Problem 6
Question
Find the \(x\) -and \(y\) -intercepts of the rational function. \(s(x)=\frac{3 x}{x-5}\)
Step-by-Step Solution
Verified Answer
Both intercepts are at (0,0).
1Step 1: Find the x-intercept
To find the x-intercept of the function \(s(x) = \frac{3x}{x-5}\), set \(s(x)\) to zero and solve for \(x\). This means \(\frac{3x}{x-5} = 0\). Since a fraction is zero when its numerator is zero, set the numerator to zero: \(3x = 0\). Solving for \(x\) gives \(x = 0\). Therefore, the x-intercept is \((0,0)\).
2Step 2: Find the y-intercept
To find the y-intercept of \(s(x)\), substitute \(x = 0\) into the function. This yields \(s(0) = \frac{3(0)}{0-5} = 0\). Thus, the y-intercept is also \((0,0)\).
Key Concepts
x-interceptsy-interceptsnumerator and denominator of a fraction
x-intercepts
The x-intercepts of a rational function are the points where the graph of the function crosses the x-axis. These intercepts occur where the function's value is zero. For a rational function, which takes the form \( f(x) = \frac{p(x)}{q(x)} \), the x-intercepts are found by setting the numerator \( p(x) \) equal to zero and solving for \( x \).
In our problem, the function is \( s(x) = \frac{3x}{x-5} \). To find the x-intercepts, we set the numerator, \( 3x \), equal to zero:
- Solve for \( x \): - \( 3x = 0 \) - Dividing both sides by 3 gives \( x = 0 \).
So, the x-intercept of the function is at \( (0,0) \). Remember that only the numerator determines the x-intercepts because a fraction is zero only when its numerator is zero.
In our problem, the function is \( s(x) = \frac{3x}{x-5} \). To find the x-intercepts, we set the numerator, \( 3x \), equal to zero:
- Solve for \( x \): - \( 3x = 0 \) - Dividing both sides by 3 gives \( x = 0 \).
So, the x-intercept of the function is at \( (0,0) \). Remember that only the numerator determines the x-intercepts because a fraction is zero only when its numerator is zero.
y-intercepts
Y-intercepts are the points where the graph of a function crosses the y-axis. These occur when the input variable \( x \) is zero, and we are interested in the value of the function at this point. To find a y-intercept for any function \( f(x) \), substitute \( x = 0 \) into the equation and solve for \( f(x) \).
For the function \( s(x) = \frac{3x}{x-5} \), we substitute zero in for \( x \):
For the function \( s(x) = \frac{3x}{x-5} \), we substitute zero in for \( x \):
- Replace \( x \) with 0: \( s(0) = \frac{3(0)}{0-5} \)
- This simplifies to \( s(0) = \frac{0}{-5} = 0 \)
numerator and denominator of a fraction
Understanding the role of the numerator and denominator in a rational function is crucial for grasping how these functions behave. A rational function is expressed as a fraction, \( \frac{p(x)}{q(x)} \), where \( p(x) \) and \( q(x) \) are polynomials.
Here's the core idea:
- The numerator \( 3x \) becomes zero at \( x = 0 \), leading to the x-intercept at \( (0,0) \).
- The denominator \( x-5 \) is zero at \( x = 5 \), where the function is undefined, indicating a vertical asymptote.
When solving for intercepts, focus on the numerator to understand when the entire fraction equals zero. This principle simplifies finding intercepts in rational functions.
Here's the core idea:
- The numerator \( p(x) \) determines where the rational function is equal to zero, thus helping us find x-intercepts.
- The denominator \( q(x) \) determines where the function is undefined, which occurs where \( q(x) = 0 \), possibly creating vertical asymptotes, but these do not affect where the function crosses axes.
- The numerator \( 3x \) becomes zero at \( x = 0 \), leading to the x-intercept at \( (0,0) \).
- The denominator \( x-5 \) is zero at \( x = 5 \), where the function is undefined, indicating a vertical asymptote.
When solving for intercepts, focus on the numerator to understand when the entire fraction equals zero. This principle simplifies finding intercepts in rational functions.
Other exercises in this chapter
Problem 5
Two polynomials \(P\) and \(D\) are given. Use either synthetic or long division to divide \(P(x)\) by \(D(x),\) and express \(P\) in the form \(P(x)=D(x) \cdot
View solution Problem 6
\(1-12\) . A polynomial \(P\) is given. (a) Find all zeros of \(P\) , real and complex. (b) Factor \(P\) completely. $$ P(x)=x^{4}-x^{2}-2 $$
View solution Problem 6
List all possible rational zeros given by the Rational Zeros Theorem (but don’t check to see which actually are zeros). $$ U(x)=12 x^{5}+6 x^{3}-2 x-8 $$
View solution Problem 6
Two polynomials \(P\) and \(D\) are given. Use either synthetic or long division to divide \(P(x)\) by \(D(x),\) and express \(P\) in the form \(P(x)=D(x) \cdot
View solution