or simplify. $$ \frac{\frac{c}{3}+\frac{d}{2}}{\frac{c}{2}+\frac{d}{7}} $$
Step-by-Step Solution
Verified Answer
\( \frac{7(2c + 3d)}{3(7c + 2d)} \)
1Step 1 - Identify the Numerator
The numerator of the given expression is \ \( \frac{c}{3} + \frac{d}{2} \).
2Step 2 - Identify the Denominator
The denominator of the given expression is \ \( \frac{c}{2} + \frac{d}{7} \).
3Step 3 - Find a Common Denominator for the Numerator
For the numerator \( \frac{c}{3} + \frac{d}{2} \), the least common multiple of 3 and 2 is 6. Rewrite the fractions with this common denominator: \ \( \frac{c}{3} = \frac{2c}{6} \) and \( \frac{d}{2} = \frac{3d}{6} \). Thus, the numerator becomes \ \( \frac{2c}{6} + \frac{3d}{6} = \frac{2c + 3d}{6} \).
4Step 4 - Find a Common Denominator for the Denominator
For the denominator \( \frac{c}{2} + \frac{d}{7} \), the least common multiple of 2 and 7 is 14. Rewrite the fractions with this common denominator: \ \( \frac{c}{2} = \frac{7c}{14} \) and \( \frac{d}{7} = \frac{2d}{14} \). Thus, the denominator becomes \ \( \frac{7c}{14} + \frac{2d}{14} = \frac{7c + 2d}{14} \).
5Step 5 - Divide the Numerator by the Denominator
Write the expression as: \ \( \frac{\frac{2c + 3d}{6}}{\frac{7c + 2d}{14}} \). To divide by a fraction, multiply by its reciprocal: \ \( \frac{2c + 3d}{6} \times \frac{14}{7c + 2d} \).
6Step 6 - Simplify the Expression
Multiply the numerators and the denominators: \ \( \frac{(2c + 3d) \times 14}{6 \times (7c + 2d)} = \frac{14(2c + 3d)}{6(7c + 2d)} \). Simplify the fractions if possible: \ \( \frac{14(2c + 3d)}{6(7c + 2d)} = \frac{7(2c + 3d)}{3(7c + 2d)} \).
Key Concepts
common denominatorsfraction divisionsimplifying fractionsleast common multiple
common denominators
In algebra, when you add or subtract fractions, they need to have the same denominator, called a common denominator. For instance, in the exercise, the fractions \( \frac{c}{3} + \frac{d}{2} \) must be combined under a common denominator. The least common multiple (LCM) of 3 and 2 is 6.
To rewrite the fractions with this common denominator, we convert them as follows:
Similarly, for the denominator \( \frac{c}{2} + \frac{d}{7} \), the LCM of 2 and 7 is 14. So, we rewrite the fractions as follows:
To rewrite the fractions with this common denominator, we convert them as follows:
- \( \frac{c}{3} = \frac{2c}{6} \)
- \( \frac{d}{2} = \frac{3d}{6} \)
Similarly, for the denominator \( \frac{c}{2} + \frac{d}{7} \), the LCM of 2 and 7 is 14. So, we rewrite the fractions as follows:
- \( \frac{c}{2} = \frac{7c}{14} \)
- \( \frac{d}{7} = \frac{2d}{14} \)
fraction division
Dividing fractions involves multiplying by the reciprocal. When we have \( \frac{\frac{2c + 3d}{6}}{\frac{7c + 2d}{14}} \), we switch from division to multiplication by flipping the denominator:
Firstly, rewrite the expression:
Firstly, rewrite the expression:
- \( \frac{\frac{2c + 3d}{6}}{\frac{7c + 2d}{14}} \)
- Reciprocal of \( \frac{7c + 2d}{14} \) is \( \frac{14}{7c + 2d} \)
- Thus, it becomes \( \frac{2c + 3d}{6} \times \frac{14}{7c + 2d} \)
simplifying fractions
Simplifying fractions means reducing them to their simplest form. For example, after we've written \( \frac{2c + 3d}{6} \times \frac{14}{7c + 2d} \), we need to simplify:
- Multiply the numerators: \( (2c + 3d) \times 14 \)
- Multiply the denominators: \( 6 \times (7c + 2d) \)
- So, we get \( \frac{14(2c + 3d)}{6(7c + 2d)} \)
- Divide the numerator: \( 14(2c + 3d) / 2 = 7(2c + 3d) \)
- Divide the denominator: \( 6(7c + 2d) / 2 = 3(7c + 2d) \)
least common multiple
The least common multiple (LCM) of two or more numbers is the smallest number that is a multiple of each of them.
In this exercise, we need the LCM to find common denominators:
In this exercise, we need the LCM to find common denominators:
- For 3 and 2, the multiples of 3 are 3, 6, 9, etc., and the multiples of 2 are 2, 4, 6, etc. The smallest common multiple is 6.
- For 2 and 7, the multiples of 2 are 2, 4, 6, 8, 10, 12, 14, etc., and the multiples of 7 are 7, 14, 21, etc. The smallest common multiple is 14.
Other exercises in this chapter
Problem 61
For exercises 1-66, simplify. $$ \frac{2 a^{3}-4 a^{2}-6 a}{4 a^{3}-16 a^{2}-20 a} $$
View solution Problem 62
For exercises 61-64, the completed problem has one mistake. (a) Describe the mistake in words or copy down the whole problem and highlight or circle the mistake
View solution Problem 62
For exercises 1-66, simplify. $$ \frac{2 c^{3}-2 c^{2}-4 c}{4 c^{3}-8 c^{2}-12 c} $$
View solution Problem 63
For exercises 39-82, simplify. $$ \frac{2 z+6}{z^{2}+3 z+2} \div \frac{z+3}{z+2} $$
View solution