Problem 6
Question
The given function models the displacement of an object moving in simple harmonic motion. (a) Find the amplitude, period, and frequency of the motion. (b) Sketch a graph of the displacement of the object over one complete period. $$y=-\frac{3}{2} \sin (0.2 t+1.4)$$
Step-by-Step Solution
Verified Answer
Amplitude: \( \frac{3}{2} \), Period: \( 10\pi \), Frequency: \( \frac{1}{10\pi} \). Sketch shows one complete sine wave cycle.
1Step 1: Understanding the Amplitude
The amplitude of a function in the form \( y = A \sin( B t + C ) \) is the absolute value of \( A \). In the given function, \( y = -\frac{3}{2} \sin (0.2 t + 1.4) \), the coefficient \( A = -\frac{3}{2} \). To find the amplitude, we take the absolute value: \[ \text{Amplitude} = |-\frac{3}{2}| = \frac{3}{2} \].
2Step 2: Calculating the Period
The period of a sine function is given by \( \frac{2\pi}{B} \), where \( B \) is the coefficient of \( t \) in the argument of the sine function. Here, \( B = 0.2 \). The period is calculated as:\[\text{Period} = \frac{2\pi}{0.2} = \frac{2\pi}{\frac{1}{5}} = 10\pi\].
3Step 3: Determining the Frequency
The frequency is the reciprocal of the period. With the period being \( 10\pi \), the frequency is calculated as:\[\text{Frequency} = \frac{1}{10\pi}\].
4Step 4: Sketching the Graph
To sketch the graph over one complete period, plot the function \( y = -\frac{3}{2} \sin (0.2 t + 1.4) \) over the interval from \( t = 0 \) to \( t = 10\pi \). The graph should show a sine wave oscillating between \( \frac{3}{2} \) and \( -\frac{3}{2} \), starting at an angle of \( 1.4 \) radians due to the phase shift. Ensure the wave completes exactly one full cycle within this range.
Key Concepts
AmplitudePeriodFrequencySine Function
Amplitude
The amplitude in a simple harmonic motion refers to the maximum extent of the vibration or wave, measured from the position of equilibrium. It tells us how far the object moves from the central position. Think of amplitude as the height of a wave or vibration peak.
In mathematical terms, for a sine function of the form \( y = A \sin(Bt + C) \), the amplitude \( A \) is the coefficient directly in front of the sine function. In our example of \( y = -\frac{3}{2} \sin(0.2t + 1.4) \), the coefficient \( A = -\frac{3}{2} \).
In mathematical terms, for a sine function of the form \( y = A \sin(Bt + C) \), the amplitude \( A \) is the coefficient directly in front of the sine function. In our example of \( y = -\frac{3}{2} \sin(0.2t + 1.4) \), the coefficient \( A = -\frac{3}{2} \).
- The amplitude is found by taking the absolute value of \( A \): \( |A| = |-\frac{3}{2}| = \frac{3}{2} \).
- A higher amplitude means a taller wave, while a lower amplitude leads to a shorter wave.
Period
The period of a simple harmonic motion helps determine how long it takes to complete one full cycle of oscillation. It's often associated with the time interval for the wave to repeat itself. Understanding the period is crucial, as it allows you to anticipate the motion of the object at any given time.
For a sine function \( y = A \sin(Bt + C) \), the period is calculated using the formula:
For a sine function \( y = A \sin(Bt + C) \), the period is calculated using the formula:
- \( \text{Period} = \frac{2\pi}{B} \)
- Here, \( B = 0.2 \).
- So, the period becomes \( \frac{2\pi}{0.2} = 10\pi \).
Frequency
The frequency of a wave describes how often the wave occurs in a specific time frame. It is a measure of how many complete wavelengths or cycles pass a specific point per unit of time.
Frequency is the reciprocal of the period. Therefore, knowing the period allows us to easily find frequency using the relationship:
Frequency is the reciprocal of the period. Therefore, knowing the period allows us to easily find frequency using the relationship:
- \( \text{Frequency} = \frac{1}{\text{Period}} \)
- \( \text{Frequency} = \frac{1}{10\pi} \).
Sine Function
The sine function is a fundamental part of simple harmonic motion, modeling the oscillatory motion found in various physical systems like springs and pendulums. It represents a smooth, periodic oscillation that can accurately depict many types of wave-like motions.
The general form of the sine function is \( y = A \sin(Bt + C) \). In our example, \( y = -\frac{3}{2} \sin(0.2t + 1.4) \), several components work together:
The general form of the sine function is \( y = A \sin(Bt + C) \). In our example, \( y = -\frac{3}{2} \sin(0.2t + 1.4) \), several components work together:
- \( A \) determines the amplitude or the peak height of the oscillation.
- \( B \) affects the period, influencing how quickly the cycle repeats.
- \( C \) is the phase shift, altering where the wave begins its cycle on the time-axis.
Other exercises in this chapter
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Graph the function. $$ f(x)=-1+\cos x $$
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\(1-6=\) Show that the point is on the unit circle. $$ \left(\frac{\sqrt{11}}{6}, \frac{5}{6}\right) $$
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