Problem 62
Question
Among all pairs of numbers whose sum is \(20,\) find a pair whose product is as large as possible. What is the maximum product?
Step-by-Step Solution
Verified Answer
The pair of numbers whose sum is 20 and whose product is maximum is (10,10), and the maximum product is 100.
1Step 1: Set up the formula for the sum of the two numbers
We can represent the two unknown numbers as \(x\) and \(y\). Since we know that they sum up to 20, we write the formula \(x + y = 20\).
2Step 2: Solve above equation for one variable
Let's solve for \(y\) in terms of \(x\). This means we have \(y = 20 - x\).
3Step 3: Express the product formula and substitute
The product of the two numbers is given by \(xy\). So, substituting \(y\) in terms of \(x\), we have \(x * (20 - x) = 20x - x^2\). We find that this formula represents a downward-facing parabola. The maximum value of this product will occur at the vertex of the parabola.
4Step 4: Find the maximum of the product function
The maximum value for a downward-facing parabola \(ax^2 + bx + c\) occurs at \(x = -\frac{b}{2a}\). In our case, \(a = -1\) and \(b=20\). Therefore, the maximum occurs at \(x = -\frac{20}{2*-1} = 10\).
5Step 5: Find maximum product
Substitute \(x = 10\) in the product \(20x - x^2\) to find \(20*10 - 10^2 = 200 - 100 = 100\) as the maximum product.
Other exercises in this chapter
Problem 61
State the Remainder Theorem.
View solution Problem 62
In Exercises \(61-64,\) find the domain of each function. $$ f(x)-\frac{1}{\sqrt{4 x^{2}-9 x+2}} $$
View solution Problem 62
Explain how the Remainder Theorem can be used to find \(f(-6)\) if \(f(x)=x^{4}+7 x^{3}+8 x^{2}+11 x+5 .\) What advantage is there to using the Remainder Theore
View solution Problem 63
In Exercises \(61-64,\) find the domain of each function. $$ f(x)-\sqrt{\frac{2 x}{x+1}-1} $$
View solution