Problem 6
Question
Solve each equation. Check each solution. See Examples 1 through \(6 .\) \(-y=8\)
Step-by-Step Solution
Verified Answer
The solution is \(y = -8\). It checks out when substituted back into the equation.
1Step 1: Understand the Equation
We are given the equation \(-y = 8\). The goal is to solve for \(y\). This equation suggests that the opposite of \(y\) equals 8.
2Step 2: Isolate the Variable
To solve for \(y\), we need to get \(y\) by itself. We do this by multiplying both sides of the equation by \(-1\). Thus, \(-1(-y) = -1(8)\).
3Step 3: Simplification
When simplifying, we have \(y = -8\) because \(-1 \times -y = y\) and \(-1 \times 8 = -8\).
4Step 4: Check the Solution
To ensure our solution is correct, substitute \(y = -8\) back into the original equation. The equation \(-y = 8\) becomes \(-(-8) = 8\), which simplifies to \(8 = 8\), confirming that our solution is correct.
Key Concepts
Understanding Algebraic ManipulationTechniques for Isolating VariablesWhy Checking Solutions is Important
Understanding Algebraic Manipulation
Solving linear equations often requires using algebraic manipulation, a powerful tool that helps us rearrange equations and find solutions. Think of it as a method to "clean up" equations by performing operations that maintain equality. These operations can include:
- Adding or subtracting the same number from both sides of the equation
- Multiplying or dividing each side by the same non-zero number
Techniques for Isolating Variables
Isolating the variable is a crucial step in solving \(y\) in the equation. Our mission is to get the variable by itself on one side of the equation. This allows us to clearly see the value of the variable. There's a simple strategy to remember:
- Do the opposite operation to cancel out unwanted terms.
Why Checking Solutions is Important
Once you've solved for a variable, it's essential to check your solution. This verifies the accuracy of your work and catches any possible mistakes. Why is it so important? Because it ensures:
- The solution satisfies the original equation
- You've applied correct algebraic processes
Other exercises in this chapter
Problem 6
The number 126 is \(35 \%\) of what number?
View solution Problem 6
Solve each equation. Check each solution. $$ -8=8+z $$
View solution Problem 6
Substitute the given values into each given formula and solve for the unknown variable. $$ A=\frac{1}{2} h(B+b) ; \quad A=60, B=7, b=3 $$
View solution Problem 7
The product of twice a number and three is the same as the difference of five times the number and \(\frac{3}{4}\). Find the number.
View solution