Problem 62
Question
Find the value of each of the following expressions when \(x=3 .\) You may substitute 3 for \(x\) in each expression the way it is written, or you may simplify each expression first and then substitute 3 for \(x .\) $$6 x+8 x+7$$
Step-by-Step Solution
Verified Answer
The value of the expression is 49 when \(x = 3\).
1Step 1: Understand the Expression
We are given the algebraic expression \(6x + 8x + 7\). Our task is to substitute \(x=3\) into this expression and calculate the result.
2Step 2: Simplify the Expression
First, we combine like terms in the expression to simplify it. The terms \(6x\) and \(8x\) are like terms. So, we add them together: \[6x + 8x = (6 + 8)x = 14x\]Thus, the expression becomes \(14x + 7\).
3Step 3: Substitute the Value of x
Next, we substitute \(x = 3\) into the simplified expression \(14x + 7\): \[14(3) + 7\]
4Step 4: Perform the Multiplication
Calculate the multiplication in the expression:\[14 imes 3 = 42\]
5Step 5: Add the Result
Add the result from the multiplication to 7:\[42 + 7 = 49\]
6Step 6: Conclude the Calculation
The final calculated value of the expression \(14x + 7\) when \(x = 3\) is 49.
Key Concepts
Combining Like TermsSubstitutionSimplifying Expressions
Combining Like Terms
To simplify an algebraic expression, one primary approach is to combine like terms. Like terms are terms in an expression that have exactly the same variable(s) and exponent(s). For example, in the expression \(6x + 8x + 7\), the terms \(6x\) and \(8x\) are like terms. They both contain the variable \(x\) raised to the same power of 1.
Combining like terms means adding or subtracting their coefficients while retaining the common variable part. In our example, we combine \(6x\) and \(8x\) to get \((6 + 8)x = 14x\). This simplification makes the expression easier to work with later steps.
Combining like terms means adding or subtracting their coefficients while retaining the common variable part. In our example, we combine \(6x\) and \(8x\) to get \((6 + 8)x = 14x\). This simplification makes the expression easier to work with later steps.
- Identify like terms by looking for the same variable part.
- Add or subtract their coefficients.
- Simplify the expression by combining the terms.
Substitution
Substitution involves replacing a variable in an expression with a specific value to find the value of the expression. In our expression, once we have simplified to \(14x + 7\), we substitute \(x = 3\) to calculate the numeric value.
The substitution step is straightforward: simply replace \(x\) with \(3\) in each instance it appears in the expression. So, \(14x + 7\) becomes \(14(3) + 7\).
The substitution step is straightforward: simply replace \(x\) with \(3\) in each instance it appears in the expression. So, \(14x + 7\) becomes \(14(3) + 7\).
- Identify where the variable occurs in the expression.
- Replace each occurrence with the given number.
- Ensure all substitutions are consistent throughout the expression.
Simplifying Expressions
Simplifying expressions is about reducing them to their most manageable form before performing calculations. This involves combining like terms, performing arithmetic operations, and ensuring the expression is as straightforward as possible.
In our example, this means simplifying \(6x + 8x + 7\) to \(14x + 7\) by combining like terms. With substitution, we then have \(14(3) + 7\). Now, it's time to do the arithmetic:
In our example, this means simplifying \(6x + 8x + 7\) to \(14x + 7\) by combining like terms. With substitution, we then have \(14(3) + 7\). Now, it's time to do the arithmetic:
- First, multiply: \(14 \times 3 = 42\).
- Second, add the constant term: \(42 + 7 = 49\).
Other exercises in this chapter
Problem 62
Translate each sentence below into an equation, then solve the equation. The sum of 8 and \(3 x\) is 2
View solution Problem 62
Suppose \(4 x+3 y=12 .\) Find \(y\) if: $$x=-3$$
View solution Problem 62
Write the mathematical expressions that are equivalent to each of the following English phrases. Three times the sum of a number and 8
View solution Problem 63
Multiply. $$2 \cdot \frac{1}{2}$$
View solution