Problem 6
Question
Write an equation that expresses each relationship. Use \(k\) as the constant of variation. \(w\) varies inversely as \(l\)
Step-by-Step Solution
Verified Answer
The equation that expresses the relationship where \(w\) varies inversely as \(l\) is \(w = \frac{k}{l}\).
1Step 1: Understanding inverse variation
An inverse variation between two variables is represented mathematically as \(y = \frac{k}{x}\), where \(k\) is the constant of variation. In this exercise, \(w\) varies inversely as \(l\). Therefore, \(w\) and \(l\) are in the positions of \(y\) and \(x\) respectively.
2Step 2: Writing the equation
Following the inverse variation formula and replacing \(w\) and \(l\) for \(y\) and \(x\) respectively and \(k\) is the constant of variation, we obtain the equation: \(w = \frac{k}{l}\).
3Step 3: Final Expression
The final equation that expresses the given relationship where 'w' varies inversely as 'l' is \(w = \frac{k}{l}\). This equation tells us that as \(l\) increases, \(w\) decreases in proportion, and vice versa, with \(k\) being the constant of variation.
Key Concepts
Constant of VariationVariablesRelationship EquationAlgebraic Expressions
Constant of Variation
In the realm of inverse variation, the constant of variation, often symbolized as \(k\), plays an essential role. This constant captures the unique relationship between two variables, indicating how one changes in response to the other. Notably, \(k\) remains constant throughout the relation, despite fluctuations in the variables themselves.
If you think about the equation \(w = \frac{k}{l}\), where \(w\) and \(l\) are inversely related, \(k\) represents the product of \(w\) and \(l\).
If you think about the equation \(w = \frac{k}{l}\), where \(w\) and \(l\) are inversely related, \(k\) represents the product of \(w\) and \(l\).
- When \(w\) increases, \(l\) must decrease to keep the product equal to \(k\).
- Conversely, if \(l\) grows, \(w\) will shrink accordingly.
Variables
Variables are foundational in expressing mathematical relationships, acting as placeholders that can take on different values. In our inverse variation context, we have two specific variables: \(w\) and \(l\).
- \(w\): This is the dependent variable, meaning its value depends on the change in \(l\).
- \(l\): This is the independent variable that dictates the values of \(w\) based on its fluctuations.
Relationship Equation
The heart of inverse variation lies in its relationship equation, \(w = \frac{k}{l}\), which succinctly captures how two variables are interconnected. This equation tells us that \(w\) is inversely proportional to \(l\).
- If \(l\) were to double, \(w\) would be halved, illustrating the inverse relationship.
- Similarly, a reduction in \(l\) causes a corresponding increase in \(w\).
Algebraic Expressions
Algebraic expressions are the language of mathematics, used to represent how quantities relate to one another. Our current expression, \(w = \frac{k}{l}\), exemplifies how inverse variation can be captured using algebra.
- "Inverse" implies that as one variable increases, the other decreases, which is clearly seen in the equation's structure.
- The fraction format highlights the division aspect, central to understanding inverses.
Other exercises in this chapter
Problem 5
Consider the equation \(x^{4}+3 x^{3}+2 x^{2}-5 x+12=0\) a. List all possible rational roots. b. Determine whether 1 is a root using synthetic division. What tw
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Divide using long division. State the quotient, \(q(x),\) and the remainder, \(r(x)\). $$\left(6 x^{3}+7 x^{2}+12 x-5\right) \div(3 x-1)$$
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In Exercises \(1-8,\) find the domain of each rational function. $$h(x)=\frac{x+8}{x^{2}-64}$$
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Use the Rational Zero Theorem to list all possible rational zeros for each given function. $$ f(x)=3 x^{4}-11 x^{3}-3 x^{2}-6 x+8 $$
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