Problem 60
Question
Find the indicated term of each binomial expansion. $$\left(2 y^{2}+z\right)^{10} ; \text { eighth term }$$
Step-by-Step Solution
Verified Answer
The eighth term in the expansion of the given binomial expression, \((2y^2+z)^{10}\), is \(T_8 = 960y^{6}z^{7}\).
1Step 1: Identify the components of the binomial expression
In this problem, we have the given binomial expression \((2y^2+z)^{10}\) and we need to find the eighth term in its expansion. The components of the binomial expression are:
- a = \(2y^2\)
- b = z
- n = 10, which is the exponent.
2Step 2: Understand the general term of a binomial expansion
The general term of a binomial expansion according to the binomial theorem is given by:
\(T_r = C(n, k) * a^{n-k}*b^k\),
where:
- \(T_r\) is the r-th term in the expansion,
- \(C(n, k)\) is the binomial coefficient (also denoted as \(\binom{n}{k}\) or nCk),
- n is the exponent in the binomial expression,
- a and b are the items of the binomial expression, and
- k ranges from 0 to n.
Since we need to find the eighth term, \(T_8\), we will use \(k = 7\) (as the first term corresponds to \(k = 0\)).
3Step 3: Calculate the binomial coefficient
To find the binomial coefficient for the eighth term, we need to calculate:
\(C(10, 7) = \binom{10}{7} = \frac{10!}{7!(3)!}\),
where ! denotes the factorial of a number.
We can calculate this as:
\(C(10, 7)= \frac{10!}{7!3!} = \frac{10\times 9 \times 8}{3 \times 2 \times 1} = 10 \times 3 \times 4 = 120\).
4Step 4: Apply the formula for the general term
Now, we can apply the formula for the eighth term, \(T_8\), using \(k = 7\):
\(T_8 = C(10,7) * (2y^2)^{10-7} * z^7\)
Plug in the binomial coefficient we found in step 3:
\(T_8 = 120*(2y^2)^3*z^7\)
5Step 5: Simplify the term
Now, simplify the term:
\(T_8 = 120*(8y^6)*z^7\)
\(T_8 = 960y^{6}z^{7}\)
So, the eighth term in the expansion of the given binomial expression is:
\(T_8 = 960y^{6}z^{7}\)
Key Concepts
Understanding the Binomial TheoremExploring Binomial CoefficientsFactorial Calculation Explained
Understanding the Binomial Theorem
The binomial theorem is a powerful algebraic tool used to expand expressions that are raised to a power, such as \( (a + b)^n \). This theorem provides a formula for expanding these expressions without multiply-ing them repeatedly. Each of the terms in the expansion is determined by the formula: \(T_k = C(n, k) \cdot a^{n-k} \cdot b^k\), where \(T_k\) represents a specific term in the expansion. This equation helps identify the terms systematically, especially for large powers.
Core components of the binomial theorem include:
For instance, for \( (2y^2 + z)^{10} \), to find the eighth term, one must understand the role of the binomial theorem in systematically locating and calculating specific terms within the expanded polynomial.
Core components of the binomial theorem include:
- Each expansion involves terms formed by varying powers of the two variables, here labeled \(a\) and \(b\).
- The coefficients of these terms are determined by binomial coefficients, which we will explore further in the next section.
- The power of \(a\) starts high and decreases, while the power of \(b\) starts at 0 and increases as you move through the terms.
For instance, for \( (2y^2 + z)^{10} \), to find the eighth term, one must understand the role of the binomial theorem in systematically locating and calculating specific terms within the expanded polynomial.
Exploring Binomial Coefficients
Binomial coefficients play a crucial role in the binomial theorem. They dictate the weight or multiplicative factor of each term in the expansion. The binomial coefficient \(C(n, k)\), often expressed as \( \binom{n}{k} \), reveals the number of ways to pick \(k\) elements from a total of \(n\) elements without regard to the order.
The calculation of a binomial coefficient is rooted in combinations from combinatorics and is given by:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
Here, \(!\) denotes the factorial operation, which is illustrated in the next section.
Understanding these coefficients not only simplifies polynomial expansion processes but also provides a deeper insight into pattern recognition within mathematical series.
The calculation of a binomial coefficient is rooted in combinations from combinatorics and is given by:
\[ C(n, k) = \frac{n!}{k!(n-k)!} \]
Here, \(!\) denotes the factorial operation, which is illustrated in the next section.
- In the exercise, for the eighth term, we use \( C(10, 7) \), highlighting that \( k = 7 \) corresponds to the exponents of each term's components being chosen.
- This results in an expanded form that systematically grows the power of \(b\) from 0 at the first term, upwards, as the power of \(a\) decreases.
Understanding these coefficients not only simplifies polynomial expansion processes but also provides a deeper insight into pattern recognition within mathematical series.
Factorial Calculation Explained
Factorials are foundational in calculating many mathematical expressions, particularly binomial coefficients. The factorial of a non-negative integer \(n\), denoted as \(n!\), is the product of all positive integers less than or equal to \(n\). Factorials are a key element in combination calculations, as well.
For example:
In our binomial coefficient calculation, \( C(10,7) = \frac{10!}{7!3!} \) requires computing:
Understanding and calculating with factorials is crucial for accurately determining the terms in a binomial expansion, revealing the structure and symmetry of polynomial expansions.
For example:
- \(0!\) is defined to be \(1\).
- \(5!\) or "5 factorial" is \(5 \times 4 \times 3 \times 2 \times 1 = 120\).
In our binomial coefficient calculation, \( C(10,7) = \frac{10!}{7!3!} \) requires computing:
- \(10!\) which involves the multiplication of integers from \1\ to \10\.
- Furthermore, dividing as indicated by the formula simplifies the calculation into manageable steps.
Understanding and calculating with factorials is crucial for accurately determining the terms in a binomial expansion, revealing the structure and symmetry of polynomial expansions.
Other exercises in this chapter
Problem 59
Write each series using summation notation. -1+2-3+4-5+6-7
View solution Problem 59
Find \(S_{8}\) for each arithmetic sequence described below. $$a_{n}=3 n+4$$
View solution Problem 60
Use the formula for \(S_{n}\) to find the sum of the terms of each geometric sequence. $$\sum_{i=1}^{8} 5(2)^{i}$$
View solution Problem 60
Write each series using summation notation. 2-4+8-16+32
View solution