Problem 60
Question
Write each series using summation notation. 2-4+8-16+32
Step-by-Step Solution
Verified Answer
The summation notation for the given series is \(\sum_{n=1}^{5} 2 × (-2)^{n-1}\).
1Step 1: Find the first term and the common ratio
The first term of the given series is 2. And since every term can be obtained by multiplying the previous term by -2, the common ratio is -2.
2Step 2: General term formula
Using the common ratio, we can create a formula for the general term. The general term of a geometric series is given by \(a_n = a_1 × r^{n-1}\), where a_n is the nth term, a_1 is the first term, r is the common ratio, and n is the number of terms.
In this case, \(a_1 = 2\), and \(r = -2\).
So, the general term formula is:
\(a_n = 2 × (-2)^{n-1}\)
3Step 3: Determine the range
As we only have information about the first 5 terms of the series, the range of our summation will be from n=1 to n=5.
4Step 4: Write the summation notation
Using the general term formula and the determined range, we can write the given series using summation notation:
\(\sum_{n=1}^{5} 2 × (-2)^{n-1}\)
Key Concepts
Geometric SeriesGeneral Term FormulaCommon Ratio
Geometric Series
A geometric series is a sequence of terms where each term after the first is found by multiplying the previous term by a constant, called the common ratio. This type of series can be identified by their pattern of consistent multiplication.
For example, in the series 2, -4, 8, -16, 32, each term is obtained by multiplying the previous term by -2. You start with the first term, 2, and continuously multiply it by the common ratio, -2, to find the subsequent terms. It's like a snowball effect, where each term builds off the last.
For example, in the series 2, -4, 8, -16, 32, each term is obtained by multiplying the previous term by -2. You start with the first term, 2, and continuously multiply it by the common ratio, -2, to find the subsequent terms. It's like a snowball effect, where each term builds off the last.
- First term: 2
- Second term: 2 × (-2) = -4
- Third term: -4 × (-2) = 8
- Fourth term: 8 × (-2) = -16
- Fifth term: -16 × (-2) = 32
General Term Formula
The general term formula is a powerful tool in expressing any term in a geometric series. It helps you calculate any term position in the series without having to list all previous terms. The formula for any term in a geometric series is given as:
\(a_n = a_1 \times r^{n-1}\)
Here:
For this series with \(a_1 = 2\) and \(r = -2\):
\(a_n = 2 \times (-2)^{n-1}\)
This formula enables you to calculate the nth term directly, which is particularly valuable with long series.
\(a_n = a_1 \times r^{n-1}\)
Here:
- \(a_n\) is the nth term you're trying to find.
- \(a_1\) is the first term of the series.
- \(r\) stands for the common ratio, which is the factor you multiply by each time.
- \(n\) is the position of the term in the series.
For this series with \(a_1 = 2\) and \(r = -2\):
\(a_n = 2 \times (-2)^{n-1}\)
This formula enables you to calculate the nth term directly, which is particularly valuable with long series.
Common Ratio
The common ratio is a key component of a geometric series and is what links each term to the previous one. It is a constant value that each term is multiplied by to obtain the next term. Understanding the common ratio is crucial for identifying and working with geometric series.
To find the common ratio \(r\), take any term in the series and divide it by the previous term. In the series 2, -4, 8, -16, 32, you can calculate \(r\) as follows:
To find the common ratio \(r\), take any term in the series and divide it by the previous term. In the series 2, -4, 8, -16, 32, you can calculate \(r\) as follows:
- Common ratio between -4 and 2: \(-4 \div 2 = -2\)
- Common ratio between 8 and -4: \(8 \div (-4) = -2\)
- Common ratio in subsequent terms: also -2
Other exercises in this chapter
Problem 60
Find the indicated term of each binomial expansion. $$\left(2 y^{2}+z\right)^{10} ; \text { eighth term }$$
View solution Problem 60
Use the formula for \(S_{n}\) to find the sum of the terms of each geometric sequence. $$\sum_{i=1}^{8} 5(2)^{i}$$
View solution Problem 60
Find \(S_{8}\) for each arithmetic sequence described below. $$a_{n}=-6 n+5$$
View solution Problem 61
Find the indicated term of each binomial expansion. $$\left(c^{3}-3 d^{2}\right)^{7} ; \text { third term }$$
View solution