Problem 60
Question
Simplify. Assume that the variables represent any real number. $$ \sqrt{x^{2}-8 x+16} $$
Step-by-Step Solution
Verified Answer
Simplified form is \(|x-4|\).
1Step 1: Recognize the Expression Inside the Square Root
The expression inside the square root is \(x^2 - 8x + 16\). This is a quadratic expression.
2Step 2: Factor the Quadratic Expression
Check if the quadratic expression \(x^2 - 8x + 16\) can be factored into a perfect square. Notice that \(x^2 - 8x + 16 = (x-4)^2\). This is because \((x-4)(x-4) = x^2 - 4x - 4x + 16 = x^2 - 8x + 16\).
3Step 3: Simplify the Square Root
Since \(x^2 - 8x + 16 = (x-4)^2\), the square root is \(\sqrt{(x-4)^2}\). The square root of a square is the absolute value: \(|x-4|\).
4Step 4: Consider the Values of the Expression
For the simplification \(|x-4|\), consider the two cases: If \(x \geq 4\), then \(|x-4| = x-4\). If \(x < 4\), then \(|x-4| = 4-x\). However, since the question allows all real numbers, the form \(|x-4|\) is correct and fully simplified.
Key Concepts
Quadratic ExpressionsFactoring QuadraticsSquare RootsAbsolute Value
Quadratic Expressions
When dealing with expressions in algebra, quadratic expressions are of great importance. A quadratic expression is a polynomial of degree two, typically written in the form: \(ax^2 + bx + c\). Here, \(a\), \(b\), and \(c\) are constants, where \(a eq 0\). This kind of expression often represents a parabola when graphed on a coordinate plane.
In the original exercise, the expression inside the square root, \(x^2 - 8x + 16\), is a quadratic expression. It's important to recognize it as such, as this helps in simplifying and solving it effectively. Quadratic expressions can usually be factored or solved using various methods such as completing the square or using the quadratic formula.
In the original exercise, the expression inside the square root, \(x^2 - 8x + 16\), is a quadratic expression. It's important to recognize it as such, as this helps in simplifying and solving it effectively. Quadratic expressions can usually be factored or solved using various methods such as completing the square or using the quadratic formula.
Factoring Quadratics
Factoring is a key step when working with quadratic expressions, helping convert them into a product of simpler expressions. In our case, the quadratic \(x^2 - 8x + 16\) can be rewritten in a factored form. You can recognize it as a perfect square.
Without this step, you may miss patterns that help solve the problem more efficiently.
- Breaking it down: recognize that \(x^2 - 8x + 16\) equals \((x-4)^2\).
- Verification: Check by expanding \((x-4)(x-4)\) back to see \(x^2 - 8x + 16\). This confirms the factorization was accurate.
Without this step, you may miss patterns that help solve the problem more efficiently.
Square Roots
Square roots are used frequently in algebra to simplify expressions and solve equations. The square root of a number is a value that, when multiplied by itself, yields the original number. For this reason, understanding the square roots of expressions, especially perfect squares, is crucial.
In the original exercise, we looked at the square root of \((x-4)^2\). Since \((x-4)^2\) is a perfect square, taking the square root simplifies directly to \(|x-4|\).
When simplifying square roots of perfect squares, it's important not to forget about absolute value, because the expression under the square root could have originally included negative numbers, affecting the result.
In the original exercise, we looked at the square root of \((x-4)^2\). Since \((x-4)^2\) is a perfect square, taking the square root simplifies directly to \(|x-4|\).
When simplifying square roots of perfect squares, it's important not to forget about absolute value, because the expression under the square root could have originally included negative numbers, affecting the result.
Absolute Value
Absolute value measures the distance of a number from zero on a number line, without considering which direction from zero the number lies.
It is always a non-negative value.
In the context of the original exercise, after simplifying the square root of \((x-4)^2\), it results in \(|x-4|\). This happens because when you take the square root of a squared term, the absolute value of the base term is returned.
It is always a non-negative value.
In the context of the original exercise, after simplifying the square root of \((x-4)^2\), it results in \(|x-4|\). This happens because when you take the square root of a squared term, the absolute value of the base term is returned.
- For \(x \geq 4\), the expression \(|x-4|\) simplifies to \(x-4\).
- For \(x < 4\), it becomes \(4-x\).
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Problem 60
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